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Identify products A and B from the given
a. Treatment of
b. Treatment of acetone
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- Deduce the structure from the c nmr dataarrow_forwardReaction of p-cresol with two equivalents of 2-methylprop-1-ene affordsBHT, a preservative with molecular formula C15H24O. BHT gives thefollowing 1H NMR spectral data: 1.4 (singlet, 18 H), 2.27 (singlet, 3 H), 5.0(singlet, 1 H), and 7.0 (singlet, 2 H) ppm. What is the structure of BHT?Draw a stepwise mechanism illustrating how it is formed.arrow_forwardGalantamine, a natural product produced by the amaryllis family of flowering plants, has been used in the early treatment of Alzheimer's disease. In a synthesis of galantamine and related compounds (J. Org. Chem. 2015, 80, 1952-1956), compound 1 was converted into compound 2. Propose an efficient synthesis for the conversion of 1 to 2 A. NaOH MeO D. DMP or PCC G. HBr MeO B. H₂SO4, H₂O, HgSO4 E. Na2Cr₂O7, H₂SO4, H₂O H. 1) O3; 2) DMS H 2 The conversion of 1 to 2 can be performed with some reagent or combination of the reagents listed below. Give the necessary reagents in the correct order for each transformation, as a string of letters (without spaces or punctuation, such as "EBF"). If there is more than one correct solution, provide just one answer. C. 1) BH3-THF; 2) H₂O2, NaOH F.HBr, ROOR I. TsCl, py Meo I₁, N Me Galanthamine OHarrow_forward
- When diphenyl ether is reacted under the same conditions as in Problem 22.35, a compound is produced whose 13C NMR spectrum shows six signals. Draw that product.arrow_forwardHow could 1H NMR spectroscopy be used to distinguish between each pair of compounds?arrow_forwardCompound A shows a molecular peak of 56 in Mass Spectrum. When compound A is treated with HBr and peroxides, it produces compound B, which shows twin molecular peaks with weights 136 and 138 in 1:1 ratio. The 'H NMR spectra of both compounds shown below. Identify the structures of A and B in the respective boxes. 2H Compound A 'H NMR of Compound A (integration is listed next to peaks) لد HBr peroxides 2H PPM 'H NMR of Compound B (integration is listed next to peaks, expansions in above) М 1H Compound B PPM 6H 6Harrow_forward
- Galantamine, a natural product produced by the amaryllis family of flowering plants, has been used in the early treatment of Alzheimer's disease. In a synthesis of galantamine and related compounds (J. Org. Chem. 2015, 80, 1952-1956), compound 1 was converted into compound 2. Propose an efficient synthesis for the conversion of 1 to 2 A. NaOH MeO D. DMP or PCC G. HBr 1 MeO B. H₂SO4, H₂O, HgSO4 E. Na₂Cr₂O7, H₂SO4, H₂O H. 1) O3; 2) DMS H 2 x I. TsCl, py The conversion of 1 to 2 can be performed with some reagent or combination of the reagents listed below. Give the necessary reagents in the correct order for each transformation, as a string of letters (without spaces or punctuation, such as "EBF"). If there is more than one correct solution, provide just one answer. C. 1) BH3-THF; 2) H₂O2, NaOH F.HBr, ROOR = MeO Ill. N Me Galanthamine OHarrow_forwardConsider the para-substituted aromatic ketones, NO2C6H4COCH3 (p-nitroacetophenone) and CH3OC6H4COCH3 (p-methoxyacetophenone).a. Which carbonyl compound is more stable?b. Which compound forms the higher percentage of hydrate at equilibrium?c. Which compound exhibits a carbonyl absorption at higher wavenumber in its IR spectrum? Explain your reasoning ineach part.arrow_forwardDeduce the structure of an unknown compound using the data. C,H,O: 10 NMR: 8 9.8 (1 H, s), 8 1.1 (9 H, s)arrow_forward
- Compound X (molecular formula C10H120) was treated with NH2NH2, ¯OH to yield compound Y (molecular formula C10H14). Match the 1H NMR spectra of X and Y to the corresponding structures of X and Y. Compound NH2NH2 Compound 'H NMR of X 6 H OH Y 1 H 5H 8. 6. 4 ppm or H NMR of Y 6 H 2H 5H 1 H multiplet multiplet 8. 6. 4. 3. 1 nnm 2. 2. 3, O:arrow_forwardConsider the para-substituted aromatic ketones, NO,CeH,COCH3 (p-nitroacetophenone) and CH30OC,H,COCH3 (p-methoxyacetophenone). a. Which carbonyl compound is more stable? b. Which compound forms the higher percentage of hydrate at equilibrium? c. Which compound exhibits a carbonyl absorption at higher wavenumber in its IR spectrum? Explain your reasoning in each part.arrow_forwardReaction of aldehyde D with amino alcohol E in the presence of NaH forms F (molecular formula C11H15NO2). F absorbs at 1730 cm−1 in its IR spectrum. F also shows eight lines in its 13C NMR spectrum, and gives the following 1H NMR spectrum: 2.32 (singlet, 6 H), 3.05 (triplet, 2 H), 4.20 (triplet, 2 H), 6.97 (doublet, 2 H), 7.82 (doublet, 2 H), and 9.97 (singlet, 1 H) ppm. Propose a structure for F. We will learn about this reaction in Chapter 18.arrow_forward
- Organic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage Learning