Chapter 11, Problem 8CR

To determine

To Find: The area of isosceles trapezoid.

Answer to Problem 8CR

  $24sq.units$

Explanation of Solution

Given: $legs=5,base=4and12$

Given: $legs=5,base=4and12$

  

Area of isosceles trapezoid.

  $\begin{array}{l}s=\frac{a+b+2c}{2}=\frac{4+12+10}{2}=13\\ A=\sqrt{(s-a)(s-b){(s-c)}^2}\\ A=\sqrt{(13-4)(13-12){(13-5)}^2}\\ A=\sqrt{9\times 64}\\ A=24sq.units\end{array}$