Chapter 13.2, Problem 4RQ

Interpretation Introduction

Interpretation:

The final pressure of neon gas has to be calculated.

Concept Introduction:

The ideal gas equation can be expressed as-

  $\mathrm{PV}=nRT$ Where, R is universal gas constant.

When ‘n’ remains constant, the ideal gas equation can be written as-

  $\frac{{\mathrm{P}}_1{V}_1}{T_1}=\frac{{\mathrm{P}}_2{V}_2}{T_2}$

Where P₁, V₁ and T₁ are variables of initial state while P₂, V₂ and T₂ are variables of final state.

Answer to Problem 4RQ

The final pressure of neon gas is 2.28 atm.

Explanation of Solution

Data given: P₁ = 5 atm, V₁ = 2.25 L, T₁ = (273 + 95) K = 368 K

V₂ = 4 L and T₂ = (273 + 25) K = 298 K

Putting the values of the variables P₂ can be calculated

  $\begin{array}{l}\frac{P_1{V}_1}{T_1}=\frac{P_2{V}_2}{T_2}\\ P_2=\frac{P_1{V}_1{T}_2}{V_2{T}_1}=\frac{5atm\times 2.25L\times 298K}{4.0L\times 368K}\\ =2.28atm\end{array}$