Explanation Given data: The mass of aluminum is 150 g . The mass of water is 250 g . The initial temperature of water and aluminum is 20 o C . The mass of the metal block is 200 g . The initial temperature of the iron block is 60 ° C . The final temperature is 22.8 ° C . Formula used: Write the equation for the change in thermal energy of water. Δ U w a t e r = c w a t e r m w a t e r ( T f − T w a t e r , i ) Here, Δ U water is the change in thermal energy of the water, c w a t e r is the specific heat of water, m w a t e r is the mass of the water, T f is the final temperature of water, and T w a t e r , i is the initial temperature of water. Write the equation for the change in thermal energy of aluminum. Δ U A l = c A l m A l ( T f − T A l , i ) Here, Δ U Al is the change in thermal energy of aluminum, c A l is the specific heat of aluminum, m A l is the mass of aluminum, T f is the final temperature of aluminum, and T A l , i is the initial temperature of aluminum. Write the equation for the change in thermal energy of the metal. Δ U x = c x m x ( T f − T x , i ) Here, Δ U x is the change in the thermal energy of the metal, c x is the specific heat of the metal, m F e is the mass of the metal, T f is the final temperature of the metal, and T F e , i is the initial temperature of the metal. Explanation: Consider the metal block be x and specific heat of water to be 4180 J/kg ⋅ ° C , the specific heat of aluminum to be 900 J/kg ⋅ ° C and specific heat of the iron to be 450 J/kg . ° C . When a metal block at 60 ° C is added to the cold water in the aluminum container, heat transfer takes place due to the temperature difference between the bodies. Conduction is the mode of heat transfer dominant in this case. The energy transfer takes place until all the bodies reach a common final temperature T f . The initial temperature of water and the aluminum container is lower than the initial temperature of the metal block. Assume that all the energy loss from the hot metal is gained by the cold water and aluminum container and there is no loss of energy to the surroundings. Therefore, the decrease in the thermal energy of the metal is equal to the increase in the thermal energy of the water and container, when the metal block is added to the water. Δ U w a t e r + Δ U A l + Δ U x = 0 Here, Δ U water is the change in thermal energy of the water, Δ U Al is the change in thermal energy of the aluminum and Δ U x is the change in thermal energy of the metal x . Substitute c w a t e r m w a t e r ( T f − T w a t e r , i ) for Δ U w a t e r , c A l m A l ( T f − T A l , i ) for Δ U A l , and c x m x ( T f − T x , i ) for Δ U x

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ISBN: 9780134601823

Author: ETKINA, Eugenia, Planinšič, G. (gorazd), Van Heuvelen, Alan

Publisher: Pearson,

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Calorimetry

Measuring the heat transferred during chemical reactions or other physical processes is known as calorimetry. It comes under the branch of thermochemistry.

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Chapter 15, Problem 28P

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The type of metal block of mass 200 g when it is added at 60 °C to a 150 g of insulated aluminum container holding 250 g of water, initially at 20 °C, resulting in a final temperature of 22.8 °C. Also, indicate the assumptions used.

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Chapter 15, Problem 27P

Chapter 15, Problem 29P

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The type of metal block of mass 200 g when it is added at 60 ° C to a 150 g of insulated aluminum container holding 250 g of water, initially at 20 ° C , resulting in a final temperature of 22.8 ° C . Also, indicate the assumptions used.

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The type of metal block of mass 200 g when it is added at 60 °C to a 150 g of insulated aluminum container holding 250 g of water, initially at 20 °C, resulting in a final temperature of 22.8 °C. Also, indicate the assumptions used.

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