(a)
Interpretation:
Structure of the given ether has to be drawn.
Concept Introduction:
Structure of ether can be derived from the common name or IUPAC name.
From common name:
The two hydrocarbon groups are given in alphabetical order in the common name. They both are attached through oxygen atom which leads to the structure of the ether.
From IUPAC name:
The base name is drawn first followed by attaching the alkoxy group at the correct number of carbon atom where it is substituted in the base name. This is indicated in the IUPAC name itself.
(b)
Interpretation:
Structure of the given ether has to be drawn.
Concept Introduction:
Structure of ether can be derived from the common name or IUPAC name.
From common name:
The two hydrocarbon groups are given in alphabetical order in the common name. They both are attached through oxygen atom which leads to the structure of the ether.
From IUPAC name:
The base name is drawn first followed by attaching the alkoxy group at the correct number of carbon atom where it is substituted in the base name. This is indicated in the IUPAC name itself.
(c)
Interpretation:
Structure of the given ether has to be drawn.
Concept Introduction:
Structure of ether can be derived from the common name or IUPAC name.
From common name:
The two hydrocarbon groups are given in alphabetical order in the common name. They both are attached through oxygen atom which leads to the structure of the ether.
From IUPAC name:
The base name is drawn first followed by attaching the alkoxy group at the correct number of carbon atom where it is substituted in the base name. This is indicated in the IUPAC name itself.
(d)
Interpretation:
Structure of the given ether has to be drawn.
Concept Introduction:
Structure of ether can be derived from the common name or IUPAC name.
From common name:
The two hydrocarbon groups are given in alphabetical order in the common name. They both are attached through oxygen atom which leads to the structure of the ether.
From IUPAC name:
The base name is drawn first followed by attaching the alkoxy group at the correct number of carbon atom where it is substituted in the base name. This is indicated in the IUPAC name itself.

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Chapter 14 Solutions
EBK GENERAL, ORGANIC, AND BIOLOGICAL CH
- > You are trying to decide if there is a single reagent you can add that will make the following synthesis possible without any other major side products: 1. ☑ CI 2. H3O+ O Draw the missing reagent X you think will make this synthesis work in the drawing area below. If there is no reagent that will make your desired product in good yield or without complications, just check the box under the drawing area and leave it blank. Click and drag to start drawing a structure. Explanation Check ? DO 18 Ar B © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Accessibilityarrow_forwardDon't use ai to answer I will report you answerarrow_forwardConsider a solution of 0.00304 moles of 4-nitrobenzoic acid (pKa = 3.442) dissolved in 25 mL water and titrated with 0.0991 M NaOH. Calculate the pH at the equivalence pointarrow_forward
- What is the name of the following compound? SiMe3arrow_forwardK Draw the starting structure that would lead to the major product shown under the provided conditions. Drawing 1. NaNH2 2. PhCH2Br 4 57°F Sunny Q Searcharrow_forward7 Draw the starting alkyl bromide that would produce this alkyne under these conditions. F Drawing 1. NaNH2, A 2. H3O+ £ 4 Temps to rise Tomorrow Q Search H2arrow_forward
- Organic And Biological ChemistryChemistryISBN:9781305081079Author:STOKER, H. Stephen (howard Stephen)Publisher:Cengage Learning,General, Organic, and Biological ChemistryChemistryISBN:9781285853918Author:H. Stephen StokerPublisher:Cengage Learning

