Chemistry: Principles and Practice
3rd Edition
ISBN: 9780534420123
Author: Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher: Cengage Learning
expand_more
expand_more
format_list_bulleted
Videos
Question
Chapter 13, Problem 13.7QE
Interpretation Introduction
Interpretation:
Expression for the half-life of a reaction that has third-order rate law has to be derived.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Chapter 13 Solutions
Chemistry: Principles and Practice
Ch. 13 - Prob. 13.1QECh. 13 - Prob. 13.2QECh. 13 - What is the difference between the integrated and...Ch. 13 - Prob. 13.4QECh. 13 - Explain why half-lives are not normally used to...Ch. 13 - Derive an expression for the half-life of a...Ch. 13 - Prob. 13.7QECh. 13 - Prob. 13.8QECh. 13 - Prob. 13.9QECh. 13 - Prob. 13.10QE
Ch. 13 - Prob. 13.11QECh. 13 - Prob. 13.12QECh. 13 - Prob. 13.13QECh. 13 - Prob. 13.14QECh. 13 - Prob. 13.15QECh. 13 - Prob. 13.16QECh. 13 - Prob. 13.17QECh. 13 - Prob. 13.18QECh. 13 - Prob. 13.19QECh. 13 - Prob. 13.20QECh. 13 - Prob. 13.21QECh. 13 - Prob. 13.22QECh. 13 - Nitrogen monoxide reacts with chlorine to form...Ch. 13 - Prob. 13.24QECh. 13 - Prob. 13.25QECh. 13 - Prob. 13.26QECh. 13 - Prob. 13.27QECh. 13 - Prob. 13.28QECh. 13 - Prob. 13.29QECh. 13 - Prob. 13.30QECh. 13 - Prob. 13.31QECh. 13 - Prob. 13.32QECh. 13 - Prob. 13.33QECh. 13 - Write a rate law for NO3(g) + O2(g) NO2(g) +...Ch. 13 - Prob. 13.35QECh. 13 - Prob. 13.36QECh. 13 - Prob. 13.37QECh. 13 - Rate data were obtained at 25 C for the following...Ch. 13 - Prob. 13.39QECh. 13 - Prob. 13.40QECh. 13 - Prob. 13.41QECh. 13 - Prob. 13.42QECh. 13 - Prob. 13.43QECh. 13 - Prob. 13.44QECh. 13 - Prob. 13.45QECh. 13 - Prob. 13.46QECh. 13 - Prob. 13.47QECh. 13 - Prob. 13.48QECh. 13 - When formic acid is heated, it decomposes to...Ch. 13 - Prob. 13.50QECh. 13 - The half-life of tritium, 3H, is 12.26 years....Ch. 13 - Prob. 13.52QECh. 13 - Prob. 13.53QECh. 13 - Prob. 13.54QECh. 13 - Prob. 13.55QECh. 13 - Prob. 13.56QECh. 13 - The decomposition of ozone is a second-order...Ch. 13 - Prob. 13.58QECh. 13 - Prob. 13.59QECh. 13 - Prob. 13.60QECh. 13 - A reaction rate doubles when the temperature...Ch. 13 - Prob. 13.62QECh. 13 - Prob. 13.63QECh. 13 - Prob. 13.64QECh. 13 - Prob. 13.65QECh. 13 - The activation energy for the decomposition of...Ch. 13 - Prob. 13.67QECh. 13 - Prob. 13.68QECh. 13 - Prob. 13.69QECh. 13 - Prob. 13.70QECh. 13 - Prob. 13.71QECh. 13 - Prob. 13.72QECh. 13 - Prob. 13.73QECh. 13 - Prob. 13.74QECh. 13 - Prob. 13.75QECh. 13 - Prob. 13.76QECh. 13 - Prob. 13.77QECh. 13 - Prob. 13.78QECh. 13 - Prob. 13.79QECh. 13 - Prob. 13.80QECh. 13 - The gas-phase reaction of nitrogen monoxide with...Ch. 13 - Prob. 13.82QECh. 13 - Prob. 13.83QECh. 13 - A catalyst reduces the activation energy of a...Ch. 13 - Prob. 13.85QECh. 13 - Prob. 13.86QECh. 13 - Prob. 13.87QECh. 13 - Prob. 13.88QECh. 13 - Prob. 13.89QECh. 13 - Prob. 13.90QECh. 13 - Prob. 13.91QECh. 13 - Prob. 13.92QECh. 13 - Prob. 13.93QECh. 13 - Prob. 13.94QECh. 13 - Prob. 13.95QECh. 13 - Prob. 13.96QECh. 13 - Prob. 13.98QECh. 13 - Prob. 13.99QE
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.Similar questions
- The decomposition of iodoethane in the gas phase proceeds according to the following equation: C2H5I(g)C2H4(g)+HI(g) At 660. K, k = 7.2 104 sl; at 720. K, k = 1.7 102 sl. What is the value of the rate constant for this first-order decomposition at 325C? If the initial pressure of iodoethane is 894 torr at 245C, what is the pressure of iodoethane after three half-lives?arrow_forwardAt 573 K, gaseous NO2(g) decomposes, forming NO(g) and O2(g). If a vessel containing NO2(g) has an initial concentration of 1.9 102 mol/L, how long will it take for 75% of the NO2(g) to decompose? The decomposition of NO2(g) is second-order in the reactant and the rate constant for this reaction, at 573 K, is 1.1 L/mol s.arrow_forwardThe Raschig reaction produces the industrially important reducing agent hydrazine, N2H4, from ammonia, NH3, and hypochlorite ion, OCl−, in basic aqueous solution. A proposed mechanism is Step 1: Step 2: Step 3: What is the overall stoichiometric equation? Which step is rate-limiting? What reaction intermediates are involved? What rate law is predicted by this mechanism?arrow_forward
- 11.64 HBr is oxidized in the following reaction: 4 HBr(g) + O2(g) —• 2 H2O(g) + 2 Br,(g) A proposed mechanism is HBr + O2 -* HOOBr (slow) HOOBr + HBr — 2 HOBr (fast) HOBr + HBr — H2O + Bn (fast) Show that this mechanism can account for the correct stoichiometry. Identify all intermediates in this mechanism. What is the molecularity of each elementary’ step? Write the rate expression for each elementary' step. Identify the rate-determining step.arrow_forwardThe decomposition of SO2Cl2 is a first-order reaction: SO2Cl2(g) SO2(g) + Cl2(g) The rate constant for the reaction is 2.8 103 min1 at 600 K. If the initial concentration of SO2Cl2 is 1.24 103 mol/L, how long will it take for the concentration to drop to 0.31 103 mol/L?arrow_forwardThe decomposition of N2O5 in CCl4 is a first-order reaction. If 2.56 mg of N2O5 is present initially and 2.50 mg is present after 4.26 minutes at 55 C, what is the value of the rate constant, k?arrow_forward
- The decomposition of azomethane, (CH3)2N2, to nitrogen and ethane gases is a first-order reaction, (CH3)2N2(g)N2(g)+C2H6(g). At a certain temperature, a 29-mg sample of azomethane is reduced to 12 mg in 1.4 s. (a) What is the rate constant k for the decomposition at that temperature? (b) What is the half-life of the decomposition? (c) How long will it take to decompose 78% of the azomethane?arrow_forwardHydrogen peroxide, H2O2(aq), decomposes to H2O() and O2(g) in a reaction that is first-order in H2O2 and has a rate constant k = 1.06 103 min1 at a given temperature. (a) How long will it take for 15% of a sample of H2O2 to decompose? (b) How long will it take for 85% of the sample to decompose?arrow_forwardThe reaction NO(g) + 1/2 Cl2(g) NOCl(g) is first-order in [Cl2] and second-order with respect to [NO]. Under a given set of conditions, the initial rate of this reaction is 620 106 mol/L s. What is the rate of this reaction if the concentration of NO is doubled and the concentration of Cl2 is reduced to half the original value? (a) 6.20 106 mol/L s (b) 124 105 mol/L s (c) 2.48 105 mol/L s (d) 4.96 105 mol/L sarrow_forward
- Hydrogen iodide decomposes when heated, forming H2(g) and I2(g). The rate law for this reaction is [HI]/t = k[HI]2. At 443C, k = 30. L/mol min. If the initial HI(g) concentration is 1.5 102 mol/L, what concentration of HI(g) will remain after 10. minutes?arrow_forwardYou are studying the kinetics of the reaction H2(g) + F2(g) 2HF(g) and you wish to determine a mechanism for the reaction. You run the reaction twice by keeping one reactant at a much higher pressure than the other reactant (this lower-pressure reactant begins at 1.000 atm). Unfortunately, you neglect to record which reactant was at the higher pressure, and you forget which it was later. Your data for the first experiment are: Pressure of HF (atm) Time(min) 0 0 0.300 30.0 0.600 65.8 0.900 110.4 1.200 169.1 1.500 255.9 When you ran the second experiment (in which the higher pressure reactant was run at a much higher pressure), you determine the values of the apparent rate constants to be the same. It also turns out that you find data taken from another person in the lab. This individual found that the reaction proceeds 40.0 times faster at 55C than at 35C. You also know, from the energy-level diagram, that there are three steps to the mechanism, and the first step has the highest activation energy. You look up the bond energies of the species involved and they are (in kJ/mol): H8H (432), F8F (154), and H8F (565). a. Sketch an energy-level diagram (qualitative) that is consistent with the one described previously. Hint: See Exercise 106. b. Develop a reasonable mechanism for the reaction. c. Which reactant was limiting in the experiments?arrow_forwardSucrose, a sugar, decomposes in acid solution to give glucose and fructose. The reaction is first-order in sucrose, and the rate constant at 25 C is k = 0.21 h1. If the initial concentration of sucrose is 0.010 mol/L, what is its concentration after 5.0 h?arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Chemistry for Engineering StudentsChemistryISBN:9781337398909Author:Lawrence S. Brown, Tom HolmePublisher:Cengage Learning
Chemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage Learning
Chemistry & Chemical ReactivityChemistryISBN:9781337399074Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage Learning
Chemistry & Chemical ReactivityChemistryISBN:9781133949640Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage Learning
Chemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage Learning
Chemistry: Principles and PracticeChemistryISBN:9780534420123Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward MercerPublisher:Cengage Learning
Chemistry for Engineering Students
Chemistry
ISBN:9781337398909
Author:Lawrence S. Brown, Tom Holme
Publisher:Cengage Learning
Chemistry: The Molecular Science
Chemistry
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:Cengage Learning
Chemistry & Chemical Reactivity
Chemistry
ISBN:9781337399074
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:Cengage Learning
Chemistry & Chemical Reactivity
Chemistry
ISBN:9781133949640
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:Cengage Learning
Chemistry: Principles and Reactions
Chemistry
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:Cengage Learning
Chemistry: Principles and Practice
Chemistry
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Cengage Learning
Kinetics: Initial Rates and Integrated Rate Laws; Author: Professor Dave Explains;https://www.youtube.com/watch?v=wYqQCojggyM;License: Standard YouTube License, CC-BY