Chapter 17, Problem 17PE

(a)

Interpretation Introduction

Interpretation:

The below redox reaction in basic solution has to be balanced.

  ${\text{Cl}}_2+{\text{IO}}_3^{-}\to {\text{Cl}}^{-}+{\text{IO}}_4^{-}$

Concept Introduction:

Rules to balance redox reactions by ion-electron method to are as follows:

1. Two half-reactions with elements that got oxidized and reduced should be written.

2. Elements other than oxygen and hydrogen should be balanced.

3. Conditions to balance $\text{O}$ and $\text{H}$ are as follows:

In acidic solution, ${\text{H}}^{+}$ and ${\text{H}}_2\text{O}$ should be used to balance $\text{O}$ and $\text{H}$.

In basic solution, equal ${\text{OH}}^{-}$ ions to ${\text{H}}^{+}$ ions should be added on both sides of balanced reaction in acidic medium.

4. For acidic medium, charge is balanced by addition of ${\text{H}}^{+}$ ion. Then combine ${\text{H}}^{+}$ and ${\text{OH}}^{-}$ to form ${\text{H}}_2\text{O}$ and cancel common ${\text{H}}_2\text{O}$ in reaction.

5. Electrons should be added to balance electric charge.

6. Finally, two half-reactions should be added and any common substance including electrons must be cancelled.

(b)

Interpretation Introduction

Interpretation:

The below redox reaction in basic solution has to be balanced.

  ${\text{MnO}}_4^{-}+{\text{ClO}}_2\to {\text{MnO}}_2+{\text{ClO}}_4$

Concept Introduction:

Refer to part (a).

(c)

Interpretation Introduction

Interpretation:

The below redox reaction in basic solution has to be balanced.

  $\text{Se}\to {\text{Se}}^{\text{2}-}+{\text{SeO}}_3^{2-}$

Concept Introduction:

Refer to part (a).

(d)

Interpretation Introduction

Interpretation:

The below redox reaction in basic solution has to be balanced.

  ${\text{Fe}}_{\text{3}}{\text{O}}_4+{\text{MnO}}_4^{-}\to {\text{Fe}}_{\text{2}}{\text{O}}_3+{\text{MnO}}_2$

Concept Introduction:

Refer to part (a).

(e)

Interpretation Introduction

Interpretation:

The below redox reaction in basic solution has to be balanced.

  ${\text{BrO}}^{-}+\text{Cr}{\left(\text{OH}\right)}_4^{-}\to {\text{Br}}^{-}+{\text{CrO}}_4^{2-}$

Concept Introduction:

Refer to part (a).