Problem 4-4 A simple pendulum is shown below. y Yo The angle of the pendulum obeys the following equation: 0(t) = 0 cas where g is the gravity of Earth, and L is the length of the pendulum in meters. O is the initial angle of the pendulum. For the purposes of this problem, you can assume that Earth's gravity g is approximately equal to x². (a) Suppose that you are told that (1) is the signal given below. 10 theta(t) 5 -5 -10 0 0.5 1 1.5 2 2.5 3 3.5 4 4.5 t (secs) What is the length of the pendulum? 5 5.5 6 (b) Now suppose that you have another pendulum with a length equal to , where L is the same as the value in the previous part. The initial angle is the same as in the previous part. Sketch (1) for this pendulum on the graph below. 10 theta (t) 5 0 -5 -10 0 0.5 1 1.5 2 2.5 3 3.5 4 4.5 5 5.5 6 t (secs) (c) Suppose that you take the first pendulum (with length L) to another location in the solar system and observe the following graph for (t). A reference table of the gravities in other locations is given below. 10 theta (t) ° -5 -10 5 0 0.5 1 1.5 2 2.5 3 3.5 4 4.5 5 5.5 6 t (secs) Where are you? Location Mercury Venus Earth Moon Ratio of 0.378 0.907 1 Mars Jupiter Saturn Uranus Neptune Pluto 0.166 0.377 2.36 0.916 0.889 1.12 0.071 gravity to Earth's gravity
Problem 4-4 A simple pendulum is shown below. y Yo The angle of the pendulum obeys the following equation: 0(t) = 0 cas where g is the gravity of Earth, and L is the length of the pendulum in meters. O is the initial angle of the pendulum. For the purposes of this problem, you can assume that Earth's gravity g is approximately equal to x². (a) Suppose that you are told that (1) is the signal given below. 10 theta(t) 5 -5 -10 0 0.5 1 1.5 2 2.5 3 3.5 4 4.5 t (secs) What is the length of the pendulum? 5 5.5 6 (b) Now suppose that you have another pendulum with a length equal to , where L is the same as the value in the previous part. The initial angle is the same as in the previous part. Sketch (1) for this pendulum on the graph below. 10 theta (t) 5 0 -5 -10 0 0.5 1 1.5 2 2.5 3 3.5 4 4.5 5 5.5 6 t (secs) (c) Suppose that you take the first pendulum (with length L) to another location in the solar system and observe the following graph for (t). A reference table of the gravities in other locations is given below. 10 theta (t) ° -5 -10 5 0 0.5 1 1.5 2 2.5 3 3.5 4 4.5 5 5.5 6 t (secs) Where are you? Location Mercury Venus Earth Moon Ratio of 0.378 0.907 1 Mars Jupiter Saturn Uranus Neptune Pluto 0.166 0.377 2.36 0.916 0.889 1.12 0.071 gravity to Earth's gravity
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I need help with this problem and an explanation of the solution for the image described below. (Introduction to Signals and Systems)
![Problem 4-4
A simple pendulum is shown below.
y
Yo
The angle of the pendulum obeys the following equation:
0(t) = 0 cas
where g is the gravity of Earth, and L is the length of the pendulum in meters. O is the initial angle of
the pendulum. For the purposes of this problem, you can assume that Earth's gravity g is approximately
equal to x².
(a) Suppose that you are told that (1) is the signal given below.
10
theta(t)
5
-5
-10
0
0.5
1
1.5
2
2.5
3
3.5
4
4.5
t (secs)
What is the length of the pendulum?
5
5.5
6](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fea56b2d3-976b-48ba-b1de-ef5a4d536379%2F9f006c15-74a8-47f9-a656-ae8a403f4cdc%2F75wr9nr_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Problem 4-4
A simple pendulum is shown below.
y
Yo
The angle of the pendulum obeys the following equation:
0(t) = 0 cas
where g is the gravity of Earth, and L is the length of the pendulum in meters. O is the initial angle of
the pendulum. For the purposes of this problem, you can assume that Earth's gravity g is approximately
equal to x².
(a) Suppose that you are told that (1) is the signal given below.
10
theta(t)
5
-5
-10
0
0.5
1
1.5
2
2.5
3
3.5
4
4.5
t (secs)
What is the length of the pendulum?
5
5.5
6
![(b) Now suppose that you have another pendulum with a length equal to , where L is the same as
the value in the previous part. The initial angle is the same as in the previous part. Sketch (1) for
this pendulum on the graph below.
10
theta (t)
5
0
-5
-10
0
0.5
1
1.5
2
2.5
3
3.5
4
4.5
5
5.5
6
t (secs)
(c) Suppose that you take the first pendulum (with length L) to another location in the solar system
and observe the following graph for (t). A reference table of the gravities in other locations is
given below.
10
theta (t)
°
-5
-10
5
0
0.5
1
1.5
2
2.5
3
3.5
4
4.5
5
5.5
6
t (secs)
Where are you?
Location
Mercury Venus
Earth Moon
Ratio of 0.378 0.907
1
Mars Jupiter Saturn Uranus Neptune Pluto
0.166 0.377 2.36 0.916 0.889
1.12
0.071
gravity to
Earth's
gravity](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fea56b2d3-976b-48ba-b1de-ef5a4d536379%2F9f006c15-74a8-47f9-a656-ae8a403f4cdc%2F6ya781e_processed.jpeg&w=3840&q=75)
Transcribed Image Text:(b) Now suppose that you have another pendulum with a length equal to , where L is the same as
the value in the previous part. The initial angle is the same as in the previous part. Sketch (1) for
this pendulum on the graph below.
10
theta (t)
5
0
-5
-10
0
0.5
1
1.5
2
2.5
3
3.5
4
4.5
5
5.5
6
t (secs)
(c) Suppose that you take the first pendulum (with length L) to another location in the solar system
and observe the following graph for (t). A reference table of the gravities in other locations is
given below.
10
theta (t)
°
-5
-10
5
0
0.5
1
1.5
2
2.5
3
3.5
4
4.5
5
5.5
6
t (secs)
Where are you?
Location
Mercury Venus
Earth Moon
Ratio of 0.378 0.907
1
Mars Jupiter Saturn Uranus Neptune Pluto
0.166 0.377 2.36 0.916 0.889
1.12
0.071
gravity to
Earth's
gravity
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