Manufacturing Engineering & Technology
7th Edition
ISBN: 9780133128741
Author: Serope Kalpakjian, Steven Schmid
Publisher: Prentice Hall
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Chapter 14, Problem 35QTP
To what thickness can a solid cylinder of 1020 steel that is 1 in. in diameter and 2 in. high be forged in a press that can generate 100,000 lb?
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Chapter 14 Solutions
Manufacturing Engineering & Technology
Ch. 14 - What is the difference between cold, warm, and hot...Ch. 14 - Explain the difference between open-die and...Ch. 14 - Explain the difference between fullering, edging,...Ch. 14 - What is flash? What is its function?Ch. 14 - Why is the intermediate shape of a part important...Ch. 14 - Describe the features of a typical forging die.Ch. 14 - Explain what is meant by load limited, energy...Ch. 14 - What type of parts can be produced by rotary...Ch. 14 - Why is hubbing an attractive alternative to...Ch. 14 - What is the difference between piercing and...
Ch. 14 - What is a hammer? What are the different kinds of...Ch. 14 - Why is there barreling in upsetting?Ch. 14 - What are the advantages and disadvantages of...Ch. 14 - Why are draft angles required in forging dies?Ch. 14 - Is a mandrel needed in swaging?Ch. 14 - Describe and explain the factors that influence...Ch. 14 - How can you tell whether a certain part is forged...Ch. 14 - Identify casting design rules, described in...Ch. 14 - Describe the factors involved in precision...Ch. 14 - Why is control of the volume of the blank...Ch. 14 - Why are there so many types of forging machines...Ch. 14 - What are the advantages and limitations of cogging...Ch. 14 - What are the advantages and limitations of using...Ch. 14 - Review Fig. 14.6e and explain why internal draft...Ch. 14 - Comment on your observations regarding the...Ch. 14 - Describe your observations concerning the control...Ch. 14 - Prob. 27QLPCh. 14 - Describe the difficulties involved in defining the...Ch. 14 - Describe the advantages of servo presses for...Ch. 14 - List the general recommendations you would make...Ch. 14 - Which would you recommend, (a) hot forging and...Ch. 14 - Take two solid, cylindrical specimens of equal...Ch. 14 - Calculate the room-temperature forging force for a...Ch. 14 - Using Eq. (14.2), estimate the forging force for...Ch. 14 - To what thickness can a solid cylinder of 1020...Ch. 14 - In Example 14.1, calculate the forging force,...Ch. 14 - Using Eq. (14.1), make a plot of the forging...Ch. 14 - How would you go about estimating the punch force...Ch. 14 - A mechanical press is powered by a 30-hp motor and...Ch. 14 - A solid cylindrical specimen, made of a perfectly...Ch. 14 - Devise an experimental method whereby you can...Ch. 14 - Assume that you represent the forging industry and...Ch. 14 - Figure P14.44 shows a round impression-die forging...Ch. 14 - Prob. 45SDPCh. 14 - Prob. 46SDPCh. 14 - Review the sequence of operations in the...Ch. 14 - Prob. 48SDPCh. 14 - Discuss the possible environmental concerns...Ch. 14 - List the advantages and disadvantages in using a...
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- 3. A steam power plant has an average monthly net power delivery of 740 MW over the course of a year. This power delivery is accomplished by burning coal in the boiler. The coal has a heating value of 9150 Btu/lbm. The cost of the coal is $14.20/ton. The overall thermal efficiency of the plant is, nth = Wnet Qboiler = 0.26 = 26% Determine the annual cost of the coal required to deliver the given average monthly power.arrow_forward47 14 16 12 34 10 12 12 33arrow_forward= The forces F₁ = 590 lb, F₂ = 380 lb, F3 = 240 lb and F 330 lb. Determine the forces in each member of the truss. Use positive values to indicate tension and negative values to indicate compression. a a a D b F₁ A 000 B. 779977 F₂V H G E F4 b BY NC SA 2013 Michael Swanbom Values for dimensions on the figure are given in the following table. Note the figure may not be to scale. Variable Value a 6 ft b 10.1 ft The force in member AB is lb. The force in member AH is lb. The force in member GH is lb. The force in member BH is lb. The force in member BC is lb. The force in member BG is lb. The force in member EG is lb. The force in member CD is lb. The force in member DE is lb. The force in member CE is lb. The force in member CG is lb.arrow_forward
- Multiple Choice Circle the best answer to each statement. 1. Which type of surface deviation is controlled by a cy- lindricity tolerance but not by a circularity tolerance? A. B. C. Ovality Taper Lobing D. None of the above 2. When verifying a cylindricity tolerance, the inspec- tion method must be able to collect a set of points and determine the: A. Distance between two coaxial cylinders that con- tain the set of points B. Cylinder that circumscribes the set of points C. Cylinder that inscribes the set of points D. Distance between two coaxial circles that contain the set of points 3. Where Rule #1 applies to a cylindrical regular feature of size, the tolerance value of a cylindricity tolerance applied to the feature of size must be tolerance. A. Less than B. Equal to C. Greater than D. None of the above the size 4. Which of the following modifiers may be applied with a cylindricity tolerance? A. M B. C. ℗ D. Ø 5. Which geometric tolerance can provide an indirect cylindricity…arrow_forwardThe beam AB is attached to the wall in the xz plane by a fixed support at A. A force of F = (−129î + 69.0ĵ + 3591) N is applied to the end of the beam at B. The weight of the beam can be modeled with a uniform distributed load of intensity w = 85.0 N/m acting in the negative z direction along its entire length. Find the support reactions at A. Z с A b a B F y Cc 10 BY NC SA 2016 Eric Davishahl X Values for dimensions on the figure are given in the following. table. Note the figure may not be to scale. Variable Value a 5.60 m b 5.00 m C 3.70 m A II = MA = ( m 2.> ~.> + + k) N k) N-arrow_forwardneed help?arrow_forward
- A bent pipe is attached to a wall with brackets as shown. A force of F = 180 lb is applied to the end of the tube with direction indicated by the dimensions in the figure. Determine the support reactions at the brackets B, C, and D. Model these brackets as journal bearings (only force reactions perpendicular to the axis of the tube) and neglect couple moment reactions. Assume the distance between the supports at B and C and the tube bends nearby are negligible such that the support at C is directly above the support at D and the dimension g gives the distance between supports B and C. Enter your answers in Cartesian components. 2013 Michael Swanbom cc 10 BY NC SA g h א B 8° У A C x каж Values for dimensions on the figure are given in the table below. Note the figure may not be to scale. Variable Value a 6.72 in b 11.8 in с 14.8 in d 42.0 in h 26.6 in g 28.0 in → The reaction at B is B = lb. The reaction at C is C = lb. The reaction at D is D = lb. + << + + 2. + + 557 〈んarrow_forwardThe force F1 = 10 kN, F2 = 10 kN, F3 = 10 kN, F4 = 5 KN are acting on the sttructure shown. Determine the forces in the members specified below. Use positive values to indicate tension and negative values to indicate compression. F2 D b F1 F3 C E b F4 b B F a G Values for dimensions on the figure are given in the following table. Note the figure may not be to scale. Variable Value a 3 m b 4 m The force in member BC is KN. The force in member BE is KN. The force in member EF is KN.arrow_forwardh = The transmission tower is subjected to the forces F₁ 3.6 KN at 50° and F2 = 3.3 kN at = 35°. Determine the forces in members BC, BP, PQ, PC, CD, DP and NP. Use positive values to indicate tension and negative values to indicate compression. 不 кажаж в *а*аж E N M d d IF, c B CENTER LINE S อ K F₂ Kbb cc 10 BY NC SA 2013 Michael Swanbom Values for dimensions on the figure are given in the following table. Note the figure may not be to scale. Variable Value a 1.7 m b 4.9 m с 3 m d 5.2 m h 8.4 m Values for dimensions on the figure are given in the following table. Note the figure may not be to scale. Variable Value a 1.7 m 4.9 m с 3 m d 5.2 m h 8.4 m The force in member BC is KN. The force in member BP is KN. The force in member PQ is KN. The force in member PC is KN. The force in member CD is KN. The force in member DP is KN. The force in member NP is KN.arrow_forward
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