(a) Interpretation: The product should be identified when C H 3 C H = C H C H 3 treated with H C l . Concept Introduction: Alkenes are hydrocarbon molecules that consist a carbon-carbon double bond which has the general formula of C n H 2 n . Alkyl halides are the hydrocarbon molecules which contains halogen atoms within the molecule. Reaction of alkene with H C l will form saturated alkyl halides and the reaction is known as hydro halogenation reaction. Hydro halogenation reaction of alkenes follows the Markovnikov's rule.

Question

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Answer 1

Question

Chapter 13, Problem 13.64P

Interpretation Introduction

(a)

Interpretation:

The product should be identified when CH3CH=CHCH3 treated with HCl.

Concept Introduction:

Alkenes are hydrocarbon molecules that consist a carbon-carbon double bond which has the general formula of CnH2n . Alkyl halides are the hydrocarbon molecules which contains halogen atoms within the molecule.

Reaction of alkene with HCl will form saturated alkyl halides and the reaction is known as hydro halogenation reaction.

Hydro halogenation reaction of alkenes follows the Markovnikov's rule.

Expert Solution

Answer to Problem 13.64P

CH3CH2CHClCH3

Explanation of Solution

Unsaturated CH3CH=CHCH3 , alkene molecule reacts with HCl and form saturated alkyl halides. Bond between hydrogen and chlorine in the HCl , is broken and also a one bond (of double bonded) between two carbon-carbon bond is broken, meanwhile new two bonds of C−Cl and C−H are formed.

Hydro halogenation reaction of alkenes follows the Markovnikov's rule. When addition of HCl molecule to an unsymmetrical alkene, H atom binds to the less substituted carbon atom is known as Markovnikov's rule. This molecule is not falling into the unsymmetrical alkene category, hence; Markovnikov's rule is not applied to this molecule.

Refer to the below reaction;

CH3CH=CHCH3→HClCH3CH2CHClCH3

Interpretation Introduction

(b)

Interpretation:

The product should be identified when C5H8 treated with H2 in the presence of Pd.

= C5H8

Concept Introduction:

Cyclic alkenes are hydrocarbon molecules that consist a carbon-carbon double bond which has the general formula of CnH2(n−m).

Reaction of alkene with H2 in the presence of Pd will form saturated alkanes and the reaction is known as hydrogenation reaction.

Expert Solution

Answer to Problem 13.64P

EBK GENERAL, ORGANIC, & BIOLOGICAL CHEM, Chapter 13, Problem 13.64P , additional homework tip 2

Explanation of Solution

Unsaturated C5H8 , alkene molecule reacts with H2 in the presence of Pd and form saturated alkanes. Bond between two H in the H2 , is broken and also a one bond (of double bonded) between two carbon-carbon bond is broken, meanwhile new two bonds of C−H are formed in the presence of Pd metallic catalyst, which reduce the activation energy of the reaction.

Refer to the below reaction;

EBK GENERAL, ORGANIC, & BIOLOGICAL CHEM, Chapter 13, Problem 13.64P , additional homework tip 3

Interpretation Introduction

(c)

Interpretation:

The product should be identified when C8H14 treated with Cl2.

= C8H14

Concept Introduction:

Cyclic alkenes are hydrocarbon molecules that consist a carbon-carbon double bond which has the general formula of CnH2(n−m) . Dihalides are the molecules which have two halogen atoms in a molecule.

Reaction of alkene with Cl2 will form saturated dihalides and the reaction is known as halogenation reaction.

Expert Solution

Answer to Problem 13.64P

EBK GENERAL, ORGANIC, & BIOLOGICAL CHEM, Chapter 13, Problem 13.64P , additional homework tip 5

Explanation of Solution

Unsaturated C8H14 , alkene molecule reacts with Cl2 and form saturated dihalides. Bond between two Cl in the Cl2 , is broken and also a one bond between (of double bonded) two carbon-carbon bond is broken, meanwhile new two bonds of C−Cl are formed. Refer to the below reaction;

EBK GENERAL, ORGANIC, & BIOLOGICAL CHEM, Chapter 13, Problem 13.64P , additional homework tip 6

Interpretation Introduction

(d)

Interpretation:

The product should be identified when CH3CH=CHCH2CH2CH3 treated with Br2.

Concept Introduction:

Alkenes are hydrocarbon molecules that consist a carbon-carbon double bond which has the general formula of CnH2n . Dihalides are the molecules which have two halogen atoms in a molecule.

Reaction of alkene with Br2 will form saturated dihalides and the reaction is known as halogenation reaction.

Expert Solution

Answer to Problem 13.64P

CH3CHBr−CHBrCH2CH2CH3

Explanation of Solution

Unsaturated CH3CH=CHCH2CH2CH3 , alkene molecule reacts with Br2 and form saturated dihalides. Bond between two Br in the Br2 , is broken and also a one bond (of double bonded) between two carbon-carbon bond is broken, meanwhile new two bonds of C−Br are formed. Refer to the below reaction;

CH3CH=CHCH2CH2CH3→Br2CH3CHBr−CHBrCH2CH2CH3

Interpretation Introduction

(e)

Interpretation:

The product should be identified when (CH3)2C=CHCH2CH3 treated with HBr.

Concept Introduction:

Alkenes are hydrocarbon molecules that consist a carbon-carbon double bond which has the general formula of CnH2n . Alkyl halides are the hydrocarbon molecules which contains halogen atoms within the molecule.

Reaction of alkene with HBr will form saturated alkyl halides and the reaction is known as hydro halogenation reaction.

Hydro halogenation reaction of alkenes follows the Markovnikov's rule.

Expert Solution

Answer to Problem 13.64P

(CH3)2CBrCH2CH2CH3

Explanation of Solution

Unsaturated (CH3)2C=CHCH2CH3 , alkene molecule reacts with HBr and form saturated alkyl halides. Bond between hydrogen and chlorine in the HBr , is broken and also a one bond (of double bonded) between two carbon-carbon bond is broken, meanwhile new two bonds of C−Br and C−H are formed.

Hydro halogenation reaction of alkenes follows the Markovnikov's rule. When addition of HBr molecule to an unsymmetrical alkene, H atom binds to the less substituted carbon atom is known as Markovnikov's rule. This molecule also falls into the unsymmetrical alkene category, hence; Markovnikov's rule is applied to this molecule.

Refer to the below reaction;

(CH3)2C=CHCH2CH3→HBr(CH3)2CBrCH2CH2CH3

Interpretation Introduction

(f)

Interpretation:

The product should be identified when C8H14 treated with H2O and H2SO4.

= C8H14

Concept Introduction:

Cyclic alkenes are hydrocarbon molecules that consist a carbon-carbon double bond which has the general formula of CnH2(n−m) . Alcohols are the hydrocarbon molecules which contains OH group in the molecule.

Reaction of alkene with H2O and H2SO4 will form saturated alcohols and the reaction is known as hydration reaction.

Hydration reaction of alkenes follows the Markovnikov's rule.

Expert Solution

Answer to Problem 13.64P

EBK GENERAL, ORGANIC, & BIOLOGICAL CHEM, Chapter 13, Problem 13.64P , additional homework tip 8

Explanation of Solution

Unsaturated C8H14 , alkene molecule reacts with H2O and H2SO4 , form alcohols. One bond between a hydrogen atom and an oxygen atom in the H2O , is broken and also a one bond between (of double bonded) two carbon-carbon bond is broken, meanwhile new two bonds of C−OH and C−H are formed. Hydrogenation occurs only in the presence of a strong acid such as H2SO4 . Refer to the below reaction;

EBK GENERAL, ORGANIC, & BIOLOGICAL CHEM, Chapter 13, Problem 13.64P , additional homework tip 9

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Answer 2

Question

Chapter 13, Problem 13.64P

Interpretation Introduction

(a)

Interpretation:

The product should be identified when CH3CH=CHCH3 treated with HCl.

Concept Introduction:

Alkenes are hydrocarbon molecules that consist a carbon-carbon double bond which has the general formula of CnH2n . Alkyl halides are the hydrocarbon molecules which contains halogen atoms within the molecule.

Reaction of alkene with HCl will form saturated alkyl halides and the reaction is known as hydro halogenation reaction.

Hydro halogenation reaction of alkenes follows the Markovnikov's rule.

Expert Solution

Answer to Problem 13.64P

CH3CH2CHClCH3

Explanation of Solution

Unsaturated CH3CH=CHCH3 , alkene molecule reacts with HCl and form saturated alkyl halides. Bond between hydrogen and chlorine in the HCl , is broken and also a one bond (of double bonded) between two carbon-carbon bond is broken, meanwhile new two bonds of C−Cl and C−H are formed.

Hydro halogenation reaction of alkenes follows the Markovnikov's rule. When addition of HCl molecule to an unsymmetrical alkene, H atom binds to the less substituted carbon atom is known as Markovnikov's rule. This molecule is not falling into the unsymmetrical alkene category, hence; Markovnikov's rule is not applied to this molecule.

Refer to the below reaction;

CH3CH=CHCH3→HClCH3CH2CHClCH3

Interpretation Introduction

(b)

Interpretation:

The product should be identified when C5H8 treated with H2 in the presence of Pd.

= C5H8

Concept Introduction:

Cyclic alkenes are hydrocarbon molecules that consist a carbon-carbon double bond which has the general formula of CnH2(n−m).

Reaction of alkene with H2 in the presence of Pd will form saturated alkanes and the reaction is known as hydrogenation reaction.

Expert Solution

Answer to Problem 13.64P

EBK GENERAL, ORGANIC, & BIOLOGICAL CHEM, Chapter 13, Problem 13.64P , additional homework tip 2

Explanation of Solution

Unsaturated C5H8 , alkene molecule reacts with H2 in the presence of Pd and form saturated alkanes. Bond between two H in the H2 , is broken and also a one bond (of double bonded) between two carbon-carbon bond is broken, meanwhile new two bonds of C−H are formed in the presence of Pd metallic catalyst, which reduce the activation energy of the reaction.

Refer to the below reaction;

EBK GENERAL, ORGANIC, & BIOLOGICAL CHEM, Chapter 13, Problem 13.64P , additional homework tip 3

Interpretation Introduction

(c)

Interpretation:

The product should be identified when C8H14 treated with Cl2.

= C8H14

Concept Introduction:

Cyclic alkenes are hydrocarbon molecules that consist a carbon-carbon double bond which has the general formula of CnH2(n−m) . Dihalides are the molecules which have two halogen atoms in a molecule.

Reaction of alkene with Cl2 will form saturated dihalides and the reaction is known as halogenation reaction.

Expert Solution

Answer to Problem 13.64P

EBK GENERAL, ORGANIC, & BIOLOGICAL CHEM, Chapter 13, Problem 13.64P , additional homework tip 5

Explanation of Solution

Unsaturated C8H14 , alkene molecule reacts with Cl2 and form saturated dihalides. Bond between two Cl in the Cl2 , is broken and also a one bond between (of double bonded) two carbon-carbon bond is broken, meanwhile new two bonds of C−Cl are formed. Refer to the below reaction;

EBK GENERAL, ORGANIC, & BIOLOGICAL CHEM, Chapter 13, Problem 13.64P , additional homework tip 6

Interpretation Introduction

(d)

Interpretation:

The product should be identified when CH3CH=CHCH2CH2CH3 treated with Br2.

Concept Introduction:

Alkenes are hydrocarbon molecules that consist a carbon-carbon double bond which has the general formula of CnH2n . Dihalides are the molecules which have two halogen atoms in a molecule.

Reaction of alkene with Br2 will form saturated dihalides and the reaction is known as halogenation reaction.

Expert Solution

Answer to Problem 13.64P

CH3CHBr−CHBrCH2CH2CH3

Explanation of Solution

Unsaturated CH3CH=CHCH2CH2CH3 , alkene molecule reacts with Br2 and form saturated dihalides. Bond between two Br in the Br2 , is broken and also a one bond (of double bonded) between two carbon-carbon bond is broken, meanwhile new two bonds of C−Br are formed. Refer to the below reaction;

CH3CH=CHCH2CH2CH3→Br2CH3CHBr−CHBrCH2CH2CH3

Interpretation Introduction

(e)

Interpretation:

The product should be identified when (CH3)2C=CHCH2CH3 treated with HBr.

Concept Introduction:

Alkenes are hydrocarbon molecules that consist a carbon-carbon double bond which has the general formula of CnH2n . Alkyl halides are the hydrocarbon molecules which contains halogen atoms within the molecule.

Reaction of alkene with HBr will form saturated alkyl halides and the reaction is known as hydro halogenation reaction.

Hydro halogenation reaction of alkenes follows the Markovnikov's rule.

Expert Solution

Answer to Problem 13.64P

(CH3)2CBrCH2CH2CH3

Explanation of Solution

Unsaturated (CH3)2C=CHCH2CH3 , alkene molecule reacts with HBr and form saturated alkyl halides. Bond between hydrogen and chlorine in the HBr , is broken and also a one bond (of double bonded) between two carbon-carbon bond is broken, meanwhile new two bonds of C−Br and C−H are formed.

Hydro halogenation reaction of alkenes follows the Markovnikov's rule. When addition of HBr molecule to an unsymmetrical alkene, H atom binds to the less substituted carbon atom is known as Markovnikov's rule. This molecule also falls into the unsymmetrical alkene category, hence; Markovnikov's rule is applied to this molecule.

Refer to the below reaction;

(CH3)2C=CHCH2CH3→HBr(CH3)2CBrCH2CH2CH3

Interpretation Introduction

(f)

Interpretation:

The product should be identified when C8H14 treated with H2O and H2SO4.

= C8H14

Concept Introduction:

Cyclic alkenes are hydrocarbon molecules that consist a carbon-carbon double bond which has the general formula of CnH2(n−m) . Alcohols are the hydrocarbon molecules which contains OH group in the molecule.

Reaction of alkene with H2O and H2SO4 will form saturated alcohols and the reaction is known as hydration reaction.

Hydration reaction of alkenes follows the Markovnikov's rule.

Expert Solution

Answer to Problem 13.64P

EBK GENERAL, ORGANIC, & BIOLOGICAL CHEM, Chapter 13, Problem 13.64P , additional homework tip 8

Explanation of Solution

Unsaturated C8H14 , alkene molecule reacts with H2O and H2SO4 , form alcohols. One bond between a hydrogen atom and an oxygen atom in the H2O , is broken and also a one bond between (of double bonded) two carbon-carbon bond is broken, meanwhile new two bonds of C−OH and C−H are formed. Hydrogenation occurs only in the presence of a strong acid such as H2SO4 . Refer to the below reaction;

EBK GENERAL, ORGANIC, & BIOLOGICAL CHEM, Chapter 13, Problem 13.64P , additional homework tip 9

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Answer 3

Question

Chapter 13, Problem 13.64P

Interpretation Introduction

(a)

Interpretation:

The product should be identified when CH3CH=CHCH3 treated with HCl.

Concept Introduction:

Alkenes are hydrocarbon molecules that consist a carbon-carbon double bond which has the general formula of CnH2n . Alkyl halides are the hydrocarbon molecules which contains halogen atoms within the molecule.

Reaction of alkene with HCl will form saturated alkyl halides and the reaction is known as hydro halogenation reaction.

Hydro halogenation reaction of alkenes follows the Markovnikov's rule.

Expert Solution

Answer to Problem 13.64P

CH3CH2CHClCH3

Explanation of Solution

Unsaturated CH3CH=CHCH3 , alkene molecule reacts with HCl and form saturated alkyl halides. Bond between hydrogen and chlorine in the HCl , is broken and also a one bond (of double bonded) between two carbon-carbon bond is broken, meanwhile new two bonds of C−Cl and C−H are formed.

Hydro halogenation reaction of alkenes follows the Markovnikov's rule. When addition of HCl molecule to an unsymmetrical alkene, H atom binds to the less substituted carbon atom is known as Markovnikov's rule. This molecule is not falling into the unsymmetrical alkene category, hence; Markovnikov's rule is not applied to this molecule.

Refer to the below reaction;

CH3CH=CHCH3→HClCH3CH2CHClCH3

Interpretation Introduction

(b)

Interpretation:

The product should be identified when C5H8 treated with H2 in the presence of Pd.

= C5H8

Concept Introduction:

Cyclic alkenes are hydrocarbon molecules that consist a carbon-carbon double bond which has the general formula of CnH2(n−m).

Reaction of alkene with H2 in the presence of Pd will form saturated alkanes and the reaction is known as hydrogenation reaction.

Expert Solution

Answer to Problem 13.64P

EBK GENERAL, ORGANIC, & BIOLOGICAL CHEM, Chapter 13, Problem 13.64P , additional homework tip 2

Explanation of Solution

Unsaturated C5H8 , alkene molecule reacts with H2 in the presence of Pd and form saturated alkanes. Bond between two H in the H2 , is broken and also a one bond (of double bonded) between two carbon-carbon bond is broken, meanwhile new two bonds of C−H are formed in the presence of Pd metallic catalyst, which reduce the activation energy of the reaction.

Refer to the below reaction;

EBK GENERAL, ORGANIC, & BIOLOGICAL CHEM, Chapter 13, Problem 13.64P , additional homework tip 3

Interpretation Introduction

(c)

Interpretation:

The product should be identified when C8H14 treated with Cl2.

= C8H14

Concept Introduction:

Cyclic alkenes are hydrocarbon molecules that consist a carbon-carbon double bond which has the general formula of CnH2(n−m) . Dihalides are the molecules which have two halogen atoms in a molecule.

Reaction of alkene with Cl2 will form saturated dihalides and the reaction is known as halogenation reaction.

Expert Solution

Answer to Problem 13.64P

EBK GENERAL, ORGANIC, & BIOLOGICAL CHEM, Chapter 13, Problem 13.64P , additional homework tip 5

Explanation of Solution

Unsaturated C8H14 , alkene molecule reacts with Cl2 and form saturated dihalides. Bond between two Cl in the Cl2 , is broken and also a one bond between (of double bonded) two carbon-carbon bond is broken, meanwhile new two bonds of C−Cl are formed. Refer to the below reaction;

EBK GENERAL, ORGANIC, & BIOLOGICAL CHEM, Chapter 13, Problem 13.64P , additional homework tip 6

Interpretation Introduction

(d)

Interpretation:

The product should be identified when CH3CH=CHCH2CH2CH3 treated with Br2.

Concept Introduction:

Alkenes are hydrocarbon molecules that consist a carbon-carbon double bond which has the general formula of CnH2n . Dihalides are the molecules which have two halogen atoms in a molecule.

Reaction of alkene with Br2 will form saturated dihalides and the reaction is known as halogenation reaction.

Expert Solution

Answer to Problem 13.64P

CH3CHBr−CHBrCH2CH2CH3

Explanation of Solution

Unsaturated CH3CH=CHCH2CH2CH3 , alkene molecule reacts with Br2 and form saturated dihalides. Bond between two Br in the Br2 , is broken and also a one bond (of double bonded) between two carbon-carbon bond is broken, meanwhile new two bonds of C−Br are formed. Refer to the below reaction;

CH3CH=CHCH2CH2CH3→Br2CH3CHBr−CHBrCH2CH2CH3

Interpretation Introduction

(e)

Interpretation:

The product should be identified when (CH3)2C=CHCH2CH3 treated with HBr.

Concept Introduction:

Alkenes are hydrocarbon molecules that consist a carbon-carbon double bond which has the general formula of CnH2n . Alkyl halides are the hydrocarbon molecules which contains halogen atoms within the molecule.

Reaction of alkene with HBr will form saturated alkyl halides and the reaction is known as hydro halogenation reaction.

Hydro halogenation reaction of alkenes follows the Markovnikov's rule.

Expert Solution

Answer to Problem 13.64P

(CH3)2CBrCH2CH2CH3

Explanation of Solution

Unsaturated (CH3)2C=CHCH2CH3 , alkene molecule reacts with HBr and form saturated alkyl halides. Bond between hydrogen and chlorine in the HBr , is broken and also a one bond (of double bonded) between two carbon-carbon bond is broken, meanwhile new two bonds of C−Br and C−H are formed.

Hydro halogenation reaction of alkenes follows the Markovnikov's rule. When addition of HBr molecule to an unsymmetrical alkene, H atom binds to the less substituted carbon atom is known as Markovnikov's rule. This molecule also falls into the unsymmetrical alkene category, hence; Markovnikov's rule is applied to this molecule.

Refer to the below reaction;

(CH3)2C=CHCH2CH3→HBr(CH3)2CBrCH2CH2CH3

Interpretation Introduction

(f)

Interpretation:

The product should be identified when C8H14 treated with H2O and H2SO4.

= C8H14

Concept Introduction:

Cyclic alkenes are hydrocarbon molecules that consist a carbon-carbon double bond which has the general formula of CnH2(n−m) . Alcohols are the hydrocarbon molecules which contains OH group in the molecule.

Reaction of alkene with H2O and H2SO4 will form saturated alcohols and the reaction is known as hydration reaction.

Hydration reaction of alkenes follows the Markovnikov's rule.

Expert Solution

Answer to Problem 13.64P

EBK GENERAL, ORGANIC, & BIOLOGICAL CHEM, Chapter 13, Problem 13.64P , additional homework tip 8

Explanation of Solution

Unsaturated C8H14 , alkene molecule reacts with H2O and H2SO4 , form alcohols. One bond between a hydrogen atom and an oxygen atom in the H2O , is broken and also a one bond between (of double bonded) two carbon-carbon bond is broken, meanwhile new two bonds of C−OH and C−H are formed. Hydrogenation occurs only in the presence of a strong acid such as H2SO4 . Refer to the below reaction;

EBK GENERAL, ORGANIC, & BIOLOGICAL CHEM, Chapter 13, Problem 13.64P , additional homework tip 9

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 4

Question

Chapter 13, Problem 13.64P

Interpretation Introduction

(a)

Interpretation:

The product should be identified when CH3CH=CHCH3 treated with HCl.

Concept Introduction:

Alkenes are hydrocarbon molecules that consist a carbon-carbon double bond which has the general formula of CnH2n . Alkyl halides are the hydrocarbon molecules which contains halogen atoms within the molecule.

Reaction of alkene with HCl will form saturated alkyl halides and the reaction is known as hydro halogenation reaction.

Hydro halogenation reaction of alkenes follows the Markovnikov's rule.

Expert Solution

Answer to Problem 13.64P

CH3CH2CHClCH3

Explanation of Solution

Unsaturated CH3CH=CHCH3 , alkene molecule reacts with HCl and form saturated alkyl halides. Bond between hydrogen and chlorine in the HCl , is broken and also a one bond (of double bonded) between two carbon-carbon bond is broken, meanwhile new two bonds of C−Cl and C−H are formed.

Hydro halogenation reaction of alkenes follows the Markovnikov's rule. When addition of HCl molecule to an unsymmetrical alkene, H atom binds to the less substituted carbon atom is known as Markovnikov's rule. This molecule is not falling into the unsymmetrical alkene category, hence; Markovnikov's rule is not applied to this molecule.

Refer to the below reaction;

CH3CH=CHCH3→HClCH3CH2CHClCH3

Interpretation Introduction

(b)

Interpretation:

The product should be identified when C5H8 treated with H2 in the presence of Pd.

= C5H8

Concept Introduction:

Cyclic alkenes are hydrocarbon molecules that consist a carbon-carbon double bond which has the general formula of CnH2(n−m).

Reaction of alkene with H2 in the presence of Pd will form saturated alkanes and the reaction is known as hydrogenation reaction.

Expert Solution

Answer to Problem 13.64P

EBK GENERAL, ORGANIC, & BIOLOGICAL CHEM, Chapter 13, Problem 13.64P , additional homework tip 2

Explanation of Solution

Unsaturated C5H8 , alkene molecule reacts with H2 in the presence of Pd and form saturated alkanes. Bond between two H in the H2 , is broken and also a one bond (of double bonded) between two carbon-carbon bond is broken, meanwhile new two bonds of C−H are formed in the presence of Pd metallic catalyst, which reduce the activation energy of the reaction.

Refer to the below reaction;

EBK GENERAL, ORGANIC, & BIOLOGICAL CHEM, Chapter 13, Problem 13.64P , additional homework tip 3

Interpretation Introduction

(c)

Interpretation:

The product should be identified when C8H14 treated with Cl2.

= C8H14

Concept Introduction:

Cyclic alkenes are hydrocarbon molecules that consist a carbon-carbon double bond which has the general formula of CnH2(n−m) . Dihalides are the molecules which have two halogen atoms in a molecule.

Reaction of alkene with Cl2 will form saturated dihalides and the reaction is known as halogenation reaction.

Expert Solution

Answer to Problem 13.64P

EBK GENERAL, ORGANIC, & BIOLOGICAL CHEM, Chapter 13, Problem 13.64P , additional homework tip 5

Explanation of Solution

Unsaturated C8H14 , alkene molecule reacts with Cl2 and form saturated dihalides. Bond between two Cl in the Cl2 , is broken and also a one bond between (of double bonded) two carbon-carbon bond is broken, meanwhile new two bonds of C−Cl are formed. Refer to the below reaction;

EBK GENERAL, ORGANIC, & BIOLOGICAL CHEM, Chapter 13, Problem 13.64P , additional homework tip 6

Interpretation Introduction

(d)

Interpretation:

The product should be identified when CH3CH=CHCH2CH2CH3 treated with Br2.

Concept Introduction:

Alkenes are hydrocarbon molecules that consist a carbon-carbon double bond which has the general formula of CnH2n . Dihalides are the molecules which have two halogen atoms in a molecule.

Reaction of alkene with Br2 will form saturated dihalides and the reaction is known as halogenation reaction.

Expert Solution

Answer to Problem 13.64P

CH3CHBr−CHBrCH2CH2CH3

Explanation of Solution

Unsaturated CH3CH=CHCH2CH2CH3 , alkene molecule reacts with Br2 and form saturated dihalides. Bond between two Br in the Br2 , is broken and also a one bond (of double bonded) between two carbon-carbon bond is broken, meanwhile new two bonds of C−Br are formed. Refer to the below reaction;

CH3CH=CHCH2CH2CH3→Br2CH3CHBr−CHBrCH2CH2CH3

Interpretation Introduction

(e)

Interpretation:

The product should be identified when (CH3)2C=CHCH2CH3 treated with HBr.

Concept Introduction:

Alkenes are hydrocarbon molecules that consist a carbon-carbon double bond which has the general formula of CnH2n . Alkyl halides are the hydrocarbon molecules which contains halogen atoms within the molecule.

Reaction of alkene with HBr will form saturated alkyl halides and the reaction is known as hydro halogenation reaction.

Hydro halogenation reaction of alkenes follows the Markovnikov's rule.

Expert Solution

Answer to Problem 13.64P

(CH3)2CBrCH2CH2CH3

Explanation of Solution

Unsaturated (CH3)2C=CHCH2CH3 , alkene molecule reacts with HBr and form saturated alkyl halides. Bond between hydrogen and chlorine in the HBr , is broken and also a one bond (of double bonded) between two carbon-carbon bond is broken, meanwhile new two bonds of C−Br and C−H are formed.

Hydro halogenation reaction of alkenes follows the Markovnikov's rule. When addition of HBr molecule to an unsymmetrical alkene, H atom binds to the less substituted carbon atom is known as Markovnikov's rule. This molecule also falls into the unsymmetrical alkene category, hence; Markovnikov's rule is applied to this molecule.

Refer to the below reaction;

(CH3)2C=CHCH2CH3→HBr(CH3)2CBrCH2CH2CH3

Interpretation Introduction

(f)

Interpretation:

The product should be identified when C8H14 treated with H2O and H2SO4.

= C8H14

Concept Introduction:

Cyclic alkenes are hydrocarbon molecules that consist a carbon-carbon double bond which has the general formula of CnH2(n−m) . Alcohols are the hydrocarbon molecules which contains OH group in the molecule.

Reaction of alkene with H2O and H2SO4 will form saturated alcohols and the reaction is known as hydration reaction.

Hydration reaction of alkenes follows the Markovnikov's rule.

Expert Solution

Answer to Problem 13.64P

EBK GENERAL, ORGANIC, & BIOLOGICAL CHEM, Chapter 13, Problem 13.64P , additional homework tip 8

Explanation of Solution

Unsaturated C8H14 , alkene molecule reacts with H2O and H2SO4 , form alcohols. One bond between a hydrogen atom and an oxygen atom in the H2O , is broken and also a one bond between (of double bonded) two carbon-carbon bond is broken, meanwhile new two bonds of C−OH and C−H are formed. Hydrogenation occurs only in the presence of a strong acid such as H2SO4 . Refer to the below reaction;

EBK GENERAL, ORGANIC, & BIOLOGICAL CHEM, Chapter 13, Problem 13.64P , additional homework tip 9

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 5

Chapter 13, Problem 13.64P

Interpretation Introduction

(a)

Interpretation:

The product should be identified when CH3CH=CHCH3 treated with HCl.

Concept Introduction:

Alkenes are hydrocarbon molecules that consist a carbon-carbon double bond which has the general formula of CnH2n . Alkyl halides are the hydrocarbon molecules which contains halogen atoms within the molecule.

Reaction of alkene with HCl will form saturated alkyl halides and the reaction is known as hydro halogenation reaction.

Hydro halogenation reaction of alkenes follows the Markovnikov's rule.

Expert Solution

Answer to Problem 13.64P

CH3CH2CHClCH3

Explanation of Solution

Unsaturated CH3CH=CHCH3 , alkene molecule reacts with HCl and form saturated alkyl halides. Bond between hydrogen and chlorine in the HCl , is broken and also a one bond (of double bonded) between two carbon-carbon bond is broken, meanwhile new two bonds of C−Cl and C−H are formed.

Hydro halogenation reaction of alkenes follows the Markovnikov's rule. When addition of HCl molecule to an unsymmetrical alkene, H atom binds to the less substituted carbon atom is known as Markovnikov's rule. This molecule is not falling into the unsymmetrical alkene category, hence; Markovnikov's rule is not applied to this molecule.

Refer to the below reaction;

CH3CH=CHCH3→HClCH3CH2CHClCH3

Interpretation Introduction

(b)

Interpretation:

The product should be identified when C5H8 treated with H2 in the presence of Pd.

= C5H8

Concept Introduction:

Cyclic alkenes are hydrocarbon molecules that consist a carbon-carbon double bond which has the general formula of CnH2(n−m).

Reaction of alkene with H2 in the presence of Pd will form saturated alkanes and the reaction is known as hydrogenation reaction.

Expert Solution

Answer to Problem 13.64P

EBK GENERAL, ORGANIC, & BIOLOGICAL CHEM, Chapter 13, Problem 13.64P , additional homework tip 2

Explanation of Solution

Unsaturated C5H8 , alkene molecule reacts with H2 in the presence of Pd and form saturated alkanes. Bond between two H in the H2 , is broken and also a one bond (of double bonded) between two carbon-carbon bond is broken, meanwhile new two bonds of C−H are formed in the presence of Pd metallic catalyst, which reduce the activation energy of the reaction.

Refer to the below reaction;

EBK GENERAL, ORGANIC, & BIOLOGICAL CHEM, Chapter 13, Problem 13.64P , additional homework tip 3

Interpretation Introduction

(c)

Interpretation:

The product should be identified when C8H14 treated with Cl2.

= C8H14

Concept Introduction:

Cyclic alkenes are hydrocarbon molecules that consist a carbon-carbon double bond which has the general formula of CnH2(n−m) . Dihalides are the molecules which have two halogen atoms in a molecule.

Reaction of alkene with Cl2 will form saturated dihalides and the reaction is known as halogenation reaction.

Expert Solution

Answer to Problem 13.64P

EBK GENERAL, ORGANIC, & BIOLOGICAL CHEM, Chapter 13, Problem 13.64P , additional homework tip 5

Explanation of Solution

Unsaturated C8H14 , alkene molecule reacts with Cl2 and form saturated dihalides. Bond between two Cl in the Cl2 , is broken and also a one bond between (of double bonded) two carbon-carbon bond is broken, meanwhile new two bonds of C−Cl are formed. Refer to the below reaction;

EBK GENERAL, ORGANIC, & BIOLOGICAL CHEM, Chapter 13, Problem 13.64P , additional homework tip 6

Interpretation Introduction

(d)

Interpretation:

The product should be identified when CH3CH=CHCH2CH2CH3 treated with Br2.

Concept Introduction:

Alkenes are hydrocarbon molecules that consist a carbon-carbon double bond which has the general formula of CnH2n . Dihalides are the molecules which have two halogen atoms in a molecule.

Reaction of alkene with Br2 will form saturated dihalides and the reaction is known as halogenation reaction.

Expert Solution

Answer to Problem 13.64P

CH3CHBr−CHBrCH2CH2CH3

Explanation of Solution

Unsaturated CH3CH=CHCH2CH2CH3 , alkene molecule reacts with Br2 and form saturated dihalides. Bond between two Br in the Br2 , is broken and also a one bond (of double bonded) between two carbon-carbon bond is broken, meanwhile new two bonds of C−Br are formed. Refer to the below reaction;

CH3CH=CHCH2CH2CH3→Br2CH3CHBr−CHBrCH2CH2CH3

Interpretation Introduction

(e)

Interpretation:

The product should be identified when (CH3)2C=CHCH2CH3 treated with HBr.

Concept Introduction:

Alkenes are hydrocarbon molecules that consist a carbon-carbon double bond which has the general formula of CnH2n . Alkyl halides are the hydrocarbon molecules which contains halogen atoms within the molecule.

Reaction of alkene with HBr will form saturated alkyl halides and the reaction is known as hydro halogenation reaction.

Hydro halogenation reaction of alkenes follows the Markovnikov's rule.

Expert Solution

Answer to Problem 13.64P

(CH3)2CBrCH2CH2CH3

Explanation of Solution

Unsaturated (CH3)2C=CHCH2CH3 , alkene molecule reacts with HBr and form saturated alkyl halides. Bond between hydrogen and chlorine in the HBr , is broken and also a one bond (of double bonded) between two carbon-carbon bond is broken, meanwhile new two bonds of C−Br and C−H are formed.

Hydro halogenation reaction of alkenes follows the Markovnikov's rule. When addition of HBr molecule to an unsymmetrical alkene, H atom binds to the less substituted carbon atom is known as Markovnikov's rule. This molecule also falls into the unsymmetrical alkene category, hence; Markovnikov's rule is applied to this molecule.

Refer to the below reaction;

(CH3)2C=CHCH2CH3→HBr(CH3)2CBrCH2CH2CH3

Interpretation Introduction

(f)

Interpretation:

The product should be identified when C8H14 treated with H2O and H2SO4.

= C8H14

Concept Introduction:

Cyclic alkenes are hydrocarbon molecules that consist a carbon-carbon double bond which has the general formula of CnH2(n−m) . Alcohols are the hydrocarbon molecules which contains OH group in the molecule.

Reaction of alkene with H2O and H2SO4 will form saturated alcohols and the reaction is known as hydration reaction.

Hydration reaction of alkenes follows the Markovnikov's rule.

Expert Solution

Answer to Problem 13.64P

EBK GENERAL, ORGANIC, & BIOLOGICAL CHEM, Chapter 13, Problem 13.64P , additional homework tip 8

Explanation of Solution

Unsaturated C8H14 , alkene molecule reacts with H2O and H2SO4 , form alcohols. One bond between a hydrogen atom and an oxygen atom in the H2O , is broken and also a one bond between (of double bonded) two carbon-carbon bond is broken, meanwhile new two bonds of C−OH and C−H are formed. Hydrogenation occurs only in the presence of a strong acid such as H2SO4 . Refer to the below reaction;

EBK GENERAL, ORGANIC, & BIOLOGICAL CHEM, Chapter 13, Problem 13.64P , additional homework tip 9

Answer 6

Chapter 13, Problem 13.64P

Interpretation Introduction

(a)

Interpretation:

The product should be identified when CH3CH=CHCH3 treated with HCl.

Concept Introduction:

Alkenes are hydrocarbon molecules that consist a carbon-carbon double bond which has the general formula of CnH2n . Alkyl halides are the hydrocarbon molecules which contains halogen atoms within the molecule.

Reaction of alkene with HCl will form saturated alkyl halides and the reaction is known as hydro halogenation reaction.

Hydro halogenation reaction of alkenes follows the Markovnikov's rule.

Expert Solution

Answer to Problem 13.64P

CH3CH2CHClCH3

Explanation of Solution

Unsaturated CH3CH=CHCH3 , alkene molecule reacts with HCl and form saturated alkyl halides. Bond between hydrogen and chlorine in the HCl , is broken and also a one bond (of double bonded) between two carbon-carbon bond is broken, meanwhile new two bonds of C−Cl and C−H are formed.

Hydro halogenation reaction of alkenes follows the Markovnikov's rule. When addition of HCl molecule to an unsymmetrical alkene, H atom binds to the less substituted carbon atom is known as Markovnikov's rule. This molecule is not falling into the unsymmetrical alkene category, hence; Markovnikov's rule is not applied to this molecule.

Refer to the below reaction;

CH3CH=CHCH3→HClCH3CH2CHClCH3

Answer 7

Chapter 13, Problem 13.64P

Interpretation Introduction

(a)

Interpretation:

The product should be identified when CH3CH=CHCH3 treated with HCl.

Concept Introduction:

Alkenes are hydrocarbon molecules that consist a carbon-carbon double bond which has the general formula of CnH2n . Alkyl halides are the hydrocarbon molecules which contains halogen atoms within the molecule.

Reaction of alkene with HCl will form saturated alkyl halides and the reaction is known as hydro halogenation reaction.

Hydro halogenation reaction of alkenes follows the Markovnikov's rule.

Answer 8

Expert Solution

Answer to Problem 13.64P

CH3CH2CHClCH3

Answer 9

Expert Solution

Answer 10

Expert Solution

Answer 11

Expert Solution

Answer 12

Explanation of Solution

Unsaturated CH3CH=CHCH3 , alkene molecule reacts with HCl and form saturated alkyl halides. Bond between hydrogen and chlorine in the HCl , is broken and also a one bond (of double bonded) between two carbon-carbon bond is broken, meanwhile new two bonds of C−Cl and C−H are formed.

Hydro halogenation reaction of alkenes follows the Markovnikov's rule. When addition of HCl molecule to an unsymmetrical alkene, H atom binds to the less substituted carbon atom is known as Markovnikov's rule. This molecule is not falling into the unsymmetrical alkene category, hence; Markovnikov's rule is not applied to this molecule.

Refer to the below reaction;

CH3CH=CHCH3→HClCH3CH2CHClCH3

Answer 13

Interpretation Introduction

(b)

Interpretation:

The product should be identified when C5H8 treated with H2 in the presence of Pd.

= C5H8

Concept Introduction:

Cyclic alkenes are hydrocarbon molecules that consist a carbon-carbon double bond which has the general formula of CnH2(n−m).

Reaction of alkene with H2 in the presence of Pd will form saturated alkanes and the reaction is known as hydrogenation reaction.

Expert Solution

Answer to Problem 13.64P

EBK GENERAL, ORGANIC, & BIOLOGICAL CHEM, Chapter 13, Problem 13.64P , additional homework tip 2

Explanation of Solution

Unsaturated C5H8 , alkene molecule reacts with H2 in the presence of Pd and form saturated alkanes. Bond between two H in the H2 , is broken and also a one bond (of double bonded) between two carbon-carbon bond is broken, meanwhile new two bonds of C−H are formed in the presence of Pd metallic catalyst, which reduce the activation energy of the reaction.

Refer to the below reaction;

EBK GENERAL, ORGANIC, & BIOLOGICAL CHEM, Chapter 13, Problem 13.64P , additional homework tip 3

Answer 14

Interpretation Introduction

(b)

Interpretation:

The product should be identified when C5H8 treated with H2 in the presence of Pd.

= C5H8

Concept Introduction:

Cyclic alkenes are hydrocarbon molecules that consist a carbon-carbon double bond which has the general formula of CnH2(n−m).

Reaction of alkene with H2 in the presence of Pd will form saturated alkanes and the reaction is known as hydrogenation reaction.

Answer 15

Expert Solution

Answer to Problem 13.64P

EBK GENERAL, ORGANIC, & BIOLOGICAL CHEM, Chapter 13, Problem 13.64P , additional homework tip 2

Answer 16

Expert Solution

Answer 17

Expert Solution

Answer 18

Expert Solution

Answer 19

Explanation of Solution

Unsaturated C5H8 , alkene molecule reacts with H2 in the presence of Pd and form saturated alkanes. Bond between two H in the H2 , is broken and also a one bond (of double bonded) between two carbon-carbon bond is broken, meanwhile new two bonds of C−H are formed in the presence of Pd metallic catalyst, which reduce the activation energy of the reaction.

Refer to the below reaction;

EBK GENERAL, ORGANIC, & BIOLOGICAL CHEM, Chapter 13, Problem 13.64P , additional homework tip 3

Answer 20

Interpretation Introduction

(c)

Interpretation:

The product should be identified when C8H14 treated with Cl2.

= C8H14

Concept Introduction:

Cyclic alkenes are hydrocarbon molecules that consist a carbon-carbon double bond which has the general formula of CnH2(n−m) . Dihalides are the molecules which have two halogen atoms in a molecule.

Reaction of alkene with Cl2 will form saturated dihalides and the reaction is known as halogenation reaction.

Expert Solution

Answer to Problem 13.64P

EBK GENERAL, ORGANIC, & BIOLOGICAL CHEM, Chapter 13, Problem 13.64P , additional homework tip 5

Explanation of Solution

Unsaturated C8H14 , alkene molecule reacts with Cl2 and form saturated dihalides. Bond between two Cl in the Cl2 , is broken and also a one bond between (of double bonded) two carbon-carbon bond is broken, meanwhile new two bonds of C−Cl are formed. Refer to the below reaction;

EBK GENERAL, ORGANIC, & BIOLOGICAL CHEM, Chapter 13, Problem 13.64P , additional homework tip 6

Answer 21

Interpretation Introduction

(c)

Interpretation:

The product should be identified when C8H14 treated with Cl2.

= C8H14

Concept Introduction:

Cyclic alkenes are hydrocarbon molecules that consist a carbon-carbon double bond which has the general formula of CnH2(n−m) . Dihalides are the molecules which have two halogen atoms in a molecule.

Reaction of alkene with Cl2 will form saturated dihalides and the reaction is known as halogenation reaction.

Answer 22

Expert Solution

Answer to Problem 13.64P

EBK GENERAL, ORGANIC, & BIOLOGICAL CHEM, Chapter 13, Problem 13.64P , additional homework tip 5

Answer 23

Expert Solution

Answer 24

Expert Solution

Answer 25

Expert Solution

Answer 26

Explanation of Solution

Unsaturated C8H14 , alkene molecule reacts with Cl2 and form saturated dihalides. Bond between two Cl in the Cl2 , is broken and also a one bond between (of double bonded) two carbon-carbon bond is broken, meanwhile new two bonds of C−Cl are formed. Refer to the below reaction;

EBK GENERAL, ORGANIC, & BIOLOGICAL CHEM, Chapter 13, Problem 13.64P , additional homework tip 6

Answer 27

Interpretation Introduction

(d)

Interpretation:

The product should be identified when CH3CH=CHCH2CH2CH3 treated with Br2.

Concept Introduction:

Alkenes are hydrocarbon molecules that consist a carbon-carbon double bond which has the general formula of CnH2n . Dihalides are the molecules which have two halogen atoms in a molecule.

Reaction of alkene with Br2 will form saturated dihalides and the reaction is known as halogenation reaction.

Expert Solution

Answer to Problem 13.64P

CH3CHBr−CHBrCH2CH2CH3

Explanation of Solution

Unsaturated CH3CH=CHCH2CH2CH3 , alkene molecule reacts with Br2 and form saturated dihalides. Bond between two Br in the Br2 , is broken and also a one bond (of double bonded) between two carbon-carbon bond is broken, meanwhile new two bonds of C−Br are formed. Refer to the below reaction;

CH3CH=CHCH2CH2CH3→Br2CH3CHBr−CHBrCH2CH2CH3

Answer 28

Interpretation Introduction

(d)

Interpretation:

The product should be identified when CH3CH=CHCH2CH2CH3 treated with Br2.

Concept Introduction:

Alkenes are hydrocarbon molecules that consist a carbon-carbon double bond which has the general formula of CnH2n . Dihalides are the molecules which have two halogen atoms in a molecule.

Reaction of alkene with Br2 will form saturated dihalides and the reaction is known as halogenation reaction.

Answer 29

Expert Solution

Answer to Problem 13.64P

CH3CHBr−CHBrCH2CH2CH3

Answer 30

Expert Solution

Answer 31

Expert Solution

Answer 32

Expert Solution

Answer 33

Explanation of Solution

Unsaturated CH3CH=CHCH2CH2CH3 , alkene molecule reacts with Br2 and form saturated dihalides. Bond between two Br in the Br2 , is broken and also a one bond (of double bonded) between two carbon-carbon bond is broken, meanwhile new two bonds of C−Br are formed. Refer to the below reaction;

CH3CH=CHCH2CH2CH3→Br2CH3CHBr−CHBrCH2CH2CH3

Answer 34

Interpretation Introduction

(e)

Interpretation:

The product should be identified when (CH3)2C=CHCH2CH3 treated with HBr.

Concept Introduction:

Alkenes are hydrocarbon molecules that consist a carbon-carbon double bond which has the general formula of CnH2n . Alkyl halides are the hydrocarbon molecules which contains halogen atoms within the molecule.

Reaction of alkene with HBr will form saturated alkyl halides and the reaction is known as hydro halogenation reaction.

Hydro halogenation reaction of alkenes follows the Markovnikov's rule.

Expert Solution

Answer to Problem 13.64P

(CH3)2CBrCH2CH2CH3

Explanation of Solution

Unsaturated (CH3)2C=CHCH2CH3 , alkene molecule reacts with HBr and form saturated alkyl halides. Bond between hydrogen and chlorine in the HBr , is broken and also a one bond (of double bonded) between two carbon-carbon bond is broken, meanwhile new two bonds of C−Br and C−H are formed.

Hydro halogenation reaction of alkenes follows the Markovnikov's rule. When addition of HBr molecule to an unsymmetrical alkene, H atom binds to the less substituted carbon atom is known as Markovnikov's rule. This molecule also falls into the unsymmetrical alkene category, hence; Markovnikov's rule is applied to this molecule.

Refer to the below reaction;

(CH3)2C=CHCH2CH3→HBr(CH3)2CBrCH2CH2CH3

Answer 35

Interpretation Introduction

(e)

Interpretation:

The product should be identified when (CH3)2C=CHCH2CH3 treated with HBr.

Concept Introduction:

Alkenes are hydrocarbon molecules that consist a carbon-carbon double bond which has the general formula of CnH2n . Alkyl halides are the hydrocarbon molecules which contains halogen atoms within the molecule.

Reaction of alkene with HBr will form saturated alkyl halides and the reaction is known as hydro halogenation reaction.

Hydro halogenation reaction of alkenes follows the Markovnikov's rule.

Answer 36

Expert Solution

Answer to Problem 13.64P

(CH3)2CBrCH2CH2CH3

Answer 37

Expert Solution

Answer 38

Expert Solution

Answer 39

Expert Solution

Answer 40

Explanation of Solution

Unsaturated (CH3)2C=CHCH2CH3 , alkene molecule reacts with HBr and form saturated alkyl halides. Bond between hydrogen and chlorine in the HBr , is broken and also a one bond (of double bonded) between two carbon-carbon bond is broken, meanwhile new two bonds of C−Br and C−H are formed.

Hydro halogenation reaction of alkenes follows the Markovnikov's rule. When addition of HBr molecule to an unsymmetrical alkene, H atom binds to the less substituted carbon atom is known as Markovnikov's rule. This molecule also falls into the unsymmetrical alkene category, hence; Markovnikov's rule is applied to this molecule.

Refer to the below reaction;

(CH3)2C=CHCH2CH3→HBr(CH3)2CBrCH2CH2CH3

Answer 41

Interpretation Introduction

(f)

Interpretation:

The product should be identified when C8H14 treated with H2O and H2SO4.

= C8H14

Concept Introduction:

Cyclic alkenes are hydrocarbon molecules that consist a carbon-carbon double bond which has the general formula of CnH2(n−m) . Alcohols are the hydrocarbon molecules which contains OH group in the molecule.

Reaction of alkene with H2O and H2SO4 will form saturated alcohols and the reaction is known as hydration reaction.

Hydration reaction of alkenes follows the Markovnikov's rule.

Expert Solution

Answer to Problem 13.64P

EBK GENERAL, ORGANIC, & BIOLOGICAL CHEM, Chapter 13, Problem 13.64P , additional homework tip 8

Explanation of Solution

Unsaturated C8H14 , alkene molecule reacts with H2O and H2SO4 , form alcohols. One bond between a hydrogen atom and an oxygen atom in the H2O , is broken and also a one bond between (of double bonded) two carbon-carbon bond is broken, meanwhile new two bonds of C−OH and C−H are formed. Hydrogenation occurs only in the presence of a strong acid such as H2SO4 . Refer to the below reaction;

EBK GENERAL, ORGANIC, & BIOLOGICAL CHEM, Chapter 13, Problem 13.64P , additional homework tip 9

Answer 42

Interpretation Introduction

(f)

Interpretation:

The product should be identified when C8H14 treated with H2O and H2SO4.

= C8H14

Concept Introduction:

Cyclic alkenes are hydrocarbon molecules that consist a carbon-carbon double bond which has the general formula of CnH2(n−m) . Alcohols are the hydrocarbon molecules which contains OH group in the molecule.

Reaction of alkene with H2O and H2SO4 will form saturated alcohols and the reaction is known as hydration reaction.

Hydration reaction of alkenes follows the Markovnikov's rule.

Answer 43

Expert Solution

Answer to Problem 13.64P

EBK GENERAL, ORGANIC, & BIOLOGICAL CHEM, Chapter 13, Problem 13.64P , additional homework tip 8

Answer 44

Expert Solution

Answer 45

Expert Solution

Answer 46

Expert Solution

Answer 47

Explanation of Solution

Unsaturated C8H14 , alkene molecule reacts with H2O and H2SO4 , form alcohols. One bond between a hydrogen atom and an oxygen atom in the H2O , is broken and also a one bond between (of double bonded) two carbon-carbon bond is broken, meanwhile new two bonds of C−OH and C−H are formed. Hydrogenation occurs only in the presence of a strong acid such as H2SO4 . Refer to the below reaction;