Prescott's Microbiology
10th Edition
ISBN: 9781259281594
Author: Joanne Willey, Linda Sherwood Adjunt Professor Lecturer, Christopher J. Woolverton Professor
Publisher: McGraw-Hill Education
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Textbook Question
Chapter 14, Problem 2CHI
Describe the
- a. A strain with a mutation in the gene encoding the lac repressor; the mutant repressor cannot bind allolactose.
- b. A strain with a mutation in the gene encoding CAP; the mutant form of CAP binds but cannot release cAMP.
- c. A strain in which the Shine-Dalgarno sequence has been deleted from the gene encoding adenyl cyclase.
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Consider a bacterial strain that has a mutant lac repressor that cannot bind the operator. A. What will happen in the presence and absence of lactose? B. Will there be any difference if glucose is present or not? Explain your answer.
An E. coli strain where the crp gene that encodes the cAMP receptor protein (CRP), also known as the catabolite activator protein, has a mutation such that it is no longer active. In this case, the strain would no longer be able to (select all that are correct)
A. Grow on minimal medium plus glucose
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Chapter 14 Solutions
Prescott's Microbiology
Ch. 14.2 - MICRO INQUIRY In what way is on inducer molecule...Ch. 14.2 - MICRO INQUIRY Is allolactose a corepressor or...Ch. 14.2 - Retrieve, Infer, Apply Many genes and operons are...Ch. 14.2 - Retrieve, Infer, Apply What are induction and...Ch. 14.2 - Retrieve, Infer, Apply Using figure 14.4 as a...Ch. 14.3 - MICRO INQUIRY How does this attenuation respond to...Ch. 14.4 - MICRO INQUIRY How does inhibition of translation...Ch. 14.4 - Prob. 1RIACh. 14.4 - Retrieve, Infer, Apply Describe how attenuation...Ch. 14.4 - Retrieve, Infer, Apply What are translational...
Ch. 14.4 - Retrieve, Infer, Apply How are translational...Ch. 14.4 - Prob. 5RIACh. 14.5 - MICRO INQUIRY Relative to each promoter, where...Ch. 14.5 - MICRO INQUIRY For what other compounds would you...Ch. 14.5 - Prob. 3MICh. 14.5 - MICRO INQUIRY Why does V. harveyi make three...Ch. 14.5 - Prob. 5MICh. 14.5 - Prob. 6MICh. 14.5 - Prob. 1.1RIACh. 14.5 - Retrieve, Infer, Apply What is diauxic growth?...Ch. 14.5 - Retrieve, Infer, Apply Describe the events that...Ch. 14.5 - Retrieve, Infer, Apply E. coli has two phosphate...Ch. 14.5 - Prob. 1.5RIACh. 14.5 - Prob. 1.6RIACh. 14.5 - Prob. 2.1RIACh. 14.5 - Retrieve, Infer, Apply Why might bacteria use...Ch. 14.5 - Prob. 2.3RIACh. 14.5 - Prob. 2.4RIACh. 14 - Attenuation affects anabolic pathways, whereas...Ch. 14 - Describe the phenotype of the following E. coli...Ch. 14 - Prob. 3CHICh. 14 - What would be the phenotype of a B. subtilis...Ch. 14 - Propose a mechanism by which a cell might sense...Ch. 14 - Neisseria meningitidis, commonly called...
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, biology and related others by exploring similar questions and additional content below.Similar questions
- Give only typing answer with explanation and conclusionarrow_forwardSelect the best explanation of the unfolded protein response (UPR): O A. The UPR senses misfolded proteins through detection of proteins tagged with polyubiquitin chains and sends them for degradation in the lysosome B. The UPR senses misfolded proteins through recognition of specific oligosaccharide conformations and sends them for degradation via the proteasome C. The UPR senses high levels of misfolded proteins in the ER and activates ubiquitin ligases to add ubiquitin to the misfolded proteins and target them for secretion from the cell. D. The UPR senses ER stress in the form of high levels of misfolded proteins and signals the cell to halt translation and induces expression of ER chaperonesarrow_forwardCTP synthetase catalyzes the glutamine-dependent conversion of UTP to CTP. The enzyme is allosterically inhibited by the product, CTP. Mammalian cells defective in this allosteric inhibition are found to have a complex phenotype: They require thymidine in the growth medium, they have unbalanced nucleotide pools, and they have an elevated spontaneous mutation rate. Explain the likely basis for these observations.arrow_forward
- Explain Pleasearrow_forwardPlease help with this question with a better explanationarrow_forwarda. Would you expect a cell to continue or to stopdividing at a nonpermissive high temperature if itis a temperature-sensitive Ras mutant whose protein product is fixed in the GTP-bound form atnonpermissive temperature?b. What would you expect if you had a temperaturesensitive mutant in which the Ras protein staysin the GDP-bound form at high temperature?arrow_forward
- A mutation occurred on the lacI (repressor) gene resulting in a constant production of beta-galactosidase and permease, even in the absence of lactose. Provide an explanation for the effect of this mutation on the repressor protein moleculearrow_forwardIf the lacl gene is mutated so that the repressor protein no longer binds to lactose, what will be the effect on the expression of B-galactosidase in lactose's presence and absence? Explain. If the promoter for lacl is mutated so that the expression of the repressor increases, what will be the effect on the expression of B-galactosidase in the presence and absence of lactose? Explain. D. (Extremely tricky question!) Describe the behavior of the lac operon assuming that the lacl gene has been mutated so that the repressor now binds to DNA in the presence of lactose but cannot bind to DNA in the absence of lactose.arrow_forwardGive only typing answer with explanation and conclusion For the genotype shown below, which best describes the expression of the B-galactosidase gene. I+ Oc Z+ / F’ Is Constitutive Repressed Inducible None of the abovearrow_forward
- Please explainarrow_forwardThe lac genotypes are as shown below: P+OcZ-Y+A+// P¯O+Z+Y+A+ (i) The lac operon consists of three structural genes, lacZ, lacY and lacA. Which structural genes are involved in lactose metabolism? Explain. (ii) Draw and explain how lactose repress the gene expression in lac IS/I- heterozygote. (iii) What is the function of the promoter in the bacterial operon?arrow_forwardThe graph below shows a growth curve of E. coli growing in a defined medium containing equal concentration of glucose and lactose. On the y-axis optical density provides a measure of cell number, higher optical density indicates greater cell number. OD (optical density) Time Based on your knowledge regarding regulation of the lac operon, the best explanation of these results is that... A. The bacteria are utilizing both sugars simultaneously. B. At early time points, inhibition of the lac repressor allows for lactose metabolism. C. Cells constitutively express enzymes needed for sugar metabolism, allowing for continuous cell growth. D. Glucose activates CAP, allowing for cell growth at intermediate time points. E. At later time points, high cAMP allows for an increase in beta-galactosidase expression.arrow_forward
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