GENERAL,ORGANIC,+BIO.CHEM.-MINDTAP
GENERAL,ORGANIC,+BIO.CHEM.-MINDTAP
7th Edition
ISBN: 9781305866966
Author: STOKER
Publisher: CENGAGE L
bartleby

Concept explainers

bartleby

Videos

Question
Book Icon
Chapter 17, Problem 17.138EP

(a)

Interpretation Introduction

Interpretation:

Structure of missing substance in the given reaction that involves amides has to be drawn.

Concept Introduction:

Amides are synthesized using amidification reaction.  This involves a reaction between amine and carboxylic acid.  In this reaction, the OH group present in carboxylic acid and H from ammonia or amine is lost to give amide as the product.  Water is obtained as a by-product in this reaction.  The general reaction scheme for synthesis of amides can be given as,

Ammonia + Carboxylic acid 100 °C amideamine + Carboxylic acid 100 °C amideamine + Carboxylic acid 100 °C amide

(a)

Expert Solution
Check Mark

Answer to Problem 17.138EP

Structure of the missing substance is,

GENERAL,ORGANIC,+BIO.CHEM.-MINDTAP, Chapter 17, Problem 17.138EP , additional homework tip  1

Explanation of Solution

Given reaction is,

GENERAL,ORGANIC,+BIO.CHEM.-MINDTAP, Chapter 17, Problem 17.138EP , additional homework tip  2

The starting material is a carboxylic acid and a primary amine.  The product obtained on amidification reaction between carboxylic acid and a primary amine is a secondary amide.  This is formed by the loss of water molecule.  The structure of the secondary amide that is formed can be given as,

GENERAL,ORGANIC,+BIO.CHEM.-MINDTAP, Chapter 17, Problem 17.138EP , additional homework tip  3

The complete reaction can be given as,

GENERAL,ORGANIC,+BIO.CHEM.-MINDTAP, Chapter 17, Problem 17.138EP , additional homework tip  4

Conclusion

Structure of the missing compound is drawn.

(b)

Interpretation Introduction

Interpretation:

Structure of missing substance in the given reaction that involves amides has to be drawn.

Concept Introduction:

Amides are synthesized using amidification reaction.  This involves a reaction between amine and carboxylic acid.  In this reaction, the OH group present in carboxylic acid and H from ammonia or amine is lost to give amide as the product.  Water is obtained as a by-product in this reaction.  The general reaction scheme for synthesis of amides can be given as,

Ammonia + Carboxylic acid 100 °C amideamine + Carboxylic acid 100 °C amideamine + Carboxylic acid 100 °C amide

(b)

Expert Solution
Check Mark

Answer to Problem 17.138EP

Structure of the missing substance is,

GENERAL,ORGANIC,+BIO.CHEM.-MINDTAP, Chapter 17, Problem 17.138EP , additional homework tip  5

Explanation of Solution

Given reaction is,

GENERAL,ORGANIC,+BIO.CHEM.-MINDTAP, Chapter 17, Problem 17.138EP , additional homework tip  6

As the nitrogen atom present in the above amide has two hydrogen atoms bonded to it and the amide is a primary amide.  Primary amide is produced by the reaction of ammonia with carboxylic acid.  The structure of carboxylic acid can be found as shown below,

GENERAL,ORGANIC,+BIO.CHEM.-MINDTAP, Chapter 17, Problem 17.138EP , additional homework tip  7

Hydrogen atom has to be added to the amine part and OH group has to be added to the acid part in order to obtain the parent molecules.  From this the missing compound is identified as,

GENERAL,ORGANIC,+BIO.CHEM.-MINDTAP, Chapter 17, Problem 17.138EP , additional homework tip  8

The complete reaction can be given as,

GENERAL,ORGANIC,+BIO.CHEM.-MINDTAP, Chapter 17, Problem 17.138EP , additional homework tip  9

Conclusion

Structure of the missing compound is drawn.

(c)

Interpretation Introduction

Interpretation:

Structure of missing substance in the given reaction that involves amides has to be drawn.

Concept Introduction:

Amides are synthesized using amidification reaction.  This involves a reaction between amine and carboxylic acid.  In this reaction, the OH group present in carboxylic acid and H from ammonia or amine is lost to give amide as the product.  Water is obtained as a by-product in this reaction.  The general reaction scheme for synthesis of amides can be given as,

Ammonia + Carboxylic acid 100 °C amideamine + Carboxylic acid 100 °C amideamine + Carboxylic acid 100 °C amide

(c)

Expert Solution
Check Mark

Answer to Problem 17.138EP

Structure of the missing substance is,

GENERAL,ORGANIC,+BIO.CHEM.-MINDTAP, Chapter 17, Problem 17.138EP , additional homework tip  10

Explanation of Solution

Given reaction is,

GENERAL,ORGANIC,+BIO.CHEM.-MINDTAP, Chapter 17, Problem 17.138EP , additional homework tip  11

As the nitrogen atom present in the above amide has no hydrogen atoms bonded to it, the amide is a tertiary amide.  Tertiary amide is produced by the reaction of secondary amine with carboxylic acid.  The parent compound structures can be identified as shown below,

GENERAL,ORGANIC,+BIO.CHEM.-MINDTAP, Chapter 17, Problem 17.138EP , additional homework tip  12

Hydrogen atom has to be added to the amine part and OH group has to be added to the acid part in order to obtain the parent molecules.  From this the missing compound is identified as,

GENERAL,ORGANIC,+BIO.CHEM.-MINDTAP, Chapter 17, Problem 17.138EP , additional homework tip  13

The complete reaction can be given as,

GENERAL,ORGANIC,+BIO.CHEM.-MINDTAP, Chapter 17, Problem 17.138EP , additional homework tip  14

Conclusion

Structure of the missing compound is drawn.

(d)

Interpretation Introduction

Interpretation:

Structure of missing substance in the given reaction that involves amides has to be drawn.

Concept Introduction:

Amides are synthesized using amidification reaction.  This involves a reaction between amine and carboxylic acid.  In this reaction, the OH group present in carboxylic acid and H from ammonia or amine is lost to give amide as the product.  Water is obtained as a by-product in this reaction.  The general reaction scheme for synthesis of amides can be given as,

Ammonia + Carboxylic acid 100 °C amideamine + Carboxylic acid 100 °C amideamine + Carboxylic acid 100 °C amide

(d)

Expert Solution
Check Mark

Answer to Problem 17.138EP

Structure of the missing substance is,

GENERAL,ORGANIC,+BIO.CHEM.-MINDTAP, Chapter 17, Problem 17.138EP , additional homework tip  15

Explanation of Solution

Given reaction is,

GENERAL,ORGANIC,+BIO.CHEM.-MINDTAP, Chapter 17, Problem 17.138EP , additional homework tip  16

As the nitrogen atom present in the above amide has one hydrogen atom bonded to it and the amide is a secondary amide.  Secondary amide is produced by the reaction of primary amine with carboxylic acid.  The structure of carboxylic acid is given and the structure of primary amine has to be found out.

GENERAL,ORGANIC,+BIO.CHEM.-MINDTAP, Chapter 17, Problem 17.138EP , additional homework tip  17

Hydrogen atom has to be added to the amine part and OH group has to be added to the acid part in order to obtain the parent molecules.  From this the missing compound is identified as,

GENERAL,ORGANIC,+BIO.CHEM.-MINDTAP, Chapter 17, Problem 17.138EP , additional homework tip  18

The complete reaction can be given as,

GENERAL,ORGANIC,+BIO.CHEM.-MINDTAP, Chapter 17, Problem 17.138EP , additional homework tip  19

Conclusion

Structure of the missing compound is drawn.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!
Students have asked these similar questions
You are trying to decide if there is a single reagent you can add that will make the following synthesis possible without any other major side products: xi 1. ☑ 2. H₂O хе i Draw the missing reagent X you think will make this synthesis work in the drawing area below. If there is no reagent that will make your desired product in good yield or without complications, just check the box under the drawing area and leave it blank. Click and drag to start drawing a structure. There is no reagent that will make this synthesis work without complications. : ☐ S ☐
Predict the major products of this organic reaction: H OH 1. LiAlH4 2. H₂O ? Note: be sure you use dash and wedge bonds when necessary, for example to distinguish between major products with different stereochemistry. Click and drag to start drawing a structure. G C टे
For each reaction below, decide if the first stable organic product that forms in solution will create a new C-C bond, and check the appropriate box. Next, for each reaction to which you answered "Yes" to in the table, draw this product in the drawing area below. Note for advanced students: for this problem, don't worry if you think this product will continue to react under the current conditions - just focus on the first stable product you expect to form in solution. NH2 CI MgCl ? Will the first product that forms in this reaction create a new CC bond? Yes No MgBr ? Will the first product that forms in this reaction create a new CC bond? Yes No G टे

Chapter 17 Solutions

GENERAL,ORGANIC,+BIO.CHEM.-MINDTAP

Ch. 17.4 - Prob. 1QQCh. 17.4 - Prob. 2QQCh. 17.5 - Prob. 1QQCh. 17.5 - Prob. 2QQCh. 17.5 - Prob. 3QQCh. 17.6 - Prob. 1QQCh. 17.6 - Prob. 2QQCh. 17.6 - Prob. 3QQCh. 17.7 - Prob. 1QQCh. 17.7 - Prob. 2QQCh. 17.7 - Prob. 3QQCh. 17.8 - Prob. 1QQCh. 17.8 - Prob. 2QQCh. 17.8 - Prob. 3QQCh. 17.8 - Prob. 4QQCh. 17.9 - Prob. 1QQCh. 17.9 - Prob. 2QQCh. 17.10 - Prob. 1QQCh. 17.10 - Prob. 2QQCh. 17.10 - Prob. 3QQCh. 17.10 - Prob. 4QQCh. 17.11 - Prob. 1QQCh. 17.11 - Prob. 2QQCh. 17.11 - Prob. 3QQCh. 17.12 - Prob. 1QQCh. 17.12 - Prob. 2QQCh. 17.12 - Prob. 3QQCh. 17.12 - Prob. 4QQCh. 17.13 - Prob. 1QQCh. 17.13 - Prob. 2QQCh. 17.13 - Prob. 3QQCh. 17.13 - Prob. 4QQCh. 17.14 - Prob. 1QQCh. 17.14 - Prob. 2QQCh. 17.14 - Prob. 3QQCh. 17.15 - Prob. 1QQCh. 17.15 - Prob. 2QQCh. 17.16 - Prob. 1QQCh. 17.16 - Prob. 2QQCh. 17.16 - Prob. 3QQCh. 17.17 - Prob. 1QQCh. 17.17 - Prob. 2QQCh. 17.17 - Prob. 3QQCh. 17.18 - Prob. 1QQCh. 17.18 - Prob. 2QQCh. 17.18 - Prob. 3QQCh. 17.19 - Prob. 1QQCh. 17.19 - Prob. 2QQCh. 17.19 - Prob. 3QQCh. 17.19 - Prob. 4QQCh. 17 - Prob. 17.1EPCh. 17 - Prob. 17.2EPCh. 17 - Prob. 17.3EPCh. 17 - Prob. 17.4EPCh. 17 - Prob. 17.5EPCh. 17 - Prob. 17.6EPCh. 17 - Indicate whether or not each of the following...Ch. 17 - Indicate whether or not each of the following...Ch. 17 - Prob. 17.9EPCh. 17 - Prob. 17.10EPCh. 17 - Prob. 17.11EPCh. 17 - Prob. 17.12EPCh. 17 - Prob. 17.13EPCh. 17 - Prob. 17.14EPCh. 17 - Prob. 17.15EPCh. 17 - Assign a common name to each of the following...Ch. 17 - Prob. 17.17EPCh. 17 - Prob. 17.18EPCh. 17 - Prob. 17.19EPCh. 17 - Prob. 17.20EPCh. 17 - Prob. 17.21EPCh. 17 - Prob. 17.22EPCh. 17 - Prob. 17.23EPCh. 17 - Prob. 17.24EPCh. 17 - Prob. 17.25EPCh. 17 - Prob. 17.26EPCh. 17 - Prob. 17.27EPCh. 17 - Prob. 17.28EPCh. 17 - Prob. 17.29EPCh. 17 - Prob. 17.30EPCh. 17 - Prob. 17.31EPCh. 17 - Prob. 17.32EPCh. 17 - Prob. 17.33EPCh. 17 - Prob. 17.34EPCh. 17 - Determine the maximum number of hydrogen bonds...Ch. 17 - Prob. 17.36EPCh. 17 - Prob. 17.37EPCh. 17 - Prob. 17.38EPCh. 17 - Prob. 17.39EPCh. 17 - Prob. 17.40EPCh. 17 - Prob. 17.41EPCh. 17 - Prob. 17.42EPCh. 17 - Prob. 17.43EPCh. 17 - Prob. 17.44EPCh. 17 - Prob. 17.45EPCh. 17 - Prob. 17.46EPCh. 17 - Prob. 17.47EPCh. 17 - Prob. 17.48EPCh. 17 - Prob. 17.49EPCh. 17 - Prob. 17.50EPCh. 17 - Prob. 17.51EPCh. 17 - Prob. 17.52EPCh. 17 - Prob. 17.53EPCh. 17 - Prob. 17.54EPCh. 17 - Prob. 17.55EPCh. 17 - Prob. 17.56EPCh. 17 - Prob. 17.57EPCh. 17 - Prob. 17.58EPCh. 17 - Prob. 17.59EPCh. 17 - Prob. 17.60EPCh. 17 - Prob. 17.61EPCh. 17 - Prob. 17.62EPCh. 17 - Prob. 17.63EPCh. 17 - Prob. 17.64EPCh. 17 - Prob. 17.65EPCh. 17 - Prob. 17.66EPCh. 17 - Prob. 17.67EPCh. 17 - Prob. 17.68EPCh. 17 - Prob. 17.69EPCh. 17 - Prob. 17.70EPCh. 17 - Prob. 17.71EPCh. 17 - Prob. 17.72EPCh. 17 - Prob. 17.73EPCh. 17 - Prob. 17.74EPCh. 17 - Prob. 17.75EPCh. 17 - Prob. 17.76EPCh. 17 - Prob. 17.77EPCh. 17 - Prob. 17.78EPCh. 17 - Prob. 17.79EPCh. 17 - Prob. 17.80EPCh. 17 - Prob. 17.81EPCh. 17 - Prob. 17.82EPCh. 17 - Prob. 17.83EPCh. 17 - Prob. 17.84EPCh. 17 - Prob. 17.85EPCh. 17 - Prob. 17.86EPCh. 17 - Prob. 17.87EPCh. 17 - Prob. 17.88EPCh. 17 - Prob. 17.89EPCh. 17 - Prob. 17.90EPCh. 17 - Prob. 17.91EPCh. 17 - Prob. 17.92EPCh. 17 - Prob. 17.93EPCh. 17 - Prob. 17.94EPCh. 17 - Prob. 17.95EPCh. 17 - Prob. 17.96EPCh. 17 - Prob. 17.97EPCh. 17 - Prob. 17.98EPCh. 17 - Indicate whether or not each of the following...Ch. 17 - Indicate whether or not each of the following...Ch. 17 - Classify each of the following amides as...Ch. 17 - Classify each of the following amides as...Ch. 17 - Classify each of the amides in Problem 17-101 as a...Ch. 17 - Prob. 17.104EPCh. 17 - Prob. 17.105EPCh. 17 - Prob. 17.106EPCh. 17 - Prob. 17.107EPCh. 17 - Prob. 17.108EPCh. 17 - Prob. 17.109EPCh. 17 - Prob. 17.110EPCh. 17 - Assign an IUPAC name to each of the following...Ch. 17 - Assign an IUPAC name to each of the following...Ch. 17 - Prob. 17.113EPCh. 17 - Prob. 17.114EPCh. 17 - Prob. 17.115EPCh. 17 - Prob. 17.116EPCh. 17 - Prob. 17.117EPCh. 17 - Prob. 17.118EPCh. 17 - Prob. 17.119EPCh. 17 - What is the relationship between the acronym DEET...Ch. 17 - Prob. 17.121EPCh. 17 - Prob. 17.122EPCh. 17 - Prob. 17.123EPCh. 17 - Prob. 17.124EPCh. 17 - Prob. 17.125EPCh. 17 - Prob. 17.126EPCh. 17 - Prob. 17.127EPCh. 17 - Prob. 17.128EPCh. 17 - Prob. 17.129EPCh. 17 - Prob. 17.130EPCh. 17 - Prob. 17.131EPCh. 17 - Prob. 17.132EPCh. 17 - Prob. 17.133EPCh. 17 - Prob. 17.134EPCh. 17 - Prob. 17.135EPCh. 17 - Prob. 17.136EPCh. 17 - Prob. 17.137EPCh. 17 - Prob. 17.138EPCh. 17 - Prob. 17.139EPCh. 17 - Prob. 17.140EPCh. 17 - Prob. 17.141EPCh. 17 - Prob. 17.142EPCh. 17 - Prob. 17.143EPCh. 17 - Prob. 17.144EPCh. 17 - Prob. 17.145EPCh. 17 - Prob. 17.146EPCh. 17 - Prob. 17.147EPCh. 17 - Prob. 17.148EPCh. 17 - Prob. 17.149EPCh. 17 - Prob. 17.150EPCh. 17 - Prob. 17.151EPCh. 17 - Prob. 17.152EPCh. 17 - Prob. 17.153EPCh. 17 - Prob. 17.154EP
Knowledge Booster
Background pattern image
Chemistry
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Similar questions
SEE MORE QUESTIONS
Recommended textbooks for you
Text book image
Organic And Biological Chemistry
Chemistry
ISBN:9781305081079
Author:STOKER, H. Stephen (howard Stephen)
Publisher:Cengage Learning,
Text book image
General, Organic, and Biological Chemistry
Chemistry
ISBN:9781285853918
Author:H. Stephen Stoker
Publisher:Cengage Learning
Text book image
Chemistry for Today: General, Organic, and Bioche...
Chemistry
ISBN:9781305960060
Author:Spencer L. Seager, Michael R. Slabaugh, Maren S. Hansen
Publisher:Cengage Learning
Text book image
Organic Chemistry
Chemistry
ISBN:9781305580350
Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote
Publisher:Cengage Learning
Nomenclature: Crash Course Chemistry #44; Author: CrashCourse;https://www.youtube.com/watch?v=U7wavimfNFE;License: Standard YouTube License, CC-BY