Concept explainers
(a)
Interpretation:
Physical state at room temperature for unbranched saturated monocarboxylic acid that contains three carbon atoms has to be indicated.
Concept Introduction:
Physical property of
(b)
Interpretation:
Physical state at room temperature for unbranched saturated dicarboxylic acid that contains three carbon atoms has to be indicated.
Concept Introduction:
Physical property of carboxylic acid is decided by the carbon chain and the functional group. Carboxylic acids are highly polar, as the carboxyl group is more polar. Due to this polar nature, the melting and boiling point are very high. Monocarboxylic acids that are unsubstituted which contains up to nine carbon atoms are present in liquid state. They have very sharp odor. Monocarboxylic acids that have more than ten carbon atoms in an unbranched fashion are waxy solids. They do not have any odor because of low volatility. Similar to this, dicarboxylic acids and aromatic carboxylic acids do not have any odor and they are solids.
(c)
Interpretation:
Physical state at room temperature for unbranched saturated monocarboxylic acid that contains six carbon atoms has to be indicated.
Concept Introduction:
Physical property of carboxylic acid is decided by the carbon chain and the functional group. Carboxylic acids are highly polar, as the carboxyl group is more polar. Due to this polar nature, the melting and boiling point are very high. Monocarboxylic acids that are unsubstituted which contains up to nine carbon atoms are present in liquid state. They have very sharp odor. Monocarboxylic acids that have more than ten carbon atoms in an unbranched fashion are waxy solids. They do not have any odor because of low volatility. Similar to this, dicarboxylic acids and aromatic carboxylic acids do not have any odor and they are solids.
(d)
Interpretation:
Physical state at room temperature for unbranched saturated dicarboxylic acid that contains five carbon atoms has to be indicated.
Concept Introduction:
Physical property of carboxylic acid is decided by the carbon chain and the functional group. Carboxylic acids are highly polar, as the carboxyl group is more polar. Due to this polar nature, the melting and boiling point are very high. Monocarboxylic acids that are unsubstituted which contains up to nine carbon atoms are present in liquid state. They have very sharp odor. Monocarboxylic acids that have more than ten carbon atoms in an unbranched fashion are waxy solids. They do not have any odor because of low volatility. Similar to this, dicarboxylic acids and aromatic carboxylic acids do not have any odor and they are solids.
Want to see the full answer?
Check out a sample textbook solutionChapter 16 Solutions
GENERAL,ORGANIC,+BIO.CHEM.-MINDTAP
- Rel. Intensity Q 1. Which one of the following is true of the compound whose mass spectrum is shown here? Explain how you decided. 100 a) It contains chlorine. b) It contains bromine. c) It contains neither chlorine nor bromine. 80- 60- 40- 20- 0.0 0.0 TT 40 80 120 160 m/z 2. Using the Table of IR Absorptions how could you distinguish between these two compounds in the IR? What absorbance would one compound have that the other compound does not? HO CIarrow_forwardIllustrate reaction mechanisms of alkenes with water in the presence of H2SO4, detailing each step of the process. Please show steps of processing. Please do both, I will thumb up for sure #1 #3arrow_forwardDraw the following molecule: (Z)-1-chloro-1-butenearrow_forward
- Identify the molecule as having a(n) E, Z, cis, or trans configuration. CH3 H₁₂C ○ E ○ z ○ cis transarrow_forwardIdentify the molecule as having a(n) E, Z, cis, or trans configuration. H₂C- CH3 О Е ○ cis ○ transarrow_forwardThe decomposition of dinitrogen pentoxide according to the equation: 50°C 2 N2O5(g) 4 NO2(g) + O2(g) follows first-order kinetics with a rate constant of 0.0065 s-1. If the initial concentration of N2O5 is 0.275 M, determine: the final concentration of N2O5 after 180 seconds. ...arrow_forward
- Don't used hand raitingarrow_forwardCS2(g) →CS(g) + S(g) The rate law is Rate = k[CS2] where k = 1.6 × 10−6 s−¹. S What is the concentration of CS2 after 5 hours if the initial concentration is 0.25 M?arrow_forwardCS2(g) → CS(g) + S(g) The rate law is Rate = k [CS2] where k = 1.6 × 10-6 s−1. S Calculate the half-life.arrow_forward
- The following is a first order reaction where the rate constant, k, is 6.29 x 10-3 min-*** What is the half-life? C2H4 C2H2 + H2arrow_forwardControl Chart Drawing Assignment The table below provides the number of alignment errors observed during the final inspection of a certain model of airplane. Calculate the central, upper, and lower control limits for the c-chart and draw the chart precisely on the graph sheet provided (based on 3-sigma limits). Your chart should include a line for each of the control limits (UCL, CL, and LCL) and the points for each observation. Number the x-axis 1 through 25 and evenly space the numbering for the y-axis. Connect the points by drawing a line as well. Label each line drawn. Airplane Number Number of alignment errors 201 7 202 6 203 6 204 7 205 4 206 7 207 8 208 12 209 9 210 9 211 8 212 5 213 5 214 9 215 8 216 15 217 6 218 4 219 13 220 7 221 8 222 15 223 6 224 6 225 10arrow_forwardCollagen is used to date artifacts. It has a rate constant = 1.20 x 10-4 /years. What is the half life of collagen?arrow_forward
- World of Chemistry, 3rd editionChemistryISBN:9781133109655Author:Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCostePublisher:Brooks / Cole / Cengage LearningOrganic And Biological ChemistryChemistryISBN:9781305081079Author:STOKER, H. Stephen (howard Stephen)Publisher:Cengage Learning,General, Organic, and Biological ChemistryChemistryISBN:9781285853918Author:H. Stephen StokerPublisher:Cengage Learning
- Chemistry for Today: General, Organic, and Bioche...ChemistryISBN:9781305960060Author:Spencer L. Seager, Michael R. Slabaugh, Maren S. HansenPublisher:Cengage Learning