Chapter 13, Problem 45QRT

(a)

Interpretation Introduction

Interpretation:

The mass of $\text{NaCl}$ needed to prepare $\text{250}\text{mL}\text{of }\text{0}\text{.50}\text{M}$$\text{NaCl}$ has to be calculated.

Concept introduction:

Molarity (M): Molarity is number of moles of the solute present in the one liter of the solution.

  $\text{Molarity}\text{=}\frac{\text{Moles}\text{of}\text{solute}}{\text{Volume of solution in L}}$

The number of moles of any substance can be determined using the equation.

  $\text{Number}\text{of}\text{moles}\text{=}\frac{\text{Given}\text{mass}\text{of}\text{the}\text{substance}}{\text{Molar}\text{mass}}$

Moles: One mole is equivalent to the mass of the substance consists of same number of units equal to the atoms present in $\text{12}\text{g}$ of ${}^{\text{12}}\text{C}$.

(b)

Interpretation Introduction

Interpretation:

The mass of ${\text{C}}_{\text{12}}{\text{H}}_{22}{\text{O}}_{11}$ needed to prepare $\text{0}\text{.5}\text{L}\text{of }\text{0}\text{.15}\text{M}$${\text{C}}_{\text{12}}{\text{H}}_{22}{\text{O}}_{11}$ has to be calculated.

Concept introduction:

Refer part (a).

(c)

Interpretation Introduction

Interpretation:

The mass of ${\text{NaHCO}}_{\text{3}}$ needed to prepare $\text{200}\text{mL}\text{of }\text{0}\text{.20}\text{M}$${\text{NaHCO}}_{\text{3}}$ has to be calculated.

Concept introduction:

Refer part (a).