(a)
Interpretation:
The common name for the given ether has to be assigned.
Concept Introduction:
Any organic molecule can be named by using certain rules given by IUPAC (International Union for Pure and applied chemistry). IUPAC name consists of three parts in major namely Prefix suffix and root word.
Prefix represents the substituent present in the molecule and its position in the root name.
Suffix denotes the presence of
Root word represents the longest continuous carbon skeleton of the organic molecule.
Rules for assigning common names to ether:
For obtaining common name for ether, two rules are applicable, one for symmetrical ethers and one for unsymmetrical ethers.
- ✓ For unsymmetrical ethers, the two hydrocarbon groups that is attached to the oxygen atom is arranged in an alphabetical order and the word ether is added. The words are separated by a space. These names have three words with space between them.
- ✓ For symmetrical ethers, prefix di- is used. Then the word ether is added with a space between the two words. These names have two words with space between them.
(b)
Interpretation:
The common name for the given ether has to be assigned.
Concept Introduction:
Any organic molecule can be named by using certain rules given by IUPAC (International Union for Pure and applied chemistry). IUPAC name consists of three parts in major namely Prefix suffix and root word.
Prefix represents the substituent present in the molecule and its position in the root name.
Suffix denotes the presence of functional group if any in the molecule. It can be an alkene, alkyne, alcohol, carboxylic acid, alcohol etc.
Root word represents the longest continuous carbon skeleton of the organic molecule.
Rules for assigning common names to ether:
For obtaining common name for ether, two rules are applicable, one for symmetrical ethers and one for unsymmetrical ethers.
- ✓ For unsymmetrical ethers, the two hydrocarbon groups that is attached to the oxygen atom is arranged in an alphabetical order and the word ether is added. The words are separated by a space. These names have three words with space between them.
- ✓ For symmetrical ethers, prefix di- is used. Then the word ether is added with a space between the two words. These names have two words with space between them.
(c)
Interpretation:
The common name for the given ether has to be assigned.
Concept Introduction:
Any organic molecule can be named by using certain rules given by IUPAC (International Union for Pure and applied chemistry). IUPAC name consists of three parts in major namely Prefix suffix and root word.
Prefix represents the substituent present in the molecule and its position in the root name.
Suffix denotes the presence of functional group if any in the molecule. It can be an alkene, alkyne, alcohol, carboxylic acid, alcohol etc.
Root word represents the longest continuous carbon skeleton of the organic molecule.
Rules for assigning common names to ether:
For obtaining common name for ether, two rules are applicable, one for symmetrical ethers and one for unsymmetrical ethers.
- ✓ For unsymmetrical ethers, the two hydrocarbon groups that is attached to the oxygen atom is arranged in an alphabetical order and the word ether is added. The words are separated by a space. These names have three words with space between them.
- ✓ For symmetrical ethers, prefix di- is used. Then the word ether is added with a space between the two words. These names have two words with space between them.
(d)
Interpretation:
The common name for the given ether has to be assigned.
Concept Introduction:
Any organic molecule can be named by using certain rules given by IUPAC (International Union for Pure and applied chemistry). IUPAC name consists of three parts in major namely Prefix suffix and root word.
Prefix represents the substituent present in the molecule and its position in the root name.
Suffix denotes the presence of functional group if any in the molecule. It can be an alkene, alkyne, alcohol, carboxylic acid, alcohol etc.
Root word represents the longest continuous carbon skeleton of the organic molecule.
Rules for assigning common names to ether:
For obtaining common name for ether, two rules are applicable, one for symmetrical ethers and one for unsymmetrical ethers.
- ✓ For unsymmetrical ethers, the two hydrocarbon groups that is attached to the oxygen atom is arranged in an alphabetical order and the word ether is added. The words are separated by a space. These names have three words with space between them.
- ✓ For symmetrical ethers, prefix di- is used. Then the word ether is added with a space between the two words. These names have two words with space between them.
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Chapter 14 Solutions
EBK GENERAL, ORGANIC, AND BIOLOGICAL CH
- 2. Use Hess's law to calculate the AH (in kJ) for: rxn CIF(g) + F2(g) → CIF 3 (1) using the following information: 2CIF(g) + O2(g) → Cl₂O(g) + OF 2(g) AH = 167.5 kJ ΔΗ 2F2 (g) + O2(g) → 2 OF 2(g) 2C1F3 (1) + 202(g) → Cl₂O(g) + 3 OF 2(g) о = = -43.5 kJ AH = 394.1kJarrow_forwardci Draw the major product(s) of the following reactions: (3 pts) CH3 HNO3/H2SO4 HNO3/ H2SO4 OCH3 (1 pts)arrow_forwardProvide the product for the reactionarrow_forward
- What is the net ionic equation for the reaction between tin(IV) sulfide and nitric acid?arrow_forwardThe combustion of 28.8 g of NH3 consumes exactly _____ g of O2. 4 NH3 + 7 O2 ----> 4 NO2 + 6 H2Oarrow_forwardWhat is the molecular formula of the bond-line structure shown below OH HO ○ C14H12O2 ○ C16H14O2 ○ C16H12O2 O C14H14O2arrow_forward
- Check all molecules that are acids on the list below. H2CO3 HC2H3O2 C6H5NH2 HNO3 NH3arrow_forwardFrom the given compound, choose the proton that best fits each given description. a CH2 CH 2 Cl b с CH2 F Most shielded: (Choose one) Least shielded: (Choose one) Highest chemical shift: (Choose one) Lowest chemical shift: (Choose one) ×arrow_forwardConsider this molecule: How many H atoms are in this molecule? How many different signals could be found in its 1H NMR spectrum? Note: A multiplet is considered one signal.arrow_forward
- For each of the given mass spectrum data, identify whether the compound contains chlorine, bromine, or neither. Compound m/z of M* peak m/z of M + 2 peak ratio of M+ : M + 2 peak Which element is present? A 122 no M + 2 peak not applicable (Choose one) B 78 80 3:1 (Choose one) C 227 229 1:1 (Choose one)arrow_forwardShow transformation from reactant to product, step by step. *see imagearrow_forwardCheck the box if the molecule contains the listed item. *See imagearrow_forward
- Organic And Biological ChemistryChemistryISBN:9781305081079Author:STOKER, H. Stephen (howard Stephen)Publisher:Cengage Learning,General, Organic, and Biological ChemistryChemistryISBN:9781285853918Author:H. Stephen StokerPublisher:Cengage LearningIntroduction to General, Organic and BiochemistryChemistryISBN:9781285869759Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar TorresPublisher:Cengage Learning
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