World of Chemistry, 3rd edition
World of Chemistry, 3rd edition
3rd Edition
ISBN: 9781133109655
Author: Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCoste
Publisher: Brooks / Cole / Cengage Learning
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Chapter 13.3, Problem 5RQ
Interpretation Introduction

Interpretation:

Avogadro’s law of the gas needs to be explained by using kinetic molecular theory.

Concept Introduction:

Kinetic molecular theory is constructed on hypothesis about the behaviour of each particle in a gas.

Avogadro’s law: The volume of a gas increases with increase in the number of moles at constant temperature and pressure.

The relationship between the volume of a gas and the number of moles present in the gas is expressed as-

  VnVn = Constant

When T and P are constant.

Expert Solution & Answer
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Explanation of Solution

When the number of moles of gas molecules increases in a closed container, the chance of collision between the gas molecules with the walls per unit time increases. If the pressure remains constant, the volume must increase to get the bigger surface area so that the molecules strike the walls less frequently. So, increase in the number of moles of gas molecules will increase volume. This is the idea of Avogadro’s law.

So, it can be said that Avogadro’s law of the gas can be explained by using kinetic molecular theory.

Chapter 13 Solutions

World of Chemistry, 3rd edition

Ch. 13.2 - Prob. 4RQCh. 13.2 - Prob. 5RQCh. 13.2 - Prob. 6RQCh. 13.2 - Prob. 7RQCh. 13.2 - Prob. 8RQCh. 13.3 - Prob. 1RQCh. 13.3 - Prob. 2RQCh. 13.3 - Prob. 3RQCh. 13.3 - Prob. 4RQCh. 13.3 - Prob. 5RQCh. 13 - Prob. 1ACh. 13 - Prob. 2ACh. 13 - Prob. 3ACh. 13 - Prob. 4ACh. 13 - Prob. 5ACh. 13 - Prob. 6ACh. 13 - Prob. 7ACh. 13 - Prob. 8ACh. 13 - Prob. 9ACh. 13 - Prob. 10ACh. 13 - Prob. 11ACh. 13 - Prob. 12ACh. 13 - Prob. 13ACh. 13 - Prob. 14ACh. 13 - Prob. 15ACh. 13 - Prob. 16ACh. 13 - Prob. 17ACh. 13 - Prob. 18ACh. 13 - Prob. 19ACh. 13 - Prob. 20ACh. 13 - Prob. 21ACh. 13 - Prob. 22ACh. 13 - Prob. 23ACh. 13 - Prob. 24ACh. 13 - Prob. 25ACh. 13 - Prob. 26ACh. 13 - Prob. 27ACh. 13 - Prob. 28ACh. 13 - Prob. 29ACh. 13 - Prob. 30ACh. 13 - Prob. 31ACh. 13 - Prob. 32ACh. 13 - Prob. 33ACh. 13 - Prob. 34ACh. 13 - Prob. 35ACh. 13 - Prob. 36ACh. 13 - Prob. 37ACh. 13 - Prob. 38ACh. 13 - Prob. 39ACh. 13 - Prob. 40ACh. 13 - Prob. 41ACh. 13 - Prob. 42ACh. 13 - Prob. 43ACh. 13 - Prob. 44ACh. 13 - Prob. 45ACh. 13 - Prob. 46ACh. 13 - Prob. 47ACh. 13 - Prob. 48ACh. 13 - Prob. 49ACh. 13 - Prob. 50ACh. 13 - Prob. 51ACh. 13 - Prob. 52ACh. 13 - Prob. 53ACh. 13 - Prob. 54ACh. 13 - Prob. 55ACh. 13 - Prob. 56ACh. 13 - Prob. 57ACh. 13 - Prob. 58ACh. 13 - Prob. 59ACh. 13 - Prob. 60ACh. 13 - Prob. 61ACh. 13 - Prob. 62ACh. 13 - Prob. 63ACh. 13 - Prob. 64ACh. 13 - Prob. 65ACh. 13 - Prob. 66ACh. 13 - Prob. 67ACh. 13 - Prob. 68ACh. 13 - Prob. 69ACh. 13 - Prob. 70ACh. 13 - Prob. 71ACh. 13 - Prob. 72ACh. 13 - Prob. 73ACh. 13 - Prob. 74ACh. 13 - Prob. 75ACh. 13 - Prob. 76ACh. 13 - Prob. 1STPCh. 13 - Prob. 2STPCh. 13 - Prob. 3STPCh. 13 - Prob. 4STPCh. 13 - Prob. 5STPCh. 13 - Prob. 6STPCh. 13 - Prob. 7STPCh. 13 - Prob. 8STPCh. 13 - Prob. 9STPCh. 13 - Prob. 10STP
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