Chapter 13.2, Problem 2RQ

Interpretation Introduction

Interpretation:

The volume of helium gas have to be calculated.

Concept Introduction:

The ideal gas law was derived by combining three important laws of the gases. The ideal gas law can be expressed as-

  $\begin{array}{l}V\propto \frac{\mathrm{n}T}{P}\\ \mathrm{PV}=nRT\end{array}$ Where, R is universal gas constant.

The ideal gas law consists of all the variables of a gas such as pressure (P), volume (V), number of moles (n) and temperature (T).

Answer to Problem 2RQ

The volume of helium gas is 55.91 litre.

Explanation of Solution

Data given: Mass of helium gas = 10 gm

Pressure of the gas = 1.10 atm

Temperature = 27 °C = 300 K

R = 0.082 L atm/mol K

Number of moles of helium ‘n’ = 10/4 = 2.5 mol

  $\begin{array}{l}PV=nRT\\ V=\frac{nRT}{P}=\frac{2.5mol\times 0.082Latm/molK\times 300K}{1.10atm}=55.91L\end{array}$