Study Guide for Campbell Biology
11th Edition
ISBN: 9780134443775
Author: Lisa A. Urry, Michael L. Cain, Steven A. Wasserman, Peter V. Minorsky, Jane B. Reece, Martha R. Taylor, Michael A. Pollock
Publisher: PEARSON
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Question
Chapter 17, Problem 2IQ
Summary Introduction
To determine: The amino acid sequence for a polypeptide codon by the given mRNA transcript.
Introduction: The genetic information of DNA is encrypted in the
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Using the genetic code table provided below, write out the sequence of three different possible
mRNA sequences that could encode the following sequence of amino acids:
Met-Phe-Cys-Trp-Glu
C
A
G
U
C
UUU Phe UCU Ser
UUC Phe UCC Ser
UCA Ser
UUA Leu
UUG Leu UCG Ser
CUU Leu CCU Pro
CUC Leu
CUA Leu
CUG Leu CCG
A
CAU His CGU Arg
CCC Pro CAC His CGC Arg
UAU Tyr UGU Cys U
UAC Tyr UGC Cys C
Stop UGA Stop
Stop UGG
Trp
UAA
A
UAG
G
CCA Pro CAA Gln
Pro CAG
AUU lle
AUC lle
AUA lle
AUG Met ACG
G
등등
Gln
CGA Arg
CGG Arg
ACU Thr AAU Asn AGU Ser
ACC
AAC Asn
AGC Ser
Thr
ACA Thr
Thr
AAA Lys AGA Arg
AAG
Lys
AGG Arg
GUU Val GCU
Ala
GAU Asp
GGU Gly
GGC Gly
GUC Val GCC
Ala
GAC
Asp
GUA Val
GCA
Ala
GAA
Glu GGA Gly
GUG Val
GCG Ala GAG
Glu GGG Gly
U
C
A
G
U
C
A
G
SUAU
Decode the unknown word using the genetic code and fill out the missing nucleotides. Translate the generated mRNA sequence using the universal genetic code table and the information derived from the previous steps. Determine the unknown word by arranging the single letter amino acid code of the hypothetical protein produced bound by the start and stop codon.
Consider the following coding 71 nucleotide DNA template sequence (It does not contain a translational start):
5’- GTTTCCCCTATGCTTCATCACGAGGGCACTGACATGTGTAAACGAAATTCCAACCTGAGCGGCGT GTTGAG-3’
By in vitro translating the mRNA, you determined that the translated peptide is 15 amino acids long. What is the expected peptide sequence in single letter abbreviations?
Chapter 17 Solutions
Study Guide for Campbell Biology
Ch. 17 - a. In what three ways does RNA differ from DNA? b....Ch. 17 - Prob. 2IQCh. 17 - Prob. 3IQCh. 17 - How does the mRNA that leaves the nucleus differ...Ch. 17 - Prob. 5IQCh. 17 - In the following diagrams of polypeptide...Ch. 17 - What determines if a ribosome becomes bound to the...Ch. 17 - Define the following terms and explain what type...Ch. 17 - You have been introduced to several types of RNA...Ch. 17 - Prob. 2SYK
Ch. 17 - What is the genetic code? Explain redundancy and...Ch. 17 - Prepare a concept map showing the types and...Ch. 17 - Prob. 1TYKCh. 17 - Transcription involves the transfer of information...Ch. 17 - Prob. 3TYKCh. 17 - Prob. 4TYKCh. 17 - Which of the following is a statement of the...Ch. 17 - Prob. 6TYKCh. 17 - Prob. 7TYKCh. 17 - Prob. 8TYKCh. 17 - Which of the following is true of RNA processing?...Ch. 17 - Prob. 10TYKCh. 17 - Prob. 11TYKCh. 17 - Prob. 12TYKCh. 17 - Prob. 13TYKCh. 17 - Prob. 14TYKCh. 17 - What type of bonding is responsible for...Ch. 17 - Prob. 16TYKCh. 17 - Prob. 17TYKCh. 17 - Prob. 18TYKCh. 17 - Prob. 19TYKCh. 17 - Prob. 20TYKCh. 17 - Prob. 21TYKCh. 17 - Prob. 22TYKCh. 17 - Prob. 23TYKCh. 17 - Prob. 24TYKCh. 17 - Prob. 25TYKCh. 17 - Prob. 26TYKCh. 17 - Prob. 27TYKCh. 17 - Prob. 28TYK
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- Template strand of DNA is: 3’ TACATAACCGGGCCCATATCGGCCATTTGC5’. 2a). Following transcription, what is the total number of codons in the mRNA transcript? 2 b). Where is the start codon located in this mRNA transcript? 2c). Following translation of this mRNA transcript, how many amino acids will the proteincontain and identify the amino acids sequence of this gene from a genetic code table*.*Note= using a genetic code tablearrow_forwardIdentify (and highlight or underline) the one nucleotide difference between the original (left) and altered (right) sequencesarrow_forwardc) A gene in a bacteria has the following DNA sequences (the promoter sequence is positioned to the left but is not shown): 5'-CAATCATGGAATGCCATGCTTCATATGAATAGTTGACAT-3' 3'-GTTAGTACCT TACGGTACGAAGTATACTTATCAACTGTA-5' i) By referring to the codon table below, write the corresponding mRNA transcript and polypeptide translated from this DNA strand. 2 Second letter с A UUUPhe UAU Tyr UAC. UGU UGCJ UCU) UCC UCA UUG Leu UCG Cys UUC UUA Ser UAA Stop UGA Stop A UAG Stop UGG Trp G CUU CÚC CCU ССС CAU CGU His САC Pro CC CỦA Leu ССА CAA Arg CGA CUG J CCG) CAG Gin CGG AUU ACU AAU Asn AGU Ser AUC le АСC АCА AAC AAA AGC. Thr JArg AUA AGA AUG Met ACG AAG Lys AGG. GAU Asp GUU) GCU GCC GCA GCG GGU" GGC GGA GGG GUC Val GUA GAC Ala Gly GAA Glu GAGJ GUG ii) If the nucleotide indicated by the highlighted bold letter undergoes a mutation that resulted in deletion of the C:G base pair, what will be the resulting amino acid sequence following transcription and translation? Third letter DUAG DUAG DUAG A. First…arrow_forward
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