Using K a value of F - , K b value for F - has to be calculated. Concept Introduction: Acid dissociation constant ( K a ) : It is an equilibrium constant which refers the dissociation (ionization) of an acid. The value of K b can be calculated by using K a and vice versa. This relation is given as, K b = K w K a or K a = K w K b
Using K a value of F - , K b value for F - has to be calculated. Concept Introduction: Acid dissociation constant ( K a ) : It is an equilibrium constant which refers the dissociation (ionization) of an acid. The value of K b can be calculated by using K a and vice versa. This relation is given as, K b = K w K a or K a = K w K b
Solution Summary: The author explains the acid dissociation constant (K_Texta), which is an equilibrium constant that refers to the ionization of an acid.
Using Ka value of F-, Kb value for F- has to be calculated.
Concept Introduction:
Acid dissociation constant(Ka):
It is an equilibrium constant which refers the dissociation (ionization) of an acid. The value of Kb can be calculated by using Ka and vice versa. This relation is given as,
Kb=KwKa or Ka=KwKb
(b)
Interpretation Introduction
Interpretation:
Using Ka value of OBr-, Kb value for OBr- has to be calculated.
Concept Introduction:
Acid dissociation constant(Ka):
It is an equilibrium constant which refers the dissociation (ionization) of an acid. The value of Kb can be calculated by using Ka and vice versa. This relation is given as,
Kb=KwKa or Ka=KwKb
(c)
Interpretation Introduction
Interpretation:
Using Ka value of HS-, Kb value for HS- has to be calculated.
Concept Introduction:
Acid dissociation constant(Ka):
It is an equilibrium constant which refers the dissociation (ionization) of an acid. The value of Kb can be calculated by using Ka and vice versa. This relation is given as,
Kb=KwKa or Ka=KwKb
(d)
Interpretation Introduction
Interpretation:
Using Ka value of S2-, Kb value for S2- has to be calculated.
Concept Introduction:
Acid dissociation constant(Ka):
It is an equilibrium constant which refers the dissociation (ionization) of an acid. The value of Kb can be calculated by using Ka and vice versa. This relation is given as,
Consider a solution of 0.00304 moles of 4-nitrobenzoic acid (pKa = 3.442) dissolved in 25 mL water and titrated with 0.0991 M NaOH. Calculate the pH at the equivalence point
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