Chapter 14, Problem 14.80SP

Interpretation Introduction

Interpretation:

$\text{pH}$ and percent dissociation in $\text{1}\text{.5 M}$${\text{HNO}}_{\text{2}}$ has to be calculated.

Concept Introduction:

$\text{pH}$ is an logarithmic expression to express a solution is acidic, basic or neutral.  $\text{pH}$ scale lies values between 1-14 and on which 7 is neutral, below 7 values are more acidic in nature and above 7 values are more basic in nature.

$\text{pH + pOH= 14}$

$\text{pH = -log}\left[{\text{H}}_{\text{3}}{\text{O}}^{\text{+}}\right]$

$\left[{\text{H}}^{+}\right]{\text{= antilog(-pH) =10}}^{\text{-pH}}$

$\left[{\text{OH}}^{-}\right]{\text{= antilog(-pOH) =10}}^{\text{-pOH}}$

Percent dissociation:

It is defined as concentration of dissociated acid divided by the concentration of the acid times $100\%$.

$\text{Percent}\text{dissociation =}\frac{{\left[\text{HF}\right]}_{\text{dissociated}}}{{\left[\text{HA}\right]}_{\text{initial}}}\times 100\%$