Chapter 14, Problem 14.117CHP

Interpretation Introduction

Interpretation:

$\text{pH}$ and the concentration of all species present in $\text{0}\text{.10 M}\text{HF}$ and $\text{0}\text{.050 M}$ Sodium benzoate has to be calculated.

Concept Introduction:

$\text{pH}$ is an logarithmic expression to express a solution is acidic, basic or neutral.  The $\text{pH}$ scale has values between $1-14$ and on which $7$ is neutral, below $7$ values are more acidic in nature and above $7$ values are more basic in nature.

$\text{pH + pOH= 14}$

$\text{pH = -log}\left[{\text{H}}_{\text{3}}{\text{O}}^{\text{+}}\right]$

$\left[{\text{H}}_{\text{3}}{\text{O}}^{\text{+}}\right]{\text{= antilog(-pH) =10}}^{\text{-pH}}$

$\text{pOH = -log}\left[{\text{OH}}^{\text{-}}\right]$

$\left[{\text{OH}}^{-}\right]{\text{= antilog(-pOH) =10}}^{\text{-pOH}}$