Please see both images to answer a) Sketch the electrostatic potential (V) inside the semiconductor.b) Sketch the electric field (εɛ)c) Does equilibrium condition prevail?d) At x = x2, p = ?e) What is the electron current density (JN) flowing at x = x1f) What is the hole drift current density (JP drift) flowing at x=x1g) What is the kinetic energy of the hole shown on the diagram? A silicon device maintained at 300K is characterized by the following energy band diagram. Use the citedenergy band diagram in answering following questions.ExEG/3HoleX1 L/3X22L/3

Answered: Image /qna-images/answer/6c8f419c-93e7-4c3d-b5b9-b2ed50179484.jpg

Answered: a) Sketch the electrostatic potential…

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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Consider an extrinsic semiconductor. Given: /n = 6550 cm² /V sec Mp = 400 cm²/V sec ni = 5.6 x 1012/cm³ Find out the hole and electron concentration in the semiconductor when conductivity is minimum (in cm-³).
At 305 °K temperature, the voltage equivalent of temperature of diode is ______________________V. Assume the Boltzmann's constant is 8.62*10-5 eV / K Answer:
The figure given below represents the energy-band diagram in the p-type semiconductor of a MOS capacitor, indicating surface potential as 0.254 V and the space charge width is 0.30 µm. Then the acceptor doping concentration is x 10¹5 cm-3. (Assume Esi = 11.7 &&0 8.85 x 10-14 F/cm). Os = 0.254 V oxide Xd 0.30 μm p-type E Efi EF MM Ev
Please Help ASAP!!! Just do A-C
The applied electric field in p-type silicon is E=10V/cm. The semiconductor conductivity is 1.5(Ω-cm)-1and cross-sectional area is 10-5cm2. Determine the driftcurrent. (b) A drift current density of 120A/cm2is established in n-type silicon with an applied electric field of 18V/cm. If the electron and hole mobilities are µn =1250 cm2/V-s and µp =450 cm2/V-s, respectively, determine the required doping concentration.
The energy band diagram of a p-type semiconductor bar of length L under equilibrium condition (i.e, the Fermi energy level Ef is constant) is shown in the figure. The valence band E, is sloped since doping is non-uniform along the bar. The difference between the energy levels of the valence band at the two edges of the bar is A. p-type Ef Ev z = 0 z = L If the charge of an electron is q, then the magnitude of the electric field developed inside this semiconductor bar is
A. Why does the conductivity of a semiconductor and some insulators change with impurity content? Compare this with the behaviour of metallic conductors. B. Discuss the location of the Fermi levels of intrinsic and extrinsic (n-type and p-type) semiconductors in low temperature and high temperature ranges. C. Discuss why the structure of the p-n junction is so important to modern technologies that impact our daily life.
In electronic circuits it is not unusual to encounter currents in themicroampere range. Assume a 35 μA current, due to the flow ofelectrons. What is the average number of electrons per second that flowpast a fixed reference cross section that is perpendicular to the directionof flow?
Calculate the drift current density in a semiconductor for a given electric field.Consider a germanium sample at T = 300°K with doping concentration of Nd = 0 and Na= 1016 cm-3. Assume complete ionization and electron and hole mobilities are 3900 cm2/V⋅sec and 1900 cm2/V⋅sec. The applied electric field is E = 50 V/cm
PROBLEM 1 Calculate the drift current density in a semiconductor for a given electric field. Consider a germanium sample at T = 300°K with doping concentration of Nd = 0 and No = 1016 cm-3 . Assume complete ionization and electron and hole mobilities are 3900 cm²/V-sec and 1900 cm2/V-sec. The applied electric field is E = 50 V/cm.
In semiconductors, a. the valence band is fully filled with electrons and there is a small energy gap before next permissible energy band. b. the valence band is fully filled with electrons and overlaps the next permissible energy band. c. the valence band is fully filled with electrons and there is a large energy gap before next permissible energy band. d. the valence band is only half filled with electrons.

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