Chapter 11.2, Problem 23WE

To determine

To Find: The area to the nearest tenth using the trigonometric table or calculator.

Answer to Problem 23WE

  $A\approx 73.5sq.unit$

Explanation of Solution

Given:

  

  

Draw the perpendicular

Then

Using trigonometric ratios

  $\begin{array}{l}\sin 50=\frac{h}{8}\\ h=6.128\end{array}$

Now

  $\begin{array}{l}b=12\\ h=AE=6.128\end{array}$

Area of parallelogram

  $\begin{array}{l}A=bh\\ A=(12)(6.128)\\ A=73.54\\ A\approx 73.5sq.unit\end{array}$

Hence, $A\approx 73.5sq.unit$