A solution contains 0.018 mole each of I − , Br − , and Cl − . When the solution is mixed with 200. mL of 0.24 M AgNO 3 , what mass of AgCl( s ) precipitates out, and what is [Ag + ]? Assume no volume change. AgI: K sp = 1.5 × 10 − 16 AgBr: K sp = 5.0 × 10 − 13 AgCl: K sp = 1.6 × 10 − 10
A solution contains 0.018 mole each of I − , Br − , and Cl − . When the solution is mixed with 200. mL of 0.24 M AgNO 3 , what mass of AgCl( s ) precipitates out, and what is [Ag + ]? Assume no volume change. AgI: K sp = 1.5 × 10 − 16 AgBr: K sp = 5.0 × 10 − 13 AgCl: K sp = 1.6 × 10 − 10
Solution Summary: The author calculates the mass of AgCl(s) that precipitates out, when the given solution is mixed with
A solution contains 0.018 mole each of I−, Br−, and Cl−. When the solution is mixed with 200. mL of 0.24 M AgNO3, what mass of AgCl(s) precipitates out, and what is [Ag+]? Assume no volume change.
AgI:
K
sp
=
1.5
×
10
−
16
AgBr:
K
sp
=
5.0
×
10
−
13
AgCl:
K
sp
=
1.6
×
10
−
10
In the electrode Pt, H2(1 atm) | H+(a=1), if the electrode balance potential is -0.118 V and the interface potential difference is +5 mV. The current voltage will be 0.005 - (-0.118) = 0.123 V ¿Correcto?
In the electrode Pt, H2(1 atm) | H+(a=1) at 298K is 0.79 mA cm-2. If the balance potential of the electrode is -0.118 V and the potential difference of the interface is +5 mV. Determine its potential.
In one electrode: Pt, H2(1 atm) | H+(a=1), the interchange current density at 298K is 0.79 mA·cm-2. If the voltage difference of the interface is +5 mV. What will be the correct intensity at pH = 2?. Maximum transfer voltage and beta = 0.5.
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Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell