Chapter 17, Problem 30AE

Interpretation Introduction

Interpretation:

Volume of ${\text{NO}}_2$ produced when $\text{75}\text{.5 g}$ of $\text{Cu}$ metal reacts with $\text{55}\text{.0 g}$ of ${\text{HNO}}_3$ has to be calculated and substance that gets oxidized and reduced have to be identified.

Concept Introduction:

The formula to calculate volume as per the ideal gas equation is as follows:

  $V=\frac{nRT}{P}$

Here,

$\text{R}$ is universal gas constant.

$V$ denotes volume.

$n$ denotes number of moles.

$T$ denotes temperature.

$P$ denotes pressure.

Oxidation refers to phenomenon of loss of electrons; loss of electropositive $\text{H}$ and gain of electronegative $\text{O}$ whereas reduction is process that involves gain of electrons, gain of $\text{H}$ or loss of electronegative $\text{O}$ atom.