Chapter 11.2, Problem 2CE

To determine

To Find: The area of $\Delta ABC,\Delta DBC,\Delta EBC$

Answer to Problem 2CE

  $A=18sq.unit$

Explanation of Solution

Given:

  

Here

  $\begin{array}{l}Base=9\\ height=4\end{array}$

Area of triangles $\Delta ABC,\Delta DBC,\Delta EBC$ are equal because the base and height are same for all three triangles.

Thus

Area of triangle

  $\begin{array}{l}A=\frac{1}{2}bh\\ A=\frac{1}{2}(9)(4)\\ A=18sq.unit\end{array}$

Hence,

  $A=18sq.unit$