MICROELECT. CIRCUIT ANALYSIS&DESIGN (LL)
4th Edition
ISBN: 9781266368622
Author: NEAMEN
Publisher: MCG
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Chapter 14, Problem 14.12EP
To determine
The value Is4 for given condition.
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Choose the correct answer for from the following sentences:
1. The purpose of the microprocessor is to control
b. memory
c. processing
d. tasks
a. switches
2. Which of the following instructions represents base-plus-index addressing mode?
a. MOV AL,[BX] b. MOV AL,[SI] c. MOV AL,BX d. MOV AL,[BX+SI]
3. The BIU pre-fetches the instruction from memory and store them in
b. memory
c. stack
d. queue
a. register
4. Which function is used to control the PWM (Pulse Width Modulation) on the Arduino
output pin?
a. digitalRead() b. analogRead() c. digitalWrite()
5. Which port in the PIC16F877A has an 8 external interrupt inputs?
a. Port-A
b. Port-C
c. Port-B
d. analogWrite()
d. Port-D
d. 4KByte
6. How much Flash EEPROM memory program found in the PIC16F877A microcontroller?
a. 32KByte
b. 16KByte
c. 8KByte
Solve and select the correct answer:
2. For a random variable X with pdf: p(x)
value of x is
=
119
10
for -5≤x≤5. The mean
(a) -75
(b) 10
(c) 0
(d) 75
3. Is the matrix A = = [1] orthogonal? Find the rank of A?
0
(a) YES, -1
(b) NO, 2
(c) YES, 2
(d) NO, -1
4. L{et sin(3t)u(t)) = (a)
s-3
(s-2)²+9
2
(b)
(5-3)² (c)
(s-3)²+4
S-2
3
(s-2)²+9
(d) (5-2)²+9
=
5. Given that x is a constant. Choose all the correct solutions for [∞ (AB)] =
(a) (AB)T (b) x ATBT
(c) α BTAT
(d) x (AB)T
DO NOT WANT AI WILL REJECT
Chapter 14 Solutions
MICROELECT. CIRCUIT ANALYSIS&DESIGN (LL)
Ch. 14 - Using the circuit and transistor parameters of...Ch. 14 - Prob. 14.2TYUCh. 14 - Prob. 14.1EPCh. 14 - Determine the closedloop input resistance at the...Ch. 14 - For a noninverting amplifier, the resistances are...Ch. 14 - An opamp with an openloop gain of AOL=105 is used...Ch. 14 - Prob. 14.3TYUCh. 14 - An operational amplifier connected in a...Ch. 14 - Prob. 14.5TYUCh. 14 - Prob. 14.6TYU
Ch. 14 - Find the closedloop input resistance of a voltage...Ch. 14 - An opamp with openloop parameters of AOL=2105 and...Ch. 14 - A 0.5 V input step function is applied at t=0 to a...Ch. 14 - The slew rate of the 741 opamp is 0.63V/s ....Ch. 14 - Prob. 14.8TYUCh. 14 - Prob. 14.8EPCh. 14 - Consider the active load bipolar duffamp stage in...Ch. 14 - Prob. 14.10EPCh. 14 - Prob. 14.11EPCh. 14 - Prob. 14.12EPCh. 14 - For the opamp circuit shown in Figure 14.28, the...Ch. 14 - Prob. 14.9TYUCh. 14 - List and describe five practical opamp parameters...Ch. 14 - What is atypical value of openloop, lowfrequency...Ch. 14 - Prob. 3RQCh. 14 - Prob. 4RQCh. 14 - Prob. 5RQCh. 14 - Prob. 6RQCh. 14 - Describe the gainbandwidth product property of a...Ch. 14 - Define slew rate and define fullpower bandwidth.Ch. 14 - Prob. 9RQCh. 14 - What is one cause of an offset voltage in the...Ch. 14 - Prob. 11RQCh. 14 - Prob. 12RQCh. 14 - Prob. 13RQCh. 14 - Prob. 14RQCh. 14 - Prob. 15RQCh. 14 - Prob. 16RQCh. 14 - Prob. 17RQCh. 14 - Prob. 14.1PCh. 14 - Consider the opamp described in Problem 14.1. In...Ch. 14 - Data in the following table were taken for several...Ch. 14 - Prob. 14.4PCh. 14 - Prob. 14.5PCh. 14 - Prob. 14.6PCh. 14 - Prob. 14.7PCh. 14 - Prob. 14.8PCh. 14 - An inverting amplifier is fabricated using 0.1...Ch. 14 - For the opamp used in the inverting amplifier...Ch. 14 - Prob. 14.11PCh. 14 - Consider the two inverting amplifiers in cascade...Ch. 14 - The noninverting amplifier in Figure P14.13 has an...Ch. 14 - For the opamp in the voltage follower circuit in...Ch. 14 - The summing amplifier in Figure P14.15 has an...Ch. 14 - Prob. 14.16PCh. 14 - Prob. 14.18PCh. 14 - Prob. 14.19PCh. 14 - Prob. 14.20PCh. 14 - Prob. 14.21PCh. 14 - Prob. 14.22PCh. 14 - Three inverting amplifiers, each with R2=150k and...Ch. 14 - Prob. 14.24PCh. 14 - Prob. 14.25PCh. 14 - Prob. 14.26PCh. 14 - Prob. 14.27PCh. 14 - Prob. D14.28PCh. 14 - Prob. 14.29PCh. 14 - Prob. 14.30PCh. 14 - Prob. 14.31PCh. 14 - Prob. 14.32PCh. 14 - Prob. 14.33PCh. 14 - Prob. 14.34PCh. 14 - Prob. 14.35PCh. 14 - Prob. 14.36PCh. 14 - Prob. 14.37PCh. 14 - In the circuit in Figure P14.38, the offset...Ch. 14 - Prob. 14.39PCh. 14 - Prob. 14.40PCh. 14 - Prob. 14.41PCh. 14 - Prob. 14.42PCh. 14 - Prob. 14.43PCh. 14 - Prob. 14.44PCh. 14 - Prob. 14.46PCh. 14 - Prob. D14.47PCh. 14 - Prob. 14.48PCh. 14 - Prob. 14.50PCh. 14 - Prob. 14.51PCh. 14 - Prob. D14.52PCh. 14 - Prob. D14.53PCh. 14 - Prob. 14.55PCh. 14 - Prob. 14.56PCh. 14 - Prob. 14.57PCh. 14 - The opamp in the difference amplifier...Ch. 14 - Prob. 14.61P
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- 3. Roughly sketch the root locus for the following locations of open-loop poles and zeros. You just need to show the shape of the root locus; you do not calculate the asymptote, break-in, and break-away points. ☑ (a) (b) ☑ Φ ① $3 (c)arrow_forwardDO NOT WANT AI WILL REJECTarrow_forwardDO NOT NEED AI WILL REJECTarrow_forward
- S+4 4. Sketch the root locus for L(s) = (s+6) (s+1)2 using rules 1, 2, and 3. For rule 3, you need to find the value of σ and a for the asymptotes. From the root-locus, explain why the closed-loop system is always stable for any choice of the design parameter K in the range 0 < K < ∞o.arrow_forward2. Consider the following system. K(s+3) (s+4) (s+1)(s+2) Check whether the points below are in the root locus. If the point is in the root locus, then also find what the corresponding gain K. i) ii) -2+j3 -2+1√ √ Hint: First find L(s). Next, in L(s) replace s with the value of the point and then express it in polar format r20 using calculator. The point will be in the root locus if and only if = 180° or odd multiple of 180°. When the point is in the root locus, the corresponding gain K is obtained as K ==arrow_forwardsolve and show workarrow_forward
- Design and find values. please solve ASAP (it's for practice before an exma, I don't have time)arrow_forwardCan you show why the answer is that for this question using second order differential equations, instead of laplace transformsarrow_forward2. For each of the following transfer functions, G(s) = Y(s)/U(s), find the differential equation relating the input u(t) to the output y(t). (s+2)(s+3) (a) G(s) = (s+1)(s+4) (s²+0.4s+1.04) (s+3) (b) G(s)= (s2+0.2s+1)(s+2)(s+4)arrow_forward
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