Organic Chemistry
11th Edition
ISBN: 9781118133576
Author: T. W. Graham Solomons, Craig Fryhle
Publisher: Wiley, John & Sons, Incorporated
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Chapter 13, Problem 8PP
Interpretation Introduction
Interpretation:
The structures of the compounds, D, E and F are to be predicted for the given reaction scheme.
Concept introduction:
Ultraviolet-visible (UV-Vis) spectroscopy is when
UV-Vis spectroscopy can differentiate between conjugated dienes and other
When an infra-red (IR) radiation is passed through a sample, the energy of the IR radiation is absorbed by the particle. Unlike UV-Vis, the electrons don’t jump to higher orbitals; instead, there is a change in the vibrational energy of the covalent bond within the molecule.
IR spectroscopy is used to find functional groups in a molecule.
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Chapter 13 Solutions
Organic Chemistry
Ch. 13 - Prob. 1PPCh. 13 - Prob. 2PPCh. 13 - Prob. 3PPCh. 13 - Practice Problem 13.4 From each set of resonance...Ch. 13 - Practice Problem 13.5 The following enol (an...Ch. 13 - Prob. 6PPCh. 13 - Practice Problem 13.7
Two compounds, A and B, have...Ch. 13 - Prob. 8PPCh. 13 - Prob. 9PPCh. 13 - Prob. 10PP
Ch. 13 - Prob. 11PPCh. 13 - Prob. 12PPCh. 13 - Prob. 13PPCh. 13 - Prob. 14PPCh. 13 - Prob. 15PPCh. 13 - Practice Problem 13.16
Diels–Alder reactions also...Ch. 13 - Prob. 17PPCh. 13 - Prob. 18PCh. 13 - What product would you expect from the following...Ch. 13 - Prob. 20PCh. 13 - Prob. 21PCh. 13 - Provide the reagents necessary for each of the...Ch. 13 - Prob. 23PCh. 13 - Prob. 24PCh. 13 - Prob. 25PCh. 13 - When 1-pentene reacts with N-bromosuccinimide...Ch. 13 - Prob. 27PCh. 13 - Prob. 28PCh. 13 - Prob. 29PCh. 13 - Prob. 30PCh. 13 - 13.31 Provide a mechanism that explains formation...Ch. 13 - 13.32 Provide a mechanism that explains formation...Ch. 13 - Treating either 1-chloro-3-methyl-2-butene or...Ch. 13 - Prob. 34PCh. 13 - Prob. 35PCh. 13 - Although both 1-bromobutane and 4-bromo-1-butene...Ch. 13 - Prob. 37PCh. 13 - Prob. 38PCh. 13 - Prob. 39PCh. 13 - Prob. 40PCh. 13 - Prob. 41PCh. 13 - Prob. 42PCh. 13 - Prob. 43PCh. 13 - Prob. 44PCh. 13 - 13.44 When furan and maleimide undergo a...Ch. 13 - Two controversial hard insecticides are aldrin and...Ch. 13 - Prob. 47PCh. 13 - Prob. 48PCh. 13 - Prob. 49PCh. 13 - Prob. 50PCh. 13 - Explain the product distribution below based on...Ch. 13 - Mixing furan (Problem 13.44) with maleic anhydride...Ch. 13 - Prob. 53PCh. 13 - Prob. 54PCh. 13 - Prob. 1LGPCh. 13 - Prob. 2LGPCh. 13 - Prob. 1QCh. 13 - Prob. 2QCh. 13 - Prob. 3QCh. 13 - Prob. 4QCh. 13 - Prob. 5Q
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- A compound of formula C6H10O2 shows only two absorptions in the proton NMR: a singlet at 2.67 ppm and a singlet at2.15 ppm. These absorptions have areas in the ratio 2:3. The IR spectrum shows a strong absorption at 1708 cm-1. Proposea structure for this compound.arrow_forwardPropose a structure consistent with each set of data.a. Compound A:Molecular formula: C8H10OIR absorption at 3150–2850 cm–11H NMR data: 1.4 (triplet, 3 H), 3.95 (quartet, 2 H), and 6.8–7.3 (multiplet, 5 H) ppm b. Compound B:Molecular formula: C9H10O2IR absorption at 1669 cm–11H NMR data: 2.5 (singlet, 3 H), 3.8 (singlet, 3 H), 6.9 (doublet, 2 H), and 7.9 (doublet, 2 H) ppmarrow_forwardTreatment of compound E (molecular formula C4H8O2) with excessCH3CH2MgBr yields compound F (molecular formula C6H14O) afterprotonation with H2O. E shows a strong absorption in its IR spectrum at1743 cm−1. F shows a strong IR absorption at 3600−3200 cm−1. The 1HNMR spectral data of E and F are given. What are the structures of E andF?Compound E signals at 1.2 (triplet, 3 H), 2.0 (singlet, 3 H), and 4.1 (quartet, 2 H) ppm Compound F signals at 0.9 (triplet, 6 H), 1.1 (singlet, 3 H), 1.5 (quartet, 4H), and 1.55 (singlet, 1 H) ppmarrow_forward
- (e)&(f) pleasearrow_forward13. (a) Compound C undergoes a reaction with SOC1₂ (or PC15) to yield compound D (Molecular Formula C₁0H₁0OCIBr) which has the following spectral data: Compound D: IR: 1685 cm¹; ¹H NMR: 8 7.84 (d, J = 8 Hz, 2H), 7.60 (d, J=8 Hz, 2H), 3.65 (t, J = 7 Hz, 2H), 3.18 (t, J = 7 Hz, 2H), 2.25 (pentet, J = 7 Hz, 2H) ppm; ¹3C NMR: d 28, 36, 45, 128, 130, 133, 137, 197 ppm; EI MS m/z: 200, 198(1:1), 185, 183 (1:1). Identify compound C from the spectral data of compound B and justify your observation. (b) Differentiate between the following: i) COSY and NOESY ii) COSY 90 and COSY 45arrow_forward13. (a) Compound C undergoes a reaction with SOC12 (or PCls) to yield compound D (Molecular Formula C₁0H₁0OCIBr) which has the following spectral data: Compound D: IR: 1685 cm¹; ¹H NMR: 8 7.84 (d, J = 8 Hz, 2H), 7.60 (d, J = 8 Hz, 2H), 3.65 (t, J = 7 Hz, 2H), 3.18 (t, J = 7 Hz, 2H), 2.25 (pentet, J = 7 Hz, 2H) ppm; ¹³C NMR: d 28, 36, 45, 128, 130, 133, 137, 197 ppm; EI MS m/z: 200, 198(1:1), 185, 183 (1:1). Identify compound C from the spectral data of compound B and justify your observation.arrow_forward
- Paragraph Styles 3.1 I. 6. 8. 1 9 110 11 12 13.1. 14 16. 1 Compound A (C9H180) forms a phenylhydrazone, but it gives a negative Tollens' test. The IR spectrum of A has a strong band near 1710 cm1. The broadband carbon NMR spectrum of A is given below. 4. a) Propose a structure for A and explain how your structure fits the spectral data. b) Propose a mechanism for the formation of phenylhydrazone. CH, A CHISO CH2 CH CDC TMS 220 200 180 160 140 120 100 80 60 40 20 6. (ppm) States)arrow_forward8. (a) Benzene derivatives exhibit medium to strong absorption in UV-region. Explain why aniline and phenoxide ion have strong UV-absorptions.arrow_forwardO PRACTICE PROBLEM 8.14 Starting with any needed alkene (or cycloalkene) and assuming you have deuterioace- tic acid (CH3CO,D) available, outline syntheses of the following deuterium-labeled compounds.s el en olad lo nohibbs ad CH3 (a) (CH3)2CHCH2CH,D (b) (CH3),CHCHDCH3 (c) (+ enantiomer) (d) Assuming you also have available BD3:THF and CH3CO2T, can you suggest a synthesis of the following? hab erl (+ enantiomer)he imo (nwond-ben) CH3 H. (asoholea)arrow_forward
- • PRACTICE PROBLEM 8.24 A, B, and C are alkynes. Elucidate their structures and that of D using the following reaction roadmap. H2, Pt H,, Pt A (C3H14) (C3H14) IR: 3300 cm (1) O3 (2) HOẠC HO, H2, Pt (C3H12) (C3H16) (1) O3 (2) HOAC hol bian vd beeollot Но. ОН AOHarrow_forward13. (a) Compound C undergoes a reaction with SOC12 (or PC15) to yield compound D (Molecular Formula C₁0H10OCIBr) which has the following spectral data: Compound D: IR: 1685 cm ¹; ¹H NMR: 87.84 (d, J = 8 Hz, 2H), 7.60 (d, J = 8 Hz, 2H), 3.65 (t, J = 7 Hz, 2H), 3.18 (t, J = 7 Hz, 2H), 2.25 (pentet, J = 7 Hz, 2H) ppm; ¹³C NMR: d 28, 36, 45, 128, 130, 133, 137, 197 ppm; EI MS m/z: 200, 198(1:1), 185, 183 (1:1). Identify compound C from the spectral data of compound B and justify your observation.arrow_forward8.11 Free radical chlorination of propane using 1 mole of C,H, and 2 moles of chlorine gives a complex mixture of chlorintated products. Careful fractional distillation of the product mixture leads to the isolation of dichlorinated compounds A, B, C and D. Identify the structures using the 'H NMR spectra data below: A = triplet (1.2 ppm, 3H) quintet (1.9 ppm, 2H) triplet (5.8 ppm, 1н) B = doublet (1.4 ppm, 3H) doublet (3.8 ppm, 2H) sextet (4.3 ppm, 1H) C = singlet (2.4 ppm, 6H) D= quintet (2.2 ppm, 2H) triplet (3.7 ppm, 4H)arrow_forward
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