A wattmeter has its current coil connected in the yellow line, and its voltage circuit is connected between the red and blue lines. The line voltage is 400 V and the balanced load takes a line current of 30 A at a power factor of 0.7 lagging. Draw circuit and phasor diagrams and derive an expression for the reading on the wattmeter in terms of the line voltage and current and of the phase difference between the phase voltage and current. Calculate the value of the wattmeter indication. ANS: . Line amperes × line volts × sin φ = 8750 var
A wattmeter has its current coil connected in the yellow line, and its voltage circuit is connected between the red and blue lines. The line voltage is 400 V and the balanced load takes a line current of 30 A at a power factor of 0.7 lagging. Draw circuit and phasor diagrams and derive an expression for the reading on the wattmeter in terms of the line voltage and current and of the phase difference between the phase voltage and current. Calculate the value of the wattmeter indication. ANS: . Line amperes × line volts × sin φ = 8750 var
Power System Analysis and Design (MindTap Course List)
6th Edition
ISBN:9781305632134
Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Chapter2: Fundamentals
Section: Chapter Questions
Problem 2.23P: A single-phase source has a terminal voltage V=1200volts and a currentI=1530, which leaves the...
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Question
A wattmeter has its current coil connected in the yellow
line, and its voltage circuit is connected between the
red and blue lines. The line voltage is 400 V and the
balanced load takes a line current of 30 A at a power
factor of 0.7 lagging. Draw circuit and phasor diagrams
and derive an expression for the reading on the wattmeter
in terms of the line voltage and current and of the phase
difference between the phase voltage and current.
Calculate the value of the wattmeter indication.
ANS:
. Line amperes × line volts × sin φ = 8750 var
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