Chemistry In Focus
Chemistry In Focus
6th Edition
ISBN: 9781305084476
Author: Tro, Nivaldo J., Neu, Don.
Publisher: Cengage Learning
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Chapter 12, Problem 12.6YT
Interpretation Introduction

Interpretation:

The concentration of sodium fluoride in parts per million is to be calculated.

Concept Introduction:

Concentration of a solution can be calculated in parts per million with the help of the masses of solute and solution.

Concentration of a solution in parts per million is expressed as follows:

ppm=Grams soluteGrams solution×106

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Chapter 12 Solutions

Chemistry In Focus

Ch. 12 - A representation of liquid water is shown below....Ch. 12 - Prob. 3SCCh. 12 - Prob. 4SCCh. 12 - Prob. 1ECh. 12 - Prob. 2ECh. 12 - Prob. 3ECh. 12 - Prob. 4ECh. 12 - Prob. 5ECh. 12 - Prob. 6ECh. 12 - Prob. 7ECh. 12 - Prob. 8ECh. 12 - Prob. 9ECh. 12 - Prob. 10ECh. 12 - Why does sweating cool the human body?Ch. 12 - Prob. 12ECh. 12 - Prob. 13ECh. 12 - Prob. 14ECh. 12 - Explain the hydrologic cycle.Ch. 12 - Prob. 16ECh. 12 - Prob. 17ECh. 12 - How does a water softener work?Ch. 12 - Prob. 19ECh. 12 - Prob. 20ECh. 12 - Prob. 21ECh. 12 - What is the SDWA?Ch. 12 - Prob. 23ECh. 12 - Prob. 24ECh. 12 - Prob. 25ECh. 12 - Explain the concerns that groups like the EWG or...Ch. 12 - Prob. 27ECh. 12 - Prob. 28ECh. 12 - Which compound would you expect to have the...Ch. 12 - Which compound would you expect to have the...Ch. 12 - Prob. 31ECh. 12 - Prob. 32ECh. 12 - Classify each molecule as polar or nonpolar:...Ch. 12 - Classify each molecule as polar or nonpolar:...Ch. 12 - Prob. 35ECh. 12 - Prob. 36ECh. 12 - Prob. 37ECh. 12 - Prob. 38ECh. 12 - How many grams of sucrose (C12H22O11) are present...Ch. 12 - How many grams of glucose (C6H12O6) are present in...Ch. 12 - Prob. 41ECh. 12 - How many grams of NaF are present in 4.5 L of a...Ch. 12 - A 250-g sample of hard water contains...Ch. 12 - Prob. 44ECh. 12 - Prob. 45ECh. 12 - Prob. 46ECh. 12 - Prob. 47ECh. 12 - Prob. 48ECh. 12 - Prob. 49ECh. 12 - Prob. 50ECh. 12 - Prob. 51ECh. 12 - Prob. 52ECh. 12 - Prob. 53ECh. 12 - Prob. 54ECh. 12 - Prob. 55ECh. 12 - Prob. 56ECh. 12 - Prob. 57ECh. 12 - Prob. 58E
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Solutions: Crash Course Chemistry #27; Author: Crash Course;https://www.youtube.com/watch?v=9h2f1Bjr0p4;License: Standard YouTube License, CC-BY