![Bundle: General, Organic, and Biological Chemistry, 7th + OWLv2 Quick Prep for General Chemistry, 4 terms (24 months) Printed Access Card](https://www.bartleby.com/isbn_cover_images/9781305717534/9781305717534_largeCoverImage.gif)
Concept explainers
(a)
Interpretation:
IUPAC name of the given compound has to be assigned.
Concept Introduction:
Amides are derivatives of
IUPAC rules for naming an amide:
- The end in name of the carboxylic acid is changed from “-ic acid” or “-oic acid” to “-amide”.
- The groups attached to the nitrogen are appended to front of base name by using N-prefix as locator.
For amides, IUPAC name and common names are given using the same rules.
(b)
Interpretation:
IUPAC name of the given compound has to be assigned.
Concept Introduction:
- Longest carbon chain has to be identified that is attached to nitrogen atom.
- Suffix “-e” in name of the parent chain
alkane is replaced by “-amine”. - Numbering of the carbon chain is done from the end that is near the nitrogen atom.
- Point of attachment of the nitrogen atom in the carbon chain is indicated by a number before the parent chain name.
- In case if substituents are present, then the identity and location of substituents are appended to the front in the parent chain name.
If the compound contains two amine groups, then the suffix “-e” is replaced by diamine. Tertiary and secondary
Common name for amine is given in a single word. Primary amine is named as alkylamine. Secondary amine is named as alkylalkylamine. Tertiary amine is named as alkylalkylalkylamine.
In a line-angle structural formula, the point of intersection and the end points represent a carbon atom.
(c)
Interpretation:
IUPAC name of the given compound has to be assigned.
Concept Introduction:
IUPAC nomenclature for amine: There are about five rules to be followed in giving IUPAC name for an amine.
- Longest carbon chain has to be identified that is attached to nitrogen atom.
- Suffix “-e” in name of the parent chain alkane is replaced by “-amine”.
- Numbering of the carbon chain is done from the end that is near the nitrogen atom.
- Point of attachment of the nitrogen atom in the carbon chain is indicated by a number before the parent chain name.
- In case if substituents are present, then the identity and location of substituents are appended to the front in the parent chain name.
If the compound contains two amine groups, then the suffix “-e” is replaced by diamine. Tertiary and secondary amines are named as N-substituted primary amines.
Common name for amine is given in a single word. Primary amine is named as alkylamine. Secondary amine is named as alkylalkylamine. Tertiary amine is named as alkylalkylalkylamine.
In a line-angle structural formula, the point of intersection and the end points represent a carbon atom.
(d)
Interpretation:
IUPAC name of the given compound has to be assigned.
Concept Introduction:
IUPAC nomenclature for amine: There are about five rules to be followed in giving IUPAC name for an amine.
- Longest carbon chain has to be identified that is attached to nitrogen atom.
- Suffix “-e” in name of the parent chain alkane is replaced by “-amine”.
- Numbering of the carbon chain is done from the end that is near the nitrogen atom.
- Point of attachment of the nitrogen atom in the carbon chain is indicated by a number before the parent chain name.
- In case if substituents are present, then the identity and location of substituents are appended to the front in the parent chain name.
If the compound contains two amine groups, then the suffix “-e” is replaced by diamine. Tertiary and secondary amines are named as N-substituted primary amines.
Common name for amine is given in a single word. Primary amine is named as alkylamine. Secondary amine is named as alkylalkylamine. Tertiary amine is named as alkylalkylalkylamine.
In a line-angle structural formula, the point of intersection and the end points represent a carbon atom.
![Check Mark](/static/check-mark.png)
Want to see the full answer?
Check out a sample textbook solution![Blurred answer](/static/blurred-answer.jpg)
Chapter 17 Solutions
Bundle: General, Organic, and Biological Chemistry, 7th + OWLv2 Quick Prep for General Chemistry, 4 terms (24 months) Printed Access Card
- Part I. Problem solving. Include all necessary calculations 13 provide plots and graphs. Complexation wl diphenyl carbazide (OPC) in acidic media is another type of sensitive photometric method used for the analysis of aqueous. hexavalent chromium. At 540nm the cherry-red complex as a result of DPC reaction w/ chromium can be photometrically measured. at this wavelength. - a 25mL The UV-vis analysis for the determination of nexavalent chromium in ground water sample is given below. The experiment was based on external calibration method w/ each measurement sample prepared are as follows lab sample analysis contained the standard 100 ppb croy cor groundwater sample, volumes used as indicated below), 12.50 mL of 0.02 M H2Soy and 5.50 ml of 100 ppm DPC (wi water to adjust final volume to 25-ml). The main stripping method was square wave voltammetry, following the conditions set in the main ASV experiment. Standard 100 Volumetric Groundwater H2SO4 0.20 M, flask Sample, mL ppb CrO4*, 100…arrow_forwardplease helparrow_forwardPredict the products of the following reactions. Draw mechanism arrows for each step for a, b, and c. a.) HBr b.) HI H₂O H2SO4 d.) C12 HO H2SO4 1.) BH3 2.) H2O2, NaOHarrow_forward
- K for the following reaction is 0.11 at constant temperature. If the equilibrium concentration of HCl is 0.5 M, what is the equilibrium concentration of NH3. NH4CI(s) ⇌ NH3(g) + HCI(g)arrow_forwardplease help by Draw the following structures (Lewis or line-angle drawing).arrow_forwardplease helparrow_forward
- Consider the reaction: 2 A (aq) ⇌ B(aq) Given the following KC values and starting with the initial concentration of A = 4.00 M, complete ICE diagram(s)and find the equilibrium concentrations for A and B.A) KC = 4.00B) KC = 200C) KC = 8.00 x10-3arrow_forward5) Consider the reaction: Cl2 (g) + F2 (g) ⟷ 2 ClF (g) KP=? The partial pressure of 203 kPa for Cl2 and a partial pressure of 405 kPa for F2. Upon reaching equilibrium, thepartial pressure of ClF is 180 kPa. Calculate the equilibrium concentrations and then find the value for KP.arrow_forwardDon't used hand raiting and don't used Ai solutionarrow_forward
- (9 Pts) In one of the two Rare Earth element rows of the periodic table, identify an exception tothe general ionization energy (IE) trend. For the two elements involved, answer the followingquestions. Be sure to cite sources for all physical data that you use.a. (2 pts) Identify the two elements and write their electronic configurations.b. (2 pts) Based on their configurations, propose a reason for the IE trend exception.c. (5 pts) Calculate effective nuclear charges for the last electron in each element and theAllred-Rochow electronegativity values for the two elements. Can any of these valuesexplain the IE trend exception? Explain how (not) – include a description of how IErelates to electronegativity.arrow_forwardDon't used hand raiting and don't used Ai solutionarrow_forwardDon't use AIarrow_forward
- General, Organic, and Biological ChemistryChemistryISBN:9781285853918Author:H. Stephen StokerPublisher:Cengage LearningOrganic And Biological ChemistryChemistryISBN:9781305081079Author:STOKER, H. Stephen (howard Stephen)Publisher:Cengage Learning,
![Text book image](https://www.bartleby.com/isbn_cover_images/9781285853918/9781285853918_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9781305081079/9781305081079_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9781305080485/9781305080485_smallCoverImage.gif)