Chapter 11.3, Problem 3CE

To determine

To Find: The area of the trapezoid and length of the median.

Answer to Problem 3CE

  $A=138sq.unit$

  $M=11.5$

Explanation of Solution

Given:

  

Area of Trapezoid.

  $A=\frac{1}{2}h(b_1+b_2)$

Here

  $\begin{array}{l}{b}_1=14\\ b_2=9\\ h=12\end{array}$

Thus

  $\begin{array}{l}A=\frac{1}{2}h(b_1+b_2)\\ A=\frac{12}{2}(14+9)\\ A=\frac{276}{2}\\ A=138sq.unit\end{array}$

Now

Median of the trapezoid.

  $\begin{array}{l}M=\frac{1}{2}(b_1+b_2)\\ M=\frac{1}{2}(14+9)\\ M=\frac{23}{2}\\ M=11.5\end{array}$

Hence, area of the trapezoid is $A=138sq.unit$ and median is $M=11.5$.