To find: The formula and domain for functions f+g f−gand fg .
The required functions are: (f+g)=√x+|x+3| , (f−g)=√x−|x+3| and f.g=√x⋅|x+3| . The domain of each function (f+g) , (f−g) and fg is the set of real numbers x∈(0,∞) .
Given data: The functions f(x) and g(x) are f(x)=√x ; g(x)=|x+3| .
Method/Formula used:
The sum, difference and product of the two functions f(x) and g(x) is also a function given by f(x)+g(x)=(f+g)x , f(x)−g(x)=(f−g)x and f(x)⋅g(x)=(f⋅g)(x) . The domain of resulting functions (f+g)x , (f−g)x and f(x)⋅g(x) are the values of x that define these functions (f+g)x (f−g)x and (f⋅g)(x)
Calculation:
The given functions are f(x)=√x ; g(x)=|x+3| . Therefore, using the definition of (f+g)(x) , (f−g)(x) and fg(x) are:
(f+g)(x) :
(f+g)x=f(x)+g(x)=√x+|x+3|
The function f+g=√x+|x+3| is not defined when x<0 .Therefore, the domain of (f+g)x is [0,∞) .
(f-g)(x) :
(f−g)x=f(x)−g(x)==√x−|x+3|
The function f−g=√x−|x+3| is not defined when x<0 .Therefore, the domain of (f+g)x is [0,∞) .
(fg)(x) :
(fg)x=√x|x+3|
The function f.g=√x⋅|x+3| is not defined when x<0 .Therefore, the domain of (fg)x is [0,∞) .
The graphs of functions √x+|x+3| , √x−|x+3| , and √x⋅|x+3| are shown in Fig. (1), here that also shows that the functions √x+|x+3| , √x−|x+3| , and √x⋅|x+3| defined for all x≥0 , asserting that the domain of each of these function is [0,∞) .
Chapter 1 Solutions
PRECALCULUS:GRAPH...-NASTA ED.(FLORIDA)
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