(a)
Interpretation:
The terms that apply for
Concept Introduction:
Free
(b)
Interpretation:
The terms that apply for
Concept Introduction:
Free amine is the one that has nitrogen atom bonded to three other atoms and a lone pair of electrons is present on it. Deprotonated base is the one that can accept a hydrogen ion. Due to the lone pair of electrons present on the nitrogen atom in amine, it can also be known as deprotonated base. Free base is the one that has a more electronegative atom which can act as a proton acceptor. Amine has a nitrogen atom which can accept a hydrogen ion. Hence, amine can be a proton acceptor. Protonated base is the one in which the nitrogen atom in the amine has four bonds. The fourth bond formed is a coordinate covalent bond. The formed species has a positive charge on it.
(c)
Interpretation:
The terms that apply for
Concept Introduction:
Free amine is the one that has nitrogen atom bonded to three other atoms and a lone pair of electrons is present on it. Deprotonated base is the one that can accept a hydrogen ion. Due to the lone pair of electrons present on the nitrogen atom in amine, it can also be known as deprotonated base. Free base is the one that has a more electronegative atom which can act as a proton acceptor. Amine has a nitrogen atom which can accept a hydrogen ion. Hence, amine can be a proton acceptor. Protonated base is the one in which the nitrogen atom in the amine has four bonds. The fourth bond formed is a coordinate covalent bond. The formed species has a positive charge on it.
(d)
Interpretation:
The terms that apply for
Concept Introduction:
Free amine is the one that has nitrogen atom bonded to three other atoms and a lone pair of electrons is present on it. Deprotonated base is the one that can accept a hydrogen ion. Due to the lone pair of electrons present on the nitrogen atom in amine, it can also be known as deprotonated base. Free base is the one that has a more electronegative atom which can act as a proton acceptor. Amine has a nitrogen atom which can accept a hydrogen ion. Hence, amine can be a proton acceptor. Protonated base is the one in which the nitrogen atom in the amine has four bonds. The fourth bond formed is a coordinate covalent bond. The formed species has a positive charge on it.
Want to see the full answer?
Check out a sample textbook solution
Chapter 17 Solutions
Bundle: General, Organic, and Biological Chemistry, 7th + OWLv2 Quick Prep for General Chemistry, 4 terms (24 months) Printed Access Card
- refer to the picture below and select two correct statement.arrow_forwardChoose from the following pairs. Which are constitutional isomers? Pair A Br Br and CH3 CH3 Pair B CH3 CH3 H. C1 H. and `H H H. H. Ci A both pair A and B B neither A nor B A D Вarrow_forward1. Choose the formula for threonine: a) CH₂ -CH-COOH OH NH₂ b) CH3 -CH-CH-COOH OH NH₂arrow_forward
- Η Η Η Η Η ΤΙΤΤΤ H-C-C-C-CC-G I | | | | Η Η Η Η Η | OH What class of organic compound does this belong to? A) Aldehyde Β Ketone Carboxylic acid Alcohol ά Ὁ Ηarrow_forward1. Label the "C" monosaccharide 2. Draw the open chain Fischer projection formula of the monosaccharide labeled “B”? Describe it as having ether the d- or l- orientationarrow_forwardFor the following reaction at equilibrium NH3 + H20 + NH4+1 + Он-1 NH3 is the It is not a hydroxide and so is a base. H20 is the It is both a very acid and a very base. NH4*1 is the It is not on the list of strong acids and so is a acid. OH-1 is the . It is a base because it contains hydroxide. а. acid b. base c. conjugate acid d. conjugate base e. strong f. moderately strong or weak g. weakarrow_forward
- A (-) charge in the transition state can be stabilized by a catalyst, which is usually a(n): a. Anion b. Base Oc. Nucleophile Od. Acidarrow_forwardWhich of the following organic compound doesnot dissolve in water? glycerol propane propanoic acid propanol H H-C Н Н H-с-с-с Н- OH HICIH H-C c-c 1 Н OH H -+ Н HICIH H Н H H C C H H OH 5-о-т OH -C-H -H OHarrow_forwardIdentify the Lewis acid in the following reaction: A. BF3 B. F C. BF4 D. None of these is an acid. B OD O A O Carrow_forward
- 3). reactions of the following alkyl iodide. Danny uses potassium tert-butoxide to promote the reaction while Claire uses water and high temperatures. One of their reactions has provided a single elimination isomer while the other has provided a mixture of elimination isomers. Organic chemistry students Danny and Claire are both performing elimination Me H20, heat Danny's Reaction Claire's Reaction H. Me a) Which student's reaction (Danny or Claire) has provided a single elimination isomer? b) Draw all the elimination isomers obtained from both students' reactions. c) Which of the dienes drawn (by you) in question 3b is the most stable? Circle that diene above.arrow_forwardIV. Draw the Fischer projection formula for the enantiomer of each of the following monosaccharides.arrow_forward1. which IR stretches and bends indicate what type of functional group we have (alcohol, carboxylic acid, ester), 2. how you can then use IR to monitor the change from the starting materials to the products. 3. indicate and discussion the absorptions that are relevant to alcohol OH and C-O, carboxylic acid OH, carboxylic acid C=O, ester C=O, and C-O). the picture below is an ir spectra of ethanolarrow_forward
Biology 2eBiologyISBN:9781947172517Author:Matthew Douglas, Jung Choi, Mary Ann ClarkPublisher:OpenStax
Biology (MindTap Course List)BiologyISBN:9781337392938Author:Eldra Solomon, Charles Martin, Diana W. Martin, Linda R. BergPublisher:Cengage Learning