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Interpretation:
The contaminants that pose immediate health risks and the contaminants that can be eliminated by boiling are to be stated.
Concept Introduction:
Water is a common liquid that is present on the Earth.
It is also known as universal solvent. It can dissolve a wide range of organic and inorganic solutes.
Water is vital for the existence of all living animals. Without water, no life form can exist, it constitutes an important part of rivers, lakes, streams, clouds, snow and ice.
Water is truly an unusual molecule such that being a low molar mass compound, it exists as a liquid at room temperature and has an anonymously high boiling point.
Ice floats on water because it has a lower density than water.
Water contains some unwanted particles which can lead to diseases and other hostile effects on human health.
Numerous types of micro-organisms such as bacteria are present in water, which contaminate the water.
Biological contaminants: Some microbes can live in water and can cause various diseases like cholera, dysentery, and so on. Two examples of such microbes are Giardia and Legionella.
Inorganic contaminants: Some inorganic molecules can dissolve in water and make it impotable (not suited for drinking). Two examples of such molecules are Nitrates and Asbestos.
Organic contaminants: Some organic molecules can dissolve in water and makes it impotable (not suited for drinking). Two examples of such molecules are chlorohydrocarbons (volatile) and ethylbenzene (non-volatile).
Radioactive contaminants: Some radioactive elements can dissolve in water and make it impotable (not suited for drinking). Two examples of such elements are Uranium and Radium.
Contaminants that pose immediate health risks are the biological contaminants and inorganic contaminants because they get immediately dissolved in blood and starts reacting with it.
Contaminants that can be eliminated by boiling are the biological contaminants because the microbes can be killed by increasing the temperature.
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Chapter 12 Solutions
Chemistry In Focus
- 3. Draw the expanded structural formula, the condensed structural formula, and the skeletal structural formula for 2-pentene. expanded structure: Condensed structure: Skeletal formula: 4. Draw the expanded structural formula, the condensed structural formula, and the skeletal structural formula for 2-methyl-3-heptene. expanded structure: Condensed structure: Skeletal formula: following structurearrow_forwardPart IV. Propose a plausible Structure w/ the following descriptions: a) A 5-carbon hydrocarbon w/ a single peak in its proton decoupled the DEPT-135 Spectrum shows a negative peak C-NMR spectrum where b) what cyclohexane dione isomer gives the largest no. Of 13C NMR signals? c) C5H120 (5-carbon alcohol) w/ most deshielded carbon absent in any of its DEPT Spectivaarrow_forward13C NMR is good for: a) determining the molecular weight of the compound b) identifying certain functional groups. c) determining the carbon skeleton, for example methyl vs ethyl vs propyl groups d) determining how many different kinds of carbon are in the moleculearrow_forward
- 6 D 2. (1 pt) Limonene can be isolated by performing steam distillation of orange peel. Could you have performed this experiment using hexane instead of water? Explain. 3. (2 pts) Using GCMS results, analyze and discuss the purity of the Limonene obtained from the steam distillation of orange peel.arrow_forwardPart III. Arrange the following carbons (in blue) in order of increasing chemical shift. HO B NH 2 A CIarrow_forward6. Choose the compound that will produce the spectrum below and assign the signals as carbonyl, aryl, or alkyl. 100 ō (ppm) 50 0 7. 200 150 Assign all of the protons on the spectrum below. 8. A B 4 E C 3 ō (ppm) 2 1 0 Choose the compound that will produce the spectrum below and assign the signals to the corresponding protons. OH 6 OH 3 2 1 0 4 ō (ppm)arrow_forward
- In the Thermo Fisher application note about wine analysis (Lesson 3), the following chromatogram was collected of nine components of wine. If peak 3 has a retention time of 3.15 minutes and a peak width of 0.070 minutes, and peak 4 has a retention time of 3.24 minutes and a peak width of 0.075 minutes, what is the resolution factor between the two peaks? [Hint: it will help to review Lesson 2 for this question.] MAU 300 200 T 34 5 100- 1 2 CO 6 7 8 9 0 2.4 2.6 2.8 3.0 3.2 3.4 3.6 3.8 4.0 4.2 4.4 4.6 4.8 5.0 5.2 Minutes 3.22 0.62 1.04 O 1.24arrow_forwardThe diagram shows two metals, A and B, which melt at 1000°C and 1400°C. State the weight percentage of the primary constituent (grains of C) that would be obtained by solidifying a 20% alloy of B. 1000°C a+L L+C 900°С 12 α a+C 45 1200 C L+y 140096 C+Y a+ß 800°C 700°C C+B 96 92 a+B 0 10 20 30 40 50 60 70 80 90 100 A % peso B Barrow_forward8. Choose the compound that will produce the spectrum below and assign the signals to the corresponding protons. 2 4 3 ō (ppm) OH 4 6 6 СОН 2 1 0arrow_forward
- 7. Assign all of the protons on the spectrum below. A B 2 C E 2 1 3 6 4 3 2 1 0arrow_forwarde. If (3R,4R)-3,4-dichloro-2,5-dimethylhexane and (3R,4S)-3,4-dichloro-2,5-dimethylhexane are in a solution at the same concentration, would this solution be expected to rotate plane polarized light (that is, be optically active)? Please provide your reasoning for your answer. [If you read this problem carefully, you will not need to draw out the structures to arrive at your answer...]arrow_forward1. How many neighbors does the proton that produces the multiplet below have? 2. 3. اللـ Draw a partial structure from the multiplet below. (The integration of the multiplet is 6) M Using the additivity constants found in appendix G of your lab manual, calculate the approximate chemical shifts of the protons indicated below. (Show your work!!!) B A Br SHarrow_forward
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