To verify : The function f,g and a domain D so that f0g(x)=x2 with the domain D .
Given information:
The functions are f(x) and g(x.) and domain are given
Concept used:
Domain is the set of independent value..
Let f and g be two functions such that the domain of f intersects the range of g . The
composition f of g , denoted , is defined by the rule
f0g(x)=fg(x) .
Calculations:
Case 1.
Consider the function f=ex,g=√2−x .
Then
fog(x)=f(g(x))=e√2−x
domain will be (−∞,2].
Case 2.
Consider the function f=(x2+2)2,g=(x+1) .
Then
fog(x)=f(g(x))=((x+1)2+2)2
So domain will be (−∞,∞).
Case 3.
Consider the function f=(x2−2)2,g=2lnx .
Then
fog(x)=f(g(x))=(4(lnx)2−2)2
domain will be (0,∞).
Case 4.
Consider the function f=1(x−1)2,g=1(x−1) .
Then
fog(x)=f(g(x))=1(1x−1−1)2=1(2−xx−1)2
The domain will be x<1,2<x<1 or x>2.
Case 5.
Consider the function f=x2−2x+1,g=√x−2 .
Then
fog(x)=f(g(x))=(√x−2)2−2(√x−2)+1=(x−1)−2(√x−2)
So domain will be [2,∞).
Case 6.
Consider the function f=(x+1x)2,g=x+1x .
Then
fog(x)=f(g(x))=(x+1x+1x+1x)2=((2x+1x)(xx+1))2=(2x+1x+1)2
So domain will be x≠−1.
Chapter 1 Solutions
PRECALCULUS:GRAPH...-NASTA ED.(FLORIDA)
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