Chapter 13, Problem 28A

Interpretation Introduction

Interpretation:

The temperature have to be calculated.

Concept Introduction:

The ideal gas law was derived by combining three important laws of the gases. The ideal gas law can be expressed as-

  $\begin{array}{l}V\propto \frac{\mathrm{n}T}{P}\\ \mathrm{PV}=nRT\end{array}$ Where, R is universal gas constant.

The ideal gas law consists of all the variables of a gas such as pressure (P), volume (V), number of moles (n) and temperature (T).

Answer to Problem 28A

The temperature is 654.81 K.

Explanation of Solution

Data given: Mass of nitrogen gas = 16.3 gm

Pressure = 1.25 atm

Volume = 25.0 L

R = 0.082 L atm/mol K

Number of moles of nitrogen $‘n’=\frac{16.3}{28}mol=0.582mol$

  $\begin{array}{l}PV=nRT\\ T=\frac{PV}{nR}\\ =\frac{1.25atm\times 25.0L}{0.582mol\times 0.082Latm/molK}=654.81K\end{array}$