Chapter 14, Problem 10CPE

To determine

Tofind: the value of $YT$ .

Answer to Problem 10CPE

The value of $YT$ is $12.5$ .

Explanation of Solution

Given information:

the figure provided in the question,

  $RX=18,XS=10\text{ and }RT=35$

Calculation: to find the value of $YT$ ,

Since, $XY\text{ and }ST$ are parallel, so

$\frac{RX}{XS}=\frac{RY}{YT}$

Now, substitute and simplify,

$\begin{array}{l}\frac{RX}{XS}=\frac{RY}{YT}\\ \frac{18}{10}=\frac{35-YT}{YT}\text{ [substitute]}\\ 18YT=350-10YT\text{ [cross multiplication]}\\ 28YT=350\text{ [add]}\\ YT=12.5\text{ [divide]}\end{array}$

Thus, the value if $12.5$ .