Chapter 13, Problem 55QRT

Interpretation Introduction

Interpretation:

The mass of $\text{KI}$ required to prepare $\text{100mL}$ of $\text{0}\text{.0200}\text{M}$$\text{KI}$ solution and the volume required to produce $\text{250mL}$ of $\text{0}\text{.0010}\text{M}$ have to be calculated.

Concept introduction:

Molarity: Dividing moles of solute by the volume of solution in Liter.

  $\text{Molarity}\text{=}\frac{\text{Moles}\text{of}\text{solute}}{\text{Volume of solution in L}}$.