The K sp value for Cu ( OH ) 2 and the overall formation constant for Cu ( NH 3 ) 4 2+ is given. The questions based on the stated data are to be answered. Concept introduction: The equilibrium constant for a given reaction is calculated by the formula, Equilibrium constant = K sp ⋅ K f At equilibrium, the equilibrium constant expression is expressed by the formula, K = Concentration of products Concentration of reactants
The K sp value for Cu ( OH ) 2 and the overall formation constant for Cu ( NH 3 ) 4 2+ is given. The questions based on the stated data are to be answered. Concept introduction: The equilibrium constant for a given reaction is calculated by the formula, Equilibrium constant = K sp ⋅ K f At equilibrium, the equilibrium constant expression is expressed by the formula, K = Concentration of products Concentration of reactants
Solution Summary: The author explains that the equilibrium constant for a given reaction is calculated by the formula, K_spcdot
Interpretation: The
Ksp value for
Cu(OH)2 and the overall formation constant for
Cu(NH3)42+ is given. The questions based on the stated data are to be answered.
Concept introduction: The equilibrium constant for a given reaction is calculated by the formula,
Equilibriumconstant=Ksp⋅Kf
At equilibrium, the equilibrium constant expression is expressed by the formula,
K=ConcentrationofproductsConcentrationofreactants
(b)
Interpretation Introduction
Interpretation: The
Ksp value for
Cu(OH)2 and the overall formation constant for
Cu(NH3)42+ is given. The questions based on the stated data are to be answered.
Concept introduction: The equilibrium constant for a given reaction is calculated by the formula,
Equilibriumconstant=Ksp⋅Kf
At equilibrium, the equilibrium constant expression is expressed by the formula,
Calculate the solubility at 25 °C of AgBr in pure water and in 0.34 M NaCN. You'll probably find some useful data in the ALEKS Data resource.
Round your answer to 2 significant digits.
Solubility in pure water:
Solubility in 0.34 M NaCN:
7.31 × 10
M
x10
Ом
Differentiate between normal spinels and inverse spinels.
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