Problem 6 (25 points) (Chap 9) (Learning objective: Plane waves) 9.5-1 A uniform plane wave propagating in free space has an electric field intensity equal to êЕo cos (wt + [1 rad/m] + [2 rad/m] y + [3 rad/m] 2). The direction of "e" is not specified. (a) What is the unit vector that points in the direction of propagation? Be as specific as possible. (b) What is the wavelength in this material? (c) What is the frequency of the wave?

Which of the following statements about electromagnetic waves in free space are true? Choose all that apply The wavelengths of the visible waves are some of the shortest electromagnetic waves. The higher-frequency waves have shorter wavelengths than the lower- frequency waves. The electric field vector is always at right angles to the magnetic field vector. The wavelengths of the visible waves are some of the longest electromagnetic waves. The higher-frequency travel faster than the lower-frequency waves. (Explain thoroughly the correct options)

The presence of a few negative alignments of magnetic dipole moment is given by which materials?     Paramagnetic       Ferromagnetic     Diamagnetic     None of these

Consider a closed triangular box resting within a horizontal electric field of magnitude E = 6.86 × 104 N/C as shown in the figure below. 30.0 cm A closed right triangular box with its vertical side on the left and downward slope on the right rests within a horizontal electric field vector E that points from left to right. The box has a height of 10.0 cm and a depth of 30.0 cm. The downward slope of the box makes an angle of 60 degrees with the vertical. (a) Calculate the electric flux through the vertical rectangular surface of the box. kN • m?/c (b) Calculate the electric flux through the slanted surface of the box. kN • m?/c (c) Calculate the electric flux through the entire surface of the box. kN • m2/c