The reason of non-formation of precipitate when 5 M ammonia is added to the solution of Cu ( OH ) 2 but there occurs formation of precipitate of Cu ( OH ) 2 when 5 M HNO 3 is added and the effect of ability of a cation to form a complex ion over the solubility of complex ion is to be stated. Concept introduction: The formation of precipitate occurs when there occurs the reaction between the cations and anions present in the solution. It is determined by using the rules of solubility of ionic compounds.

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Answer 1

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Chapter 15, Problem 9RQ

Interpretation Introduction

Interpretation: The reason of non-formation of precipitate when 5 M ammonia is added to the solution of Cu(OH)2 but there occurs formation of precipitate of Cu(OH)2 when 5 M HNO3 is added and the effect of ability of a cation to form a complex ion over the solubility of complex ion is to be stated.

Concept introduction: The formation of precipitate occurs when there occurs the reaction between the cations and anions present in the solution. It is determined by using the rules of solubility of ionic compounds.

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Answer 2

Question

Chapter 15, Problem 9RQ

Interpretation Introduction

Interpretation: The reason of non-formation of precipitate when 5 M ammonia is added to the solution of Cu(OH)2 but there occurs formation of precipitate of Cu(OH)2 when 5 M HNO3 is added and the effect of ability of a cation to form a complex ion over the solubility of complex ion is to be stated.

Concept introduction: The formation of precipitate occurs when there occurs the reaction between the cations and anions present in the solution. It is determined by using the rules of solubility of ionic compounds.

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Answer 3

Question

Chapter 15, Problem 9RQ

Interpretation Introduction

Interpretation: The reason of non-formation of precipitate when 5 M ammonia is added to the solution of Cu(OH)2 but there occurs formation of precipitate of Cu(OH)2 when 5 M HNO3 is added and the effect of ability of a cation to form a complex ion over the solubility of complex ion is to be stated.

Concept introduction: The formation of precipitate occurs when there occurs the reaction between the cations and anions present in the solution. It is determined by using the rules of solubility of ionic compounds.

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Answer 4

Question

Chapter 15, Problem 9RQ

Interpretation Introduction

Interpretation: The reason of non-formation of precipitate when 5 M ammonia is added to the solution of Cu(OH)2 but there occurs formation of precipitate of Cu(OH)2 when 5 M HNO3 is added and the effect of ability of a cation to form a complex ion over the solubility of complex ion is to be stated.

Concept introduction: The formation of precipitate occurs when there occurs the reaction between the cations and anions present in the solution. It is determined by using the rules of solubility of ionic compounds.

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Answer 5

Chapter 15, Problem 9RQ

Interpretation Introduction

Interpretation: The reason of non-formation of precipitate when 5 M ammonia is added to the solution of Cu(OH)2 but there occurs formation of precipitate of Cu(OH)2 when 5 M HNO3 is added and the effect of ability of a cation to form a complex ion over the solubility of complex ion is to be stated.

Concept introduction: The formation of precipitate occurs when there occurs the reaction between the cations and anions present in the solution. It is determined by using the rules of solubility of ionic compounds.

Answer 6

Chapter 15, Problem 9RQ

Interpretation Introduction

Interpretation: The reason of non-formation of precipitate when 5 M ammonia is added to the solution of Cu(OH)2 but there occurs formation of precipitate of Cu(OH)2 when 5 M HNO3 is added and the effect of ability of a cation to form a complex ion over the solubility of complex ion is to be stated.

Concept introduction: The formation of precipitate occurs when there occurs the reaction between the cations and anions present in the solution. It is determined by using the rules of solubility of ionic compounds.

Answer 7

Chapter 15, Problem 9RQ

Interpretation Introduction

Interpretation: The reason of non-formation of precipitate when 5 M ammonia is added to the solution of Cu(OH)2 but there occurs formation of precipitate of Cu(OH)2 when 5 M HNO3 is added and the effect of ability of a cation to form a complex ion over the solubility of complex ion is to be stated.

Concept introduction: The formation of precipitate occurs when there occurs the reaction between the cations and anions present in the solution. It is determined by using the rules of solubility of ionic compounds.

Answer 8

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Answer 9

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Answer 11

Ch. 15 - To what reaction does the solubility product...Ch. 15 - Prob. 2RQ Ch. 15 - Prob. 3RQ Ch. 15 - Prob. 4RQ Ch. 15 - Prob. 5RQ Ch. 15 - Prob. 6RQ Ch. 15 - Prob. 7RQ Ch. 15 - Prob. 8RQ Ch. 15 - Prob. 9RQ Ch. 15 - Prob. 10RQ

Solution Summary: The author explains that the formation of precipitate occurs when there occurs the reaction between the cations and anions present in the solution.

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