Microelectronics: Circuit Analysis and Design
4th Edition
ISBN: 9780073380643
Author: Donald A. Neamen
Publisher: McGraw-Hill Companies, The
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Chapter 15, Problem 15.26P
Consider the phase shift oscillator in Figure 15.16. (a) Determine the frequency of oscillation for
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In a Wien bridge oscillator circuit, resistor and capacitor form a series branch and a parallel branch. The value of the resistor is 200 ohm and the value of the capacitor is 10 mF. Determine the frequency of oscillation for the Wien Bridge oscillator circuit.
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Chapter 15 Solutions
Microelectronics: Circuit Analysis and Design
Ch. 15 - Design a twopole lowpass Butterworth filter with a...Ch. 15 - Consider the switchedcapacitor circuit in Figure...Ch. 15 - Prob. 15.3EPCh. 15 - (a) Design a threepole highpass Butterworth active...Ch. 15 - Prob. 15.2TYUCh. 15 - Prob. 15.3TYUCh. 15 - Simulate a 25M resistance using the circuit in...Ch. 15 - Design the phaseshift oscillator shown in Figure...Ch. 15 - Design the Wienbridge circuit in Figure 15.17 to...Ch. 15 - Prob. 15.5TYU
Ch. 15 - Prob. 15.6TYUCh. 15 - Prob. 15.6EPCh. 15 - Redesign the street light control circuit shown in...Ch. 15 - A noninverting Schmitt trigger is shown m Figure...Ch. 15 - For the Schmitt trigger in Figure 15.30(a), the...Ch. 15 - Prob. 15.9TYUCh. 15 - Prob. 15.8EPCh. 15 - Prob. 15.9EPCh. 15 - Consider the 555 IC monostablemultivibrator. (a)...Ch. 15 - The 555 IC is connected as an...Ch. 15 - Prob. 15.10TYUCh. 15 - Prob. 15.11TYUCh. 15 - Prob. 15.12TYUCh. 15 - Prob. 15.12EPCh. 15 - Prob. 15.13EPCh. 15 - (a) Consider the bridge amplifier in Figure 15.46...Ch. 15 - Prob. 15.14EPCh. 15 - Prob. 15.15EPCh. 15 - Prob. 15.16EPCh. 15 - Prob. 1RQCh. 15 - Prob. 2RQCh. 15 - Consider a lowpass filter. What is the slope of...Ch. 15 - Prob. 4RQCh. 15 - Describe how a capacitor in conjunction with two...Ch. 15 - Sketch a onepole lowpass switchedcapacitor filter...Ch. 15 - Explain the two basic principles that must be...Ch. 15 - Prob. 8RQCh. 15 - Prob. 9RQCh. 15 - Prob. 10RQCh. 15 - Prob. 11RQCh. 15 - What is the primary advantage of a Schmitt trigger...Ch. 15 - Sketch the circuit and explain the operation of a...Ch. 15 - Prob. 14RQCh. 15 - Prob. 15RQCh. 15 - Prob. 16RQCh. 15 - Prob. 17RQCh. 15 - Prob. 18RQCh. 15 - Prob. D15.1PCh. 15 - Prob. 15.2PCh. 15 - The specification in a highpass Butterworth filter...Ch. 15 - (a) Design a twopole highpass Butterworth active...Ch. 15 - (a) Design a threepole lowpass Butterworth active...Ch. 15 - Prob. 15.6PCh. 15 - Prob. 15.7PCh. 15 - Prob. 15.8PCh. 15 - A lowpass filter is to be designed to pass...Ch. 15 - Prob. 15.10PCh. 15 - Prob. 15.11PCh. 15 - Prob. D15.12PCh. 15 - Prob. D15.13PCh. 15 - Prob. D15.14PCh. 15 - Prob. 15.15PCh. 15 - Prob. 15.16PCh. 15 - Prob. 15.17PCh. 15 - Prob. 15.18PCh. 15 - A simple bandpass filter can be designed by...Ch. 15 - Prob. 15.20PCh. 15 - Prob. 15.21PCh. 15 - Prob. D15.22PCh. 15 - Prob. 15.23PCh. 15 - Consider the phase shift oscillator in Figure...Ch. 15 - In the phaseshift oscillator in Figure 15.15, the...Ch. 15 - Consider the phase shift oscillator in Figure...Ch. 15 - Prob. 15.27PCh. 15 - Prob. 15.28PCh. 15 - Prob. 15.29PCh. 15 - Prob. 15.30PCh. 15 - Prob. 15.31PCh. 15 - A Wienbridge oscillator is shown in Figure P15.32....Ch. 15 - Prob. 15.33PCh. 15 - Prob. D15.34PCh. 15 - Prob. D15.35PCh. 15 - Prob. 15.36PCh. 15 - Prob. 15.37PCh. 15 - Prob. D15.38PCh. 15 - Prob. 15.39PCh. 15 - Prob. 15.40PCh. 15 - Prob. 15.41PCh. 15 - For the comparator in the circuit in Figure...Ch. 15 - Prob. 15.43PCh. 15 - Prob. 15.44PCh. 15 - Prob. 15.45PCh. 15 - Consider the Schmitt trigger in Figure P15.46....Ch. 15 - The saturated output voltages are VP for the...Ch. 15 - Consider the Schmitt trigger in Figure 15.30(a)....Ch. 15 - Prob. 15.50PCh. 15 - Prob. 15.52PCh. 15 - Prob. 15.53PCh. 15 - Prob. 15.54PCh. 15 - Prob. 15.55PCh. 15 - Prob. 15.56PCh. 15 - Prob. 15.57PCh. 15 - Prob. D15.58PCh. 15 - Prob. 15.59PCh. 15 - The saturated output voltages of the comparator in...Ch. 15 - (a) The monostablemultivibrator in Figure 15.37 is...Ch. 15 - A monostablemultivibrator is shown in Figure...Ch. 15 - Prob. D15.63PCh. 15 - Design a 555 monostablemultivibrator to provide a...Ch. 15 - Prob. 15.65PCh. 15 - Prob. 15.66PCh. 15 - Prob. 15.67PCh. 15 - Prob. 15.68PCh. 15 - An LM380 must deliver ac power to a 10 load. The...Ch. 15 - Prob. 15.70PCh. 15 - Prob. D15.71PCh. 15 - Prob. 15.72PCh. 15 - (a) Design the circuit shown in Figure P15.72 such...Ch. 15 - Prob. 15.74PCh. 15 - Prob. 15.75PCh. 15 - Prob. 15.76PCh. 15 - Prob. D15.77PCh. 15 - Prob. 15.78P
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- d) Design (Find the values of the R₁, R2, and C₁) an astable multivibrator circuit to have an output waveform as shown below in the figure (tH = 375µs and t₁ = 125µs). (Assume C₁ = C₂ and R₁ # R₂) and determine the frequency of oscillation and the duty cycle. R1: R2 C1 Q Vcc 4 555 5 C2 10nF I 8 1 3L -OVO tH = 375.0us tL = 125.0usarrow_forwardDraw a diagram for astable multivibrator using 555 timer. Find the oscillation frequency of the output signal and its duty cycle when the external capacitor is 0.01 uF, the R1 and R2 are 10 kn and 50 kn respectively. While the decoupling capacitor equal 0.1 µF. What happened to the duty cycle when R2 become 1M02?arrow_forward6. Refer to the RC Phase-shift Oscillator below. A Vin R₁ + Rf 6.a. Derive the feedback factor formula for this circuit. 6.b. Draw the output waveform. C C mm C Vout wwwwwarrow_forward
- A differentiator sub-system is built from an op-amp, a 10 yF capacitor and a 200 ka resistor. The output, viewed on an oscilloscope, is a t 5 volt square wave with a frequency of 0.25 Hz. The input waveform is O A triangle wave of peak-to-peak amplitude 5 volts O A pure sine wave of amplitude 2.5 volts and frequency 0.25 Hz O Unknown, since the amplifier output is clearly overloaded O An inverted + 0.2 volt square wavearrow_forwardFor the Wien-Bridge oscillator, determine the oscillator frequency, fout R4 R3 ... LM324 Vout C2 OU R1 U1A 10k 0.75UF R2 C1 10k 0.75uF A 10.52 Hz B) 21.22 Hz 33.33 Hz 52.67 Hz 11arrow_forwardSince the frequency of the Wien bridge oscillator circuit you see in the figure below is f= 15.915 kHz; b. The capacitor you found and the current capacitor values do not change, and the frequency is doubled. What should be done to remove it, explain by calculation? 100k 1 %3D 2n R1.C1.R2.C2 741 J+12 Vo 100k 10k 10nF 10karrow_forward
- with comments on the output for better understanding Thank youarrow_forward02 1) The PWM is new thechnigue adopted in power electronies application .explaine the advantages of this application 2) In Puls width modulation applieation we Use line and sine wave refrences .explane the advantages and dis advanteges each onearrow_forwardThe clamping circuit clamps or shift the input sinusoidal signal up or down. Farrow_forward
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