Chapter 13, Problem 2STP

Interpretation Introduction

Interpretation:

The pressure of the gas have to be calculated.

Concept Introduction:

The ideal gas law was derived by combining three important laws of the gases. The ideal gas law can be expressed as-

  $\begin{array}{l}V\propto \frac{\mathrm{n}T}{P}\\ \mathrm{PV}=nRT\end{array}$ Where, R is universal gas constant.

The ideal gas law consists of all the variables of a gas such as pressure (P), volume (V), number of moles (n) and temperature (T).

Answer to Problem 2STP

The pressure of the gas is-

C. 15.4 atm.

Explanation of Solution

Data given: Number of moles of the gas = 1.80 mole

Volume = 2.92 L

Temperature = 32 °C = (273 + 32) K = 305 K

R = 0.082 L atm/mol K

  $\begin{array}{l}P=\frac{nRT}{V}\\ =\frac{1.80mol\times 0.082Latm/molK\times 305K}{2.92L}\\ =15.42atm\end{array}$

Conclusion

Reasons for incorrect options:

From the calculation we got the pressure of the gas is 15.4 atm.

So the answer is option C.

That means other options that is,

A. 1.62 atm

B. 8.57 atm

D. 22.4 atm are found to be incorrect.