Study Guide for Campbell Biology
11th Edition
ISBN: 9780134443775
Author: Lisa A. Urry, Michael L. Cain, Steven A. Wasserman, Peter V. Minorsky, Jane B. Reece, Martha R. Taylor, Michael A. Pollock
Publisher: PEARSON
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Chapter 17, Problem 2IQ
Summary Introduction
To determine: The amino acid sequence for a polypeptide codon by the given mRNA transcript.
Introduction: The genetic information of DNA is encrypted in the
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Using the genetic code table provided below, write out the sequence of three different possible
mRNA sequences that could encode the following sequence of amino acids:
Met-Phe-Cys-Trp-Glu
C
A
G
U
C
UUU Phe UCU Ser
UUC Phe UCC Ser
UCA Ser
UUA Leu
UUG Leu UCG Ser
CUU Leu CCU Pro
CUC Leu
CUA Leu
CUG Leu CCG
A
CAU His CGU Arg
CCC Pro CAC His CGC Arg
UAU Tyr UGU Cys U
UAC Tyr UGC Cys C
Stop UGA Stop
Stop UGG
Trp
UAA
A
UAG
G
CCA Pro CAA Gln
Pro CAG
AUU lle
AUC lle
AUA lle
AUG Met ACG
G
등등
Gln
CGA Arg
CGG Arg
ACU Thr AAU Asn AGU Ser
ACC
AAC Asn
AGC Ser
Thr
ACA Thr
Thr
AAA Lys AGA Arg
AAG
Lys
AGG Arg
GUU Val GCU
Ala
GAU Asp
GGU Gly
GGC Gly
GUC Val GCC
Ala
GAC
Asp
GUA Val
GCA
Ala
GAA
Glu GGA Gly
GUG Val
GCG Ala GAG
Glu GGG Gly
U
C
A
G
U
C
A
G
SUAU
Decode the unknown word using the genetic code and fill out the missing nucleotides. Translate the generated mRNA sequence using the universal genetic code table and the information derived from the previous steps. Determine the unknown word by arranging the single letter amino acid code of the hypothetical protein produced bound by the start and stop codon.
Consider the following coding 71 nucleotide DNA template sequence (It does not contain a translational start):
5’- GTTTCCCCTATGCTTCATCACGAGGGCACTGACATGTGTAAACGAAATTCCAACCTGAGCGGCGT GTTGAG-3’
By in vitro translating the mRNA, you determined that the translated peptide is 15 amino acids long. What is the expected peptide sequence in single letter abbreviations?
Chapter 17 Solutions
Study Guide for Campbell Biology
Ch. 17 - a. In what three ways does RNA differ from DNA? b....Ch. 17 - Prob. 2IQCh. 17 - Prob. 3IQCh. 17 - How does the mRNA that leaves the nucleus differ...Ch. 17 - Prob. 5IQCh. 17 - In the following diagrams of polypeptide...Ch. 17 - What determines if a ribosome becomes bound to the...Ch. 17 - Define the following terms and explain what type...Ch. 17 - You have been introduced to several types of RNA...Ch. 17 - Prob. 2SYK
Ch. 17 - What is the genetic code? Explain redundancy and...Ch. 17 - Prepare a concept map showing the types and...Ch. 17 - Prob. 1TYKCh. 17 - Transcription involves the transfer of information...Ch. 17 - Prob. 3TYKCh. 17 - Prob. 4TYKCh. 17 - Which of the following is a statement of the...Ch. 17 - Prob. 6TYKCh. 17 - Prob. 7TYKCh. 17 - Prob. 8TYKCh. 17 - Which of the following is true of RNA processing?...Ch. 17 - Prob. 10TYKCh. 17 - Prob. 11TYKCh. 17 - Prob. 12TYKCh. 17 - Prob. 13TYKCh. 17 - Prob. 14TYKCh. 17 - What type of bonding is responsible for...Ch. 17 - Prob. 16TYKCh. 17 - Prob. 17TYKCh. 17 - Prob. 18TYKCh. 17 - Prob. 19TYKCh. 17 - Prob. 20TYKCh. 17 - Prob. 21TYKCh. 17 - Prob. 22TYKCh. 17 - Prob. 23TYKCh. 17 - Prob. 24TYKCh. 17 - Prob. 25TYKCh. 17 - Prob. 26TYKCh. 17 - Prob. 27TYKCh. 17 - Prob. 28TYK
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Similar questions
- Consider the following DNA sequence, which codes for a short polypeptide: 5'-ATGGGCTTAGCGTAGGTTAGT-3' Determine the mRNA transcript of this sequence. You have to write these sequences from the 5' end to the 3' end and indicate those ends as shown in the original sequence in order to get the full mark. How many amino acids will make up this polypeptide? Determine the first four anticodons that will be used in order to translate this sequence.arrow_forwardThe following RNA sequence represents a small messenger which can be translated in a prokaryotic cell: 5'-ACGAAUGCACAGUAAAACUGGCUAGCGUAGGCUGA-3 Assume that the messenger RNA is translated in the cell, using the correct machinery and signals required for accurate protein synthesis. Using this RNA sequence and the Genetic Code Dictionary (see your textbook for the dictionary), solve the following problems A. Write the sequence of a protein that would be translated from this mRNA, using the appropriate stop and start signals, and indicating the correct termini of the protein product. B. Suppose that the underlined A in the sequence is changed to a U. Write the expected protein product of this mRNA.arrow_forwardDecode the unknown word using the genetic code and fill out the missing nucleotides. Translate the generated mRNA sequence using the universal genetic code table and the information derived from the previous steps. Determine the unknown word by arranging the single letter amino acid code of the hypothetical protein produced bound by the start and stop codon.arrow_forward
- Template strand of DNA is: 3’ TACATAACCGGGCCCATATCGGCCATTTGC5’. 2a). Following transcription, what is the total number of codons in the mRNA transcript? 2 b). Where is the start codon located in this mRNA transcript? 2c). Following translation of this mRNA transcript, how many amino acids will the proteincontain and identify the amino acids sequence of this gene from a genetic code table*.*Note= using a genetic code tablearrow_forwardIdentify (and highlight or underline) the one nucleotide difference between the original (left) and altered (right) sequencesarrow_forwardc) A gene in a bacteria has the following DNA sequences (the promoter sequence is positioned to the left but is not shown): 5'-CAATCATGGAATGCCATGCTTCATATGAATAGTTGACAT-3' 3'-GTTAGTACCT TACGGTACGAAGTATACTTATCAACTGTA-5' i) By referring to the codon table below, write the corresponding mRNA transcript and polypeptide translated from this DNA strand. 2 Second letter с A UUUPhe UAU Tyr UAC. UGU UGCJ UCU) UCC UCA UUG Leu UCG Cys UUC UUA Ser UAA Stop UGA Stop A UAG Stop UGG Trp G CUU CÚC CCU ССС CAU CGU His САC Pro CC CỦA Leu ССА CAA Arg CGA CUG J CCG) CAG Gin CGG AUU ACU AAU Asn AGU Ser AUC le АСC АCА AAC AAA AGC. Thr JArg AUA AGA AUG Met ACG AAG Lys AGG. GAU Asp GUU) GCU GCC GCA GCG GGU" GGC GGA GGG GUC Val GUA GAC Ala Gly GAA Glu GAGJ GUG ii) If the nucleotide indicated by the highlighted bold letter undergoes a mutation that resulted in deletion of the C:G base pair, what will be the resulting amino acid sequence following transcription and translation? Third letter DUAG DUAG DUAG A. First…arrow_forward
- Knowing that the genetic code is almost universal, a scientist uses molecular biological methods to insert the human - globin gene (shown in the figure below (Links to an external site.)) into bacterial cells, hoping the cells will express it and synthesize functional - globin protein. Instead, the protein produced is nonfunctional and is found to contain many fewer amino acids than does -globin made by a eukaryotic cell. Explain why and give thoughts as to how to overcome this.arrow_forwardPlease by using the first base of each as the first triplet in a condo, how do I translate two almost identical RNA strand into sequences? You will notice that the second strand has a point deletion (the u in bold) with respect to the first strand – comment on how this has affected the resulting peptide chain. aguuguuaucgaaaacugcgaguaaauauccugagggcgcgaagcaacc aguuguaucgaaaacugcgaguaaauauccugagggcgcgaagcaaccarrow_forwardConsider the following DNA template: 5’-AAGAGGTTCCAATGCAGGCACTCACCAACTCTTAAATAAA-3’ 3’-TTCTCCAAGGTTACGTCCGTGAGTGGTTGAGAATTTATTT-5’ If the bottom DNA strand is used as template to transcribe mRNA, predict the amino acid sequence that would result from the process of translation. Met-Ala-Leu-Thr-Gln-Glu-Gly Met-Gly-Ser-Leu-Asn-Ser-Gln Met-Thr-Asn-Ser-Leu-Ala-Gln Met-Gln-Ala-Leu-Thr-Asn-Ser Met-Glu-Ala-His-Trp-Ser-Tyrarrow_forward
- In the copies of each sequence below, divide the sequences into codons (triplets) by putting a slash between each group of three bases. Sequence ATCTTCCCTCCTAAACGTTCAACCGGTTCTTAATCCGCCGCCAGGGCCCCGCCCCTCAGAAGTTGGTSequence BTCAGACGTTTTTGCCCCGTAACAACTTGTTACAACATGGTCATAAACGTCAGAGATGGTCAATCTCTTAATGACTSequence CTACAAACATGTAAACACACCCTCAGTGGACCAACTCCGCAACATAAACCAAACACCGCTCGCGCCGAAAAAGATATGGarrow_forwardFor the messenger RNA sequence below, find the beginning of the amino acid coding sequence and translate the sequence using the genetic code provided below. 5' - AAUUAUGGGCAAUAUGCCGGGCcGGUUAAGCG - 3' Second Letter A UGU cys u UGC Phe UCU UU U UUC UUA UAU Tyr Ser UAC UAA UAG Leu UCA Stop UGA Stop UUG UCG Stop UGG Trp CUU CU CAU His CGU c cuc Leu ccc ССА CCG Pro CÁC CAA CAG CGC CGA CGG Arg CUA CUG Gin 1st 3rd letter Ser u letter AUU ACU AAU AAC AAA AAG Asn A AUC AUA AUG lle ACC ACA AGU AGC AGA AGG Thr Lys Arg Met ACG GUU G GUC GUA GUG GCU GAU GAC GAA Asp GGU Val GCC Ala GGC Gly GCA GGA Glu GCG GAG GGG Garrow_forwardSequence: CUCAACACGCCGCUCAGUGCCCUCGUGAUGAAGCAUAGGGGAAAC By in vitro translating the mRNA, you determined that the translated peptide is 15 amino acids long. What is the expected peptide sequence in single letter abbreviations?arrow_forward
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