Chapter 11.1, Problem 31WE

To determine

To Find: The dimensions.

Answer to Problem 31WE

  $28\times 14cm$

Explanation of Solution

Given: A rectangle having area $392m^2$ is twice as long as its width.

Given: Area= $392m^2$

Length is twice as its width

i.e.

  $l=2b$

The area of rectangle

  $\begin{array}{l}A=lb\\ 392=(2b)(b)\\ 2b^2=392\\ b^2=196\\ b=\sqrt{196}\\ b=14cm\\ then\\ l=2b\\ l=2(14)\\ l=28cm\end{array}$

Thus

  $l=28cm,b=14cm$

Hence, the dimensions are $28\times 14cm$