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Practice Problem 13.7
Two compounds, A and B, have the same molecular formula,
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Organic Chemistry
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- Deduce the structure of compound C.arrow_forward14. Compound B has molecular formula C9H12. It shows five signals in the 1H-NMR spectrum - a doublet of integral 6 at 1.22 ppm, a septet of integral 1 at 2.86 ppm, a singlet of integral 1 at 5.34 ppm, a doublet of integral 2 at 6.70 ppm, and a doublet of integral 2 at 7.03 ppm. The 13C-NMR spectrum of B shows six unique signals (23.9, 34.0, 115.7, 128.7, 148.9, and 157.4). Identify B and explain your reasoning.arrow_forwardA compound (L) with the molecular formula C9H10 reacts with bromine and gives an IR absorption spectrum that includes the following absorption peaks: 3035 cm ¹(m), 3020 cm ¹(m), 2925 cm ¹(m), 2853 cm ¹(w), 1640 cm ¹1(m), 990 cm ¹(s), 915 cm ¹(s), 740 cm ¹(s), 695 cm ¹(s). The ¹H NMR spectrum of L consists of: Doublet 3.1 ppm (2H) Multiplet 5.1 ppm Multiplet 7.1 (5H) ppm Multiplet 4.8 ppm Multiplet 5.8 ppm The UV spectrum shows a maximum at 255 nm. Propose a structure for compound L. Edit Drawing harrow_forward
- Treatment of 2-methylpropanenitrile [(CH3)2CHCN] withCH3CH2CH2MgBr, followed by aqueous acid, affords compound V, whichhas molecular formula C7H14O. V has a strong absorption in its IRspectrum at 1713 cm−1, and gives the following 1H NMR data: 0.91(triplet, 3 H), 1.09 (doublet, 6 H), 1.6 (multiplet, 2 H), 2.43 (triplet, 2 H), and2.60 (septet, 1 H) ppm. What is the structure of V?arrow_forwardCompound A has molecular formula C8H18. It shows one singlet in the ¹H-NMR spectrum. Identify A and explain your reasoning. For the toolbar, press ALT+F10 (PC) or ALT+FN+F10 (Mac). BIUS Paragraph V Arial = = = = +8HE {} X² X₂ PR хо 23 V 10pt >¶ ¶< - ABC :3 v V ✓ Ev AV ¶T "Ω Θ I 用く x B Q ► 8. Earrow_forwardDraw the structural formulas of the following compounds and indicate the number of NMR signals that would be expected for each compound. (a) methyl iodide (b) 2,4-dimethylpentane (c) cyclopentane (d) propylene (propene)arrow_forward
- The 'H NMR spectrum of compound A (C3H100) has four signals: a multiplet at 8 = 7.25-7.32 ppm (5 H), a singlet at d = 5.17 ppm (1 H), a quartet at d = 4.98 ppm (1 H), and a doublet at ô = 1.49 ppm (3 H). There are 6 signals in its 13C NMR spectrum. The IR spectrum has a broad absorption in the -3200 cm-1 region. Compound A reacts with KMNO4 in a basic solution followed by acidification to give compound B with the molecular formula C7H6O2. Draw structures for compounds A and B.arrow_forwardProvide the structure of three compounds with the molecular formula C4H,O that give an absorption peak at 1600-1640 cm¹ in the infrared spectrum, but no significant peaks at 3000-3600 cm²¹ or at 1650-1750 cm-¹.arrow_forwardO2N 1 3 7H 6 4 HO 6 8 A Predict the number of signals in the 13C NMR spectrum. Provide a rough sketch of the 13C NMR spectrum of compound A.arrow_forward
- The 1H-NMR spectrum of ethanol shows a triplet at 1.23 ppm, a singlet at 2.61 pm, and a quartet at 3.69 ppm. Assign each signal to the protons it corresponds to in the molecule. Explain the splitting pattern observed for each signal.arrow_forwardThe NMR spectra for compound 1 were acquired in a 7.5 mg / 0.6 mL solution ofCDCl3 and are found in the accompanying file. The 1H are also listedbelow. Identify the name of compound 1 and Provide a full analysis of the NMR spectra for compound 1 with table showing peak name and assignment 1H NMR (400 MHz, CDCl3) δ 7.73 (d, J = 9.5 Hz, 1H), 7.56 (ddd, J = 8.5, 7.5, 1.6 Hz, 1H),7.51 (dd, J = 7.5, 1.6 Hz, 1H), 7.36 (d, J = 8.5 Hz, 1H), 7.30 (dd, J = 8.5, 7.5 Hz, 1H), 6.45(d, J = 9.5 Hz, 1H).arrow_forwardplease help with this, i want to use this to study. please draw a compound given the following infoarrow_forward
- Organic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage Learning