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The Fourier series trigonometric representation of a periodic function is
Find the exponential Fourier series representation of f(t).

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Chapter 17 Solutions
EBK FUNDAMENTALS OF ELECTRIC CIRCUITS
- Design a self-biased JFET circuit (Fig. 6) assuming VGS(0) = -1.3 and ipss= 20 mA. We require a VGS = -0.7. Assume a supply voltage of 15 volts. Draw the load line for this circuit using Fig. 4b once you have selected the appropriate values for the components. Does the load line intersect the VGS = -0.7 volt line at the computed in point? RD. RG Rs 12 20nA GS = -1.3 VGS 10nA Fig. 6. Circuit for Examples 2 &3. 50 100 150 200 □ ID(J1) UDS Fig. 4b. The IV characteristics of an n-channel JFET (J113). The plots are for VGs increments of 0.05 volts. VGS(0) -1.3. The yellow and blue load lines are for examples 2 &3, respectively.arrow_forwardFind the operating point and the load line of a voltage-divider JFET biasing circuit using the following parameters: VGS(0) = -1.3 and Vcc = 15 volts. Assume ipss = 20 mA, RG₁ = RG2 = 10 kn, RD = 300, and Rs = 1 kn. Use Fig. 4b for the IV characteristic of the JFET. 20nA GS=-1.3 GS 10nA- 50 100 150 200 ID(J1) UDS Fig. 4b. The IV characteristics of an n-channel JFET (J113). The plots are for VGs increments of 0.05 volts. VGS(0) -1.3. The yellow and blue load lines are for examples 2 &3, respectively.arrow_forwardDesign the JFET circuit for the largest in swing. Use the self-bias circuit shown in Fig. 6. Assume that VGS (0) = -1.3 and Vcc = 15 volts. Furthermore, assume that ipss = 20 mA. Using Fig. 4b, draw the load line and identify the Q point. Explain why this will allow the largest swing. Use ip = ipss (1- VGS VGS(0) to show what happens to i, and vps when you have a swing of 0.2 volts in vcs form its operating point (that is, change vas by ±0.2 volts and compute the corresponding iD and VDs). RD RG Rs 0 20nA GS=-1.3 VGS 12 10nA -0- Fig. 6. Circuit for Examples 2 &3. BA-C 50 100 150 200 □ ID(J1) UDS Fig. 4b. The IV characteristics of an n-channel JFET (J113). The plots are for VGs increments of 0.05 volts. VGS(0) -1.3. The yellow and blue load lines are for examples 2 &3, respectively.arrow_forward
- please do the correct VI chrastaristics curve on excel. I am not sure if mine is correctarrow_forwardplease do the correct VI chrastaristics curve on excel. I am not sure if mine is correct. Note the two curves in the picture are for both but its two tries and i dont know which is correct, and probebly both are wrong SCR (Forward Bias Condition) NO VAA VG= 0V, IG=0 mA VG= 5V, IG=4.07mA VG= 10V, IG=9.05mA VAK (V) IAK(mA) VAK (V) IAK(mA) VAK (V) IAK(mA) 1 0 0 0 0 0 0 0 2 5 0.576 4.42 mA 0.576 4.42 mA 0.576 4.43 3 10 7.99 2 0.598 9.4 0.598 9.4 4 15 14.99 0.003 0.612 14.4 0.612 14.4 5 20 19.994 0.004 0.622 19.4 0.622 19.4 6 25 0.63 24.4 0.63 24.4 0.63 24.4 4 30 0.637 29.4 0.637 29.4 0.637 29.4 8 40 0.65 39.4 0.65 39.4 0.65 39.4 9 50 0.66 49.3 0.66 49.3 0.66 49.3 10 60 0.67 59.3 0.67 59.3 0.67 59.3 11 70 0.679 69.3 0.679 69.3 SCR (Reversed Bias…arrow_forwardSee both images attachedarrow_forward
- 5 Find the value of voltage Vy using nodal analysis (write and then solve the set of equations to get voltage Vx from your variables.) 43 LX + Vx да ww 1 23 дъх 83 38 wwarrow_forwardhelp on this question about block diagram reduction?arrow_forward4) Find the valve of current if using nodal analys.3. (write and then solve the set of equations toget current Ex from your voltage variables.) M 3 ча + GA हुप 8Aarrow_forward
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