EBK ORGANIC CHEMISTRY
8th Edition
ISBN: 8220102744127
Author: Bruice
Publisher: PEARSON
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Textbook Question
Chapter 15.8, Problem 24P
Show the mechanism for the acid-catalyzed formation of 23c starting with the product from its hydrolysis.
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LABORATORY REPORT FORM
Part I. Determination of the Formula of a Known Hydrate
1. Mass of empty evaporating dish
3. Mass of hydrate
Using subtraction
or mass by difference,
find the mass of
the hydrate
76.96
-75.40
75.40g
76.968
1.568
01.56
76.90 g
2. Mass of evaporating dish + hydrate
4. Mass of evaporating dish + hydrate (after heating)
First 76.98 g
Third 76.66g
Second
Fourth (if necessary) 76.60g
5. Mass of anhydrate
6. Mass of water lost by the hydrate
7. Percent of water of hydration
(Show Calculations)
8. Moles of water
(Show Calculations)
mol
mass of water
=
MM of water (g/m)
9. Moles of anhydrate
(Show Calculations)
10. Ratio of moles of water to moles of anhydrate
11 F(Show Calculations)
11. Formula of hydrate
- Mass of water (g) x 100
% water hydration
g
g
%
Mass of hydrate (9) x IC
% = (Mass of hydrate- mass of an)
mass of hydrate (g)
% = (1.569-
× 100=
mol
1.569
mol Mol Mass of
anhydrate/MM
of anhydrate
12. What was the color of the hydrate?
blue
What was the color of the…
compared t-critical with t-calculated and 95% confidence interval to answer this question
Comparing two means. Horvat and co-workers used atomic absorption spectroscopy to determine the concentration of Hg in coal fly ash. Of particular interest to the authors was developing an appropriate procedure for digesting samples and releasing the Hg for analysis. As part of their study they tested several reagents for digesting samples. Their results using HNO3 and using a 1+3 mixture of HNO3 and HCl are shown here. All concentrations are given as ppb Hg sample.
HNO3: 161, 165, 160, 167, 166
1+3 HNO3–HCl: 159, 145, 140, 147, 143, 156
Determine whether there is a significant difference between these methods at the 95% confidence interval.
Chapter 15 Solutions
EBK ORGANIC CHEMISTRY
Ch. 15.1 - The aromas of many flowers and fruits are due to...Ch. 15.1 - Name the following:Ch. 15.1 - Prob. 3PCh. 15.2 - Which is longer, the carbon-oxygen single bond in...Ch. 15.2 - There are three carbon-oxygen bonds in methyl...Ch. 15.2 - Prob. 6PCh. 15.4 - a. What is the product of the reaction of acetyl...Ch. 15.4 - What is the product of an acyl substitution...Ch. 15.5 - a. Which compound has the stretching vibration for...Ch. 15.5 - Using the pKa values listed in Table 15.1, predict...
Ch. 15.5 - Is the following statement true or false? If the...Ch. 15.6 - Starting with acetyl chloride, what neutral...Ch. 15.6 - Prob. 13PCh. 15.7 - Starting with methyl acetate, what neutral...Ch. 15.7 - We saw that it is necessary to use excess amine in...Ch. 15.7 - Prob. 17PCh. 15.7 - Which ester hydrolyzes more rapidly? a. methyl...Ch. 15.7 - a. state three factors that cause the uncatalyzed...Ch. 15.8 - Prob. 21PCh. 15.8 - Using the mechanism for the acid-catalyzed...Ch. 15.8 - Prob. 23PCh. 15.8 - Show the mechanism for the acid-catalyzed...Ch. 15.8 - Prob. 25PCh. 15.8 - Write the mechanism for the acid-catalyzed...Ch. 15.8 - Write the mechanism for the acid-catalyzed...Ch. 15.9 - Prob. 28PCh. 15.9 - Prob. 29PCh. 15.10 - Show how each of the following esters could he...Ch. 15.10 - Prob. 32PCh. 15.11 - Prob. 33PCh. 15.11 - Which of the following reactions leads to the...Ch. 15.12 - Prob. 35PCh. 15.12 - Prob. 36PCh. 15.13 - Prob. 37PCh. 15.14 - Prob. 38PCh. 15.14 - Prob. 39PCh. 15.15 - Prob. 40PCh. 15.15 - Which alkyl halides from the carboxylic acids...Ch. 15.16 - Prob. 43PCh. 15.16 - Prob. 44PCh. 15.16 - Prob. 45PCh. 15.17 - Prob. 46PCh. 15.18 - How could you synthesize the following compounds...Ch. 15 - Prob. 48PCh. 15 - Name the following:Ch. 15 - Prob. 50PCh. 15 - What compound are obtained from the fallowing...Ch. 15 - a. Rank the following esters in order of...Ch. 15 - Because bromocyclohexane is a secondary alkyl...Ch. 15 - a. Which compound would you expect to have a...Ch. 15 - How could you use 1H NMR spectroscopy to...Ch. 15 - Rank the following compounds in order of...Ch. 15 - Prob. 57PCh. 15 - Prob. 58PCh. 15 - Prob. 59PCh. 15 - A compound with molecular formula C5H10O2 gives...Ch. 15 - Prob. 61PCh. 15 - Prob. 62PCh. 15 - Prob. 63PCh. 15 - Prob. 64PCh. 15 - Prob. 65PCh. 15 - Prob. 66PCh. 15 - Two products, A and B, are obtained from the...Ch. 15 - Prob. 68PCh. 15 - Prob. 69PCh. 15 - Prob. 70PCh. 15 - Prob. 71PCh. 15 - Prob. 72PCh. 15 - When treated with an equivalent of methanol,...Ch. 15 - a. Identify the two products obtained from the...Ch. 15 - Prob. 75PCh. 15 - Prob. 76PCh. 15 - a. When a carboxylic acid is dissolved in...Ch. 15 - Prob. 78PCh. 15 - Identity the major and minor products of the...Ch. 15 - When a compound with molecular formula C11H14O2...Ch. 15 - Prob. 81PCh. 15 - Prob. 82PCh. 15 - Prob. 83PCh. 15 - The 1H NMR spectra for two esters with molecular...Ch. 15 - Show how the following compounds could be prepared...Ch. 15 - Prob. 86PCh. 15 - Prob. 87PCh. 15 - The intermediate shown here is formed during the...Ch. 15 - Prob. 89PCh. 15 - Propose a mechanism that accounts for the...Ch. 15 - Catalytic antibodies catalyze a reaction by...Ch. 15 - Prob. 92P
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- Comparison of experimental data to “known” value. Monna and co-workers used radioactive isotopes to date sediments from lakes and estuaries.21 To verify this method they analyzed a 208Po standard known to have an activity of 77.5 decays/min, obtaining the following results. 77.09, 75.37, 72.42, 76.84, 77.84, 76.69, 78.03, 74.96, 77.54, 76.09, 81.12, 75.75 Do the results differ from the expected results at the 95% confidence interval?arrow_forwardExplain the difference between the propagated uncertainty and the standard deviation. Which number would you use to describe the uncertainty in the measurement? if the standard deviation is 0.01 and the propagated uncertainty is 0.03arrow_forwardPropagation of uncertainty. Find the absolute and percent relative uncertainty assuming the ±-values are random error. 7.65±0.04 + 5.28±0.02 – 1.12±0.01 85.6±0.9 × 50.2±0.7 ÷ 13.8±0.5 [4.88±0.07 + 3.22±0.05] / 1.53±0.02arrow_forward
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