Chapter 11.5, Problem 3AR

To determine

To Find: The value of each expression using the given values of variables.

Answer to Problem 3AR

  $32\pi$

Explanation of Solution

Given:

  $\frac{1}{3}\pi r^{2}hwhenr=2\sqrt{6},h=4$

Given: $r=2\sqrt{6},h=4$

i.e.

  $\begin{array}{l}=\frac{1}{3}\pi r^{2}hwhenr=2\sqrt{6},h=4\\ $ =\frac{1}{3}\pi {(2\sqrt{6})}^2(4)$=\frac{1}{3}\pi (24)(4)\\ =32\pi \end{array}$