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Concept explainers
12-27 Explain why each name is incorrect and then write a correct name.
- 2-Ethyl-l-propene
- 5-lsopropylcyclohexene
- 4-Methyl-4-hexene
- 2-sec-Butyl-l-butene
- 6,6-Dimethylcyclohexene
- 2-Ethyl-2-hexene
![Check Mark](/static/check-mark.png)
(a)
Interpretation:
To identify the error in name of the given compound and write the correct IUPAC names.
Concept Introduction:
The rules to write the IUPAC names are as follows-
- The longest carbon chain is identified, and the root name is given accordingly.
- All the substituents attached to the root chain are determined.
- The position of the substituents is so assigned that the sum of their positions comes to be the least of all possible positions.
- The prefix di, tri, tetra is used if the same substituent is present two, three and four times respectively.
- All the substituents in the name are written in alphabetical order.
- For a cyclic hydrocarbon the prefix cyclo- is used.
Answer to Problem 17P
2-Methyl-but-1-ene.
Explanation of Solution
2-Ethyl-1-propene.
Error- longest chain not correctly located.
Correct name-
2-Methyl-but-1-ene.
![Check Mark](/static/check-mark.png)
(b)
Interpretation:
To identify the error in name of the given compound and write the correct IUPAC names.
Concept Introduction:
The rules to write the IUPAC names are as follows-
- The longest carbon chain is identified, and the root name is given accordingly.
- All the substituents attached to the root chain are determined.
- The position of the substituents is so assigned that the sum of their positions comes to be the least of all possible positions.
- The prefix di, tri, tetra is used if the same substituent is present two, three and four times respectively.
- All the substituents in the name are written in alphabetical order.
- For a cyclic hydrocarbon the prefix cyclo- is used.
Answer to Problem 17P
4-Isopropylcyclohexene.
Explanation of Solution
5-Isopropylcyclohexene.
Error- position of the substituent not correctly mentioned.
Correct name-
4-Isopropylcyclohexene.
![Check Mark](/static/check-mark.png)
(c)
Interpretation:
To identify the error in name of the given compound and write the correct IUPAC names.
Concept Introduction:
The rules to write the IUPAC names are as follows-
- The longest carbon chain is identified, and the root name is given accordingly.
- All the substituents attached to the root chain are determined.
- The position of the substituents is so assigned that the sum of their positions comes to be the least of all possible positions.
- The prefix di, tri, tetra is used if the same substituent is present two, three and four times respectively.
- All the substituents in the name are written in alphabetical order.
- For a cyclic hydrocarbon the prefix cyclo- is used.
Answer to Problem 17P
3-Methyl-2-hexene.
Explanation of Solution
4-Methyl-4-hexene.
Error- position of the double bond not correctly mentioned.
Correct name-
3-Methyl-2-hexene.
![Check Mark](/static/check-mark.png)
(d)
Interpretation:
To identify the error in name of the given compound and write the correct IUPAC names.
Concept Introduction:
The rules to write the IUPAC names are as follows-
- The longest carbon chain is identified, and the root name is given accordingly.
- All the substituents attached to the root chain are determined.
- The position of the substituents is so assigned that the sum of their positions comes to be the least of all possible positions.
- The prefix di, tri, tetra is used if the same substituent is present two, three and four times respectively.
- All the substituents in the name are written in alphabetical order.
- For a cyclic hydrocarbon the prefix cyclo- is used.
Answer to Problem 17P
2-Ethyl-3-methyl -1-pentene.
Explanation of Solution
2-sec-butyl-1-butene.
Error- longest chain not correctly determined.
Correct name-
2-Ethyl-3-methyl -1-pentene.
![Check Mark](/static/check-mark.png)
(e)
Interpretation:
To identify the error in name of the given compound and write the correct IUPAC names.
Concept Introduction:
The rules to write the IUPAC names are as follows-
- The longest carbon chain is identified, and the root name is given accordingly.
- All the substituents attached to the root chain are determined.
- The position of the substituents is so assigned that the sum of their positions comes to be the least of all possible positions.
- The prefix di, tri, tetra is used if the same substituent is present two, three and four times respectively.
- All the substituents in the name are written in alphabetical order.
- For a cyclic hydrocarbon the prefix cyclo- is used.
Answer to Problem 17P
3,3-Dimethylcyclohexene.
Explanation of Solution
6,6-Dimethylcyclohexene.
Error- position of substituents not correctly determined.
Correct name-
3,3-Dimethylcyclohexene.
![Check Mark](/static/check-mark.png)
(f)
Interpretation:
To identify the error in name of the given compound and write the correct IUPAC names.
Concept Introduction:
The rules to write the IUPAC names are as follows-
- The longest carbon chain is identified, and the root name is given accordingly.
- All the substituents attached to the root chain are determined.
- The position of the substituents is so assigned that the sum of their positions comes to be the least of all possible positions.
- The prefix di, tri, tetra is used if the same substituent is present two, three and four times respectively.
- All the substituents in the name are written in alphabetical order.
- For a cyclic hydrocarbon the prefix cyclo- is used.
Answer to Problem 17P
3-Methyl-3-Heptene.
Explanation of Solution
2-Ethyl-2-hexene.
Error- longest chain not correctly determined.
Correct name-
3-Methyl-3-Heptene.
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Chapter 12 Solutions
Introduction To General, Organic, And Biochemistry
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- 5. The existence of compounds of the noble gases was once a great surprise and stimulated a great deal of theoretical work. Label the molecular orbital diagram for XeF (include atom chemical symbol, atomic orbitals, and molecular orbitals) and deduce its ground state electron configuration. Is XeF likely to have a shorter bond length than XeF+? Bond Order XeF XeF+arrow_forward6. Draw the molecular orbital diagram shown to determine which of the following is paramagnetic. B22+ B22+, B2, C22, B22 and N22+ Molecular Orbital Diagram B2 C22- B22- N22+ Which molecule is paramagnetic?arrow_forward3. Put the following species in order of increasing bond length by using molecular orbital diagrams and calculating their bond orders: F2, F2, F2+ Molecular Orbital Diagram F2 F2 F2+ Bond Order Shortest bond: Longest bondarrow_forward
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